I think I have made a mistake on trigonometric calculation. In the horizontal distance, instead of (5.04)*(1/tan(180-112)) = 2.0524, I have used 5.478 (=sqrt(5.04*5.04 + 2.0524*2.0524)) . Sorry for using hypotenuse length of right triangle.
@@mahmudhasanmaraj I'm not sure if Solidworks does it because I use Inventor and you don't need to do that calculation the software will calculate that line's length automatically if you draw the entire sketch and set the relations correctly and the result is 64.633mm.
thank u
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why we added the 5.478 ?
I think I have made a mistake on trigonometric calculation. In the horizontal distance, instead of (5.04)*(1/tan(180-112)) = 2.0524, I have used 5.478 (=sqrt(5.04*5.04 + 2.0524*2.0524)) . Sorry for using hypotenuse length of right triangle.
@@mahmudhasanmaraj I'm not sure if Solidworks does it because I use Inventor and you don't need to do that calculation the software will calculate that line's length automatically if you draw the entire sketch and set the relations correctly and the result is 64.633mm.
@@TeddyKrimsony I used Freecad and I didnt have to use any formula either
i don't understand that how to get 5.04?