The best of the best!!! This video is simple yet knowledgeable; and the teacher gives you some valuable information that most other teachers neglected to mention.
In common-base configuration, the base is common to the input and output circuits. The collector current is approximately equal to the emitter current, with a small base current. Key moments: 00:05 Transistors have three configurations: common base, common emitter, and common collector. Common emitter configuration is widely used due to its advantages in amplifying weak signals in active mode. -Explanation of common base configuration. Base is common to input and output circuits, facilitating signal amplification in active mode. -Operation in active mode. Transistor has two junctions: Junction j1 forward biased (diode EB) and Junction j2 reverse biased (diode BC) for signal amplification. -Comparison with diodes. Transistors are two-port devices with input (ie, V B II) and output (IC, V CE B) characteristics, unlike single-port diodes. 05:10 Understanding the proper nomenclature in transistor circuits is crucial for accurate representation. Kirchoff's current law helps derive key equations for active mode operation and current gain, essential for analyzing transistor behavior. -Importance of following proper nomenclature in transistor circuits for accurate representation of voltage and current. -Deriving key equations using Kirchoff's current law for active mode operation and understanding current gain in transistor circuits. -Explaining the significance of alpha as the common base current gain and its implications on emitter and collector currents.
Thank you for uploading videos with such clear explanations. It's a kind request to you sir that please upload practicals on electronics like digital gates using IC's.
Thank u, twas really conceptual and eliminating out confusions. I liked the way, you drew Vcb and Vbe later in the circuit and gave understanding of its terminals. Most of the lectures i found previously, they seemed to mug up the circuit diagram without and explanations and then explain just the results, that too in a confusing way.
in vk mehta book, nomenclature of Vbe is opposite , it confused me and i opened this lecture to clear my confusion , my confusion is now totally clear ! Thank you so much Sir ! greetings from Bangladesh
This video are really helpful for me . I watching this video from Bangladesh . And I am the student of Gazipur Technical school and college, and my trade is Electrical works and maintenance.
Sir. We r fortunate to have ur lectures seriously... Thanks a lot. Sir y emitter should be highly doped as well as base is lightly.? What's d reason behind it. Plz tell me sir.
Base is lightly doped so that there is less recombination in it and more charge carriers are able to pass to the collector region. The emitter is highly doped to get large number of charge carriers in forward bias.
@@raghuyuva start from scratch. Everything is available on the TH-cam. And there is pretty sufficient time to prepare for it. Watch the videos,make schedule and you will be good to go.
sir,wonderful lecture of ur's helped me in solving many doubts of transistor and pls..... upload working of low passand high pass filters also.......... thankyou for ur lecture
I cbo means the reverse saturation current in common base configuration when the emitter terminal is open ( battery across emitter is disconnected). I ceo means the reverse saturation current in common emitter configuration when the base terminal is open ( battery across base is disconnected). Both I cbo and I ceo are very small so they can be interchanged. Because later we have to ignore thier value anyway.
at 1:43 instance in video you said we apply weak signal in input and get a amplified signal at output.......in common base current gain does not exceed 1 .....so how this is possible...
Your videos really very clear,. Thanks for your this videos., These are very helpful me for Ugc Net Exam.. But ,I have one doubt...mentioned as below.. Please , Explain Why in CB configuration, VCB plot gone to -ve side of axis..,? Thank you
as Vcb is increasing it means reverse bias is increasing so the width of the depletion increases and that implies the base region narrowing and now less voltage is required to keep EB in F.B and due to this curve shifts in -x axis or left side of the graph
For,EB diode,one can neglect RE,since EB diode is in forward bias & any diode in forward-bias-condition has very low resistance.So,from that point of view,we can say,VBE=VEE. But,how can we say VCB=VCC because in that case,RC can't be neglected since the resistance in reverse-bias condition is very high.
First of all thank you so much sir for sharing knowledge with us. My doubt is why in the O/P characteristics of CE every curve ends at origin and why not in CB(it ends in 2nd quad in case of CB). THANK YOU
explain by "device physics"(like Ben J streetman does) how base current controls collector current to provide current amplification in the first place.CE,CB,CC comes after that
at 9:15 you said Ib=(1-alpha)Ie ....so when we put dis value in Ie=Ic + Ib where Ic = (alpha)Ie + Ico....den it reduces to Ico =0 which is not possible
Sir in active mode at J2, due to reverse biasing holes will move to p and electrons to n,as they are minority charge carriers,so the direction of current should be from n to p and hence this should be the equation Ic=a×Ie-Icbo. Clear my doubt sir please..
thanku sir for sharing. My question is sir, E is input terminal and C is output terminal while the input terminal current is coming out and output current is going inside. Make it clear sir, Thanking you.
Dear sir all your lectures are very good. I am also a lecturer and wishing to make video lectures. Will you please tell me on which platform you created your lectures.
The best of the best!!! This video is simple yet knowledgeable; and the teacher gives you some valuable information that most other teachers neglected to mention.
In common-base configuration, the base is common to the input and output circuits. The collector current is approximately equal to the emitter current, with a small base current.
Key moments:
00:05 Transistors have three configurations: common base, common emitter, and common collector. Common emitter configuration is widely used due to its advantages in amplifying weak signals in active mode.
-Explanation of common base configuration. Base is common to input and output circuits, facilitating signal amplification in active mode.
-Operation in active mode. Transistor has two junctions: Junction j1 forward biased (diode EB) and Junction j2 reverse biased (diode BC) for signal amplification.
-Comparison with diodes. Transistors are two-port devices with input (ie, V B II) and output (IC, V CE B) characteristics, unlike single-port diodes.
05:10 Understanding the proper nomenclature in transistor circuits is crucial for accurate representation. Kirchoff's current law helps derive key equations for active mode operation and current gain, essential for analyzing transistor behavior.
-Importance of following proper nomenclature in transistor circuits for accurate representation of voltage and current.
-Deriving key equations using Kirchoff's current law for active mode operation and understanding current gain in transistor circuits.
-Explaining the significance of alpha as the common base current gain and its implications on emitter and collector currents.
Passing my ECCF exams only because of you, sir! Thanks a lot :)
Excellent lecture! Thank you sir for the conceptual clarity😄
Thank you for uploading videos with such clear explanations. It's a kind request to you sir that please upload practicals on electronics like digital gates using IC's.
tq sir!very well explained,ill have my exam on basic electronic,staying up to watch ur videos and understand all the concept, T.T
These videos are excellent and very well made. Kudos to the creators!
𝗛𝗵𝗼
The way of explanation is harts of sir...
Keep doing this best explanations
Thanks a lot sir
Thank u, twas really conceptual and eliminating out confusions. I liked the way, you drew Vcb and Vbe later in the circuit and gave understanding of its terminals. Most of the lectures i found previously, they seemed to mug up the circuit diagram without and explanations and then explain just the results, that too in a confusing way.
in vk mehta book, nomenclature of Vbe is opposite , it confused me and i opened this lecture to clear my confusion , my confusion is now totally clear ! Thank you so much Sir ! greetings from Bangladesh
It is still so much useful after 8 years.... Thank you❤
thank you soo much sir, best for one-night batting students, just like me.
anyone like that. please like.
Haha
Exactly
This video are really helpful for me . I watching this video from Bangladesh . And I am the student of Gazipur Technical school and college, and my trade is Electrical works and maintenance.
Kemon asen
Well explained sir................ ✨✨✨✨
Thank u☺️✌️
This is an seriously helpful vid i have seen ,all the confusions has been cleared out now.thankyou for the videos.
very well explained just awesome thanku sir for this simple explanation.
Best lect on this topic available online..thanks a lot sir
nice sir........i m happy becoz you created playlist for each subject........so continue sir it very helpful
the best academy is neso. thanks sir.
Thanks!
We already know, we already know. Sweetest thing I will hear this week.
Most underrated youtube channel ❤️
good job Neso academy from Ethiopia
Arre great sir 😘
I become huge fan of your teaching😍😍🤗
Keep helping us tqsm...
Sir. We r fortunate to have ur lectures seriously... Thanks a lot. Sir y emitter should be highly doped as well as base is lightly.? What's d reason behind it. Plz tell me sir.
Base is lightly doped so that there is less recombination in it and more charge carriers are able to pass to the collector region.
The emitter is highly doped to get large number of charge carriers in forward bias.
tq sir
@@313Ritesh sir I don't know anything about subject then how should I pass backlogs
@@raghuyuva start from scratch. Everything is available on the TH-cam. And there is pretty sufficient time to prepare for it. Watch the videos,make schedule and you will be good to go.
Emitter is heavily doped as it's job is to produce much number of electrons
God gifted lecturer to students.❤
how beautifully u explained sir......really awesome
big thank you to you sir
Thanku sir respect from Pakistan
Superbb lecture...😘😘😘😘😘keep going...
you are the best at explaining sir
Thanks for making our engineering life easy. May our creator bless you.
thank you sir...best lecture ever.....
boss in electronics......love you my master
Tq soo much.. really understood in one attempt..thanks for the valuable information
deep thanks and big appreciation to you;sir
realy nice video and beautiful handwriting
I wish my professor was clear cut like you professor. Hats off.
sir,wonderful lecture of ur's helped me in solving many doubts of transistor and pls..... upload working of low passand high pass filters also.......... thankyou for ur lecture
Very motivating , helpful and life saver videos...well explained everything...👍🙏👏
Thank you very much sir!! You helped me a lot🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
Very understandable 👏🏼
Nice explanation 👍
I cbo means the reverse saturation current in common base configuration when the emitter terminal is open ( battery across emitter is disconnected).
I ceo means the reverse saturation current in common emitter configuration when the base terminal is open ( battery across base is disconnected).
Both I cbo and I ceo are very small so they can be interchanged. Because later we have to ignore thier value anyway.
Always u help a lot sir😁😁
Sema sir... Tanq 4 te lecture... 🙏
Really great work bro...helped a lot conceptually
at 1:43 instance in video you said we apply weak signal in input and get a amplified signal at output.......in common base current gain does not exceed 1 .....so how this is possible...
Shubham Dhama u will gain voltage amplification..
How did we get base current as (1-alpha)of emitter current given at the ending of presentation
When the base is grounded current should be zero ?
Thanks for the exolanation sir 🙏🙏
Very well explained. Thank you!
Your videos really very clear,.
Thanks for your this videos.,
These are very helpful me for Ugc Net Exam..
But ,I have one doubt...mentioned as below..
Please , Explain Why in CB configuration, VCB plot gone to -ve side of axis..,?
Thank you
as Vcb is increasing it means reverse bias is increasing so the width of the depletion increases and that implies the base region narrowing and now less voltage is required to keep EB in F.B and due to this curve shifts in -x axis or left side of the graph
I do not understand the reverse saturation current, Icbo and Ico. @_@
Thank you for these lectures... Very helpfull..
V EB IS CORRECT BECAUSE POTENTIAL OF E IS MORE THAN B REST ALL IS GOOD
Thank you Sir for the Lectures.Really helpful.
Thank you sir ❤️
semester saver videos... thankyou sir..
For,EB diode,one can neglect RE,since EB diode is in forward bias & any diode in forward-bias-condition has very low resistance.So,from that point of view,we can say,VBE=VEE.
But,how can we say VCB=VCC because in that case,RC can't be neglected since the resistance in reverse-bias condition is very high.
First of all thank you so much sir for sharing knowledge with us.
My doubt is why in the O/P characteristics of CE every curve ends at origin and why not in CB(it ends in 2nd quad in case of CB).
THANK YOU
any indians here? SIR?
Yes
Yes I am
Who cares dude
Can anyone please tell me why we are using "Ground " in this cercit?
Yes?
love u sir please make as much video as you can
Great videos. You are a life saver.
Super. I thought may be u will go to the inside of electrons that flowing. That much details.
Oops damn lecture , excellent sir 😍😍😍😍😘😘😘😘😘😘😘😘😘😘😎
Sir plz Upload Notes for these lectures would be really helpful
What are the significance(meaning) of the resistances Re and Rc ?
If they r externally provided or internal properties of bjt?
Please tell in detail.
GYAN PRAKASH Internally due to barrier potential.
what happens after electron-holes recombine in base region?
I mean do they again split to form I-b
Thnks a lot sir u made it easy
explain by "device physics"(like Ben J streetman does) how base current controls collector current to provide current amplification in the first place.CE,CB,CC comes after that
Thanks a lot from my hard❤️❤️
thanku sir it was very helpful
Which is greater Ic or Ib ?
Ic is greater
Why eb in forward bias?
Thanks sir 🙏☺️
thank you sir for the good work
Why is J2 reverse biased in active region? And how do we know whether it needs to reverse biased or not?
As it is in active mode j1 act as FB and j2 act as RB
it was really helpful tq sir
Very clear explanation sir.
Thanks a lot😊
Can I ask which program you use to draw
Sir why is alpha (gain) multiplied with IE ??To find IC I know but how?
at 9:15 you said Ib=(1-alpha)Ie ....so when we put dis value in Ie=Ic + Ib where Ic = (alpha)Ie + Ico....den it reduces to Ico =0 which is not possible
plzz correct me where I m wrong and explain me
Sir, could it possible tht Vbe>Vee if we apply kvl in first loop thn
Vee - Vbe + IeRe=0 and if we increase Ie thn Vbe>Vee
I was asking te same question
Actually, Ie is due to Vee only. So Vee is the source. you cannot increase Ie without increasing Vee
Sir in active mode at J2, due to reverse biasing holes will move to p and electrons to n,as they are minority charge carriers,so the direction of current should be from n to p and hence this should be the equation Ic=a×Ie-Icbo.
Clear my doubt sir please..
Thanks sir u r the best
thnxxx,, a lot its very help full
Can somebody please tell me why the terminal that attached to C was +ve even tho it is n type?
because to operate transistor iin active mode, we have to connect o/p to reverse biased. that is done by connecting C to reverse biased voltage.
Sir can you please also add lecture on voltage divider rule of transistor
A lot of thank you ....................................sir
in above explained configuration ...(NPN) IE is taken as input current...but its leaving current from BJT....??
pls explain
we owe your or lives
Thanks Sir
SEMA Anna....
thanku sir for sharing. My question is sir, E is input terminal and C is output terminal while the input terminal current is coming out and output current is going inside. Make it clear sir, Thanking you.
Dear sir all your lectures are very good. I am also a lecturer and wishing to make video lectures. Will you please tell me on which platform you created your lectures.
It will b more useful if u use more bright markers... So that it would b more visible
Ur classes are very useful.... Thank u very much
Thank you for the feedback.
@@nesoacademy u r most welcome
Best tutorial
Agar emitter base junction reverse bias hai to potential barrier greater hoga then how majority charge carriers pass this potential barrier???
Sir if Vcb also contains barrier potential??
very important this videos thanx
why we ground the node in the cb transistor circuit, please answer?
Sir I think there's one correction - proper nomenclature shld be V EB according to ur battery connection.. Pls check once
If I use pnp transistor, the voltage symbols will become VEB and VBC instead of VBE, VCB in npn?