Common-Emitter Transistor (Input Characteristics)

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  • เผยแพร่เมื่อ 23 ธ.ค. 2024

ความคิดเห็น •

  • @SauravKumar-yo8hb
    @SauravKumar-yo8hb 3 ปีที่แล้ว +5

    Thanks

  • @bhargav1811
    @bhargav1811 3 ปีที่แล้ว +22

    When w effective decreases means concentration gradient increases and base current should increase which u told in common base then why that logic is not applied here??

    • @nabindhami364
      @nabindhami364 3 ปีที่แล้ว

      Exactly my question too

    • @goutamsutradhar9566
      @goutamsutradhar9566 3 ปีที่แล้ว +5

      Because in common base configuration the electrons movement increased towards base thus increasing the current in IE(opposite). Similarly in the common emitter configuration decrease in the w effective Increases the electrons in base thus increasing IE current And further decreasing IB current. Here as only IB is needed for the graph ,IE is not mentioned. I think this is how it works.

    • @aadii1706
      @aadii1706 2 ปีที่แล้ว

      @@goutamsutradhar9566 combination decreases then collector current increases hence base current should decrease...
      In common base , collector current increases therefore emitter current also increases as Ie=Ib+Ic

    • @luckytech9064
      @luckytech9064 2 ปีที่แล้ว

      @@aadii1706 kya bhai polytechnic lecturer me hua h kya

    • @aadii1706
      @aadii1706 2 ปีที่แล้ว +1

      @@luckytech9064 ??

  • @tejashreerasam9831
    @tejashreerasam9831 3 ปีที่แล้ว +6

    Nice explained sir .
    I understand difficult concepts very easily.
    Thank you sir 😊😊😊
    🙏🙏🙏

  • @AnoNymous-po5sx
    @AnoNymous-po5sx 4 ปีที่แล้ว +3

    8:28 gave me a relief. My head started pounding when you wrote milli amps instead of micro amps lol

  • @linhnguyenduy1904
    @linhnguyenduy1904 5 ปีที่แล้ว +7

    Thank you sir, you've helped me alot in EC.

  • @kirtxn_
    @kirtxn_ ปีที่แล้ว +4

    On decreasing width of effective recombination , iB decreases but iE increases

  • @santudhali3
    @santudhali3 7 ปีที่แล้ว +8

    nice sir!!!
    u told us the basic caused of everything!!!
    thank you sir...

  • @raviyadav2552
    @raviyadav2552 5 ปีที่แล้ว +2

    Awesome explanation sir . i understand everything

  • @dikukhanikar2837
    @dikukhanikar2837 4 ปีที่แล้ว +9

    Can you explain how emitter current increases in CB configuration but the Base current decreases in CE configuration for the decrease in effective width of base region.?

    • @simplemathematics7792
      @simplemathematics7792 3 ปีที่แล้ว +5

      In CB configuration also Ib decrease since weff decreases implies recombination decreases ,but in graph we plot the Ie not Ib there ,here we are plotting Ib same concept there and here nothing changed.

  • @nageswarrao2848
    @nageswarrao2848 4 ปีที่แล้ว +4

    Sir if recombination decreases input current should increase sir.as u told in common base configuration.But how decreases

    • @obamaengineer4806
      @obamaengineer4806 3 ปีที่แล้ว

      Exactly my doubt too😢😢😢

    • @aadii1706
      @aadii1706 2 ปีที่แล้ว

      Emitter current increases therefore base current decreases and here base current is input current..

  • @rehanahmad6236
    @rehanahmad6236 6 ปีที่แล้ว +8

    Thank u Sir.
    Q: What will be the effect on the breakdown voltage across CB on fixing the values of Vce at two different values?

  • @shaikriyaz7519
    @shaikriyaz7519 5 ปีที่แล้ว +3

    At the end of the video,to draw the input characteristics, Vce should be increased or decreased??

  • @KINGคภ
    @KINGคภ ปีที่แล้ว +1

    If we consider PNP transistor the input characteristics is drawn between Veb vs Vec??????

  • @mervindcosta8192
    @mervindcosta8192 5 ปีที่แล้ว +1

    Really great explanation with the ease of the viewer to go back and rewind. Keep up the good work and keep on inspiring.

  • @apostolidispeter2499
    @apostolidispeter2499 7 ปีที่แล้ว +2

    These videos are really helpfull, thanks for the hard work

  • @anujgupta9542
    @anujgupta9542 6 ปีที่แล้ว +1

    Sir, why are we applying Vcb in common emitter configuration?

  • @imqwerty5171
    @imqwerty5171 6 ปีที่แล้ว +2

    How did you reverse biase the collector-emitter junction? They're both n.

    • @johnsonshougaijam8127
      @johnsonshougaijam8127 2 ปีที่แล้ว

      Follow the books as well they all wrote the same what he tought here

  • @ananyasaxena948
    @ananyasaxena948 6 ปีที่แล้ว

    Really nice....Ws confused a lot regarding thèse characterstics...bt now i got the basics...👍👍

  • @mehdi7136
    @mehdi7136 2 ปีที่แล้ว

    very great explanation I have been looking for such training about this concept for a long time thanks a lot 🙏🙏🙏

  • @Amitsingh8005i
    @Amitsingh8005i 2 ปีที่แล้ว

    Sir at 3:39 current should be in microampere ???

  • @VishalKumar-rf4kq
    @VishalKumar-rf4kq หลายเดือนก่อน +1

    Love from Haryana ❤❤

  • @achintize
    @achintize 5 ปีที่แล้ว +1

    Hi..0:50 you said Ic is output current...is this right?

  • @vimalkumarchaudhary1384
    @vimalkumarchaudhary1384 7 ปีที่แล้ว +16

    in common emmiter the early effect case is different than common base please explain sir

    • @abdelmoumenederoueche369
      @abdelmoumenederoueche369 6 ปีที่แล้ว +3

      It is the same. For common base we were talking about I(E) which increases with increasing Vcb . Here we are talking about I(b) which decreases

    • @zeyadahmed731
      @zeyadahmed731 5 ปีที่แล้ว

      @@abdelmoumenederoueche369 I can understand why I(b) decreases with increase in Vcb.
      But I didn't understand why I(E) increases with increase in Vcb.
      I can't understand how I(E) depends on Vcb.

    • @abdelmoumenederoueche369
      @abdelmoumenederoueche369 5 ปีที่แล้ว

      @@zeyadahmed731 try to watch from 4:30 again. Because we increase Vcb the width of depletion layer increases between C and B which mean the base region will be smaller it will have a width ( weff) less than what was before. Thus, less combinations will occur in it, so I(b) will decrease

    • @zeyadahmed731
      @zeyadahmed731 5 ปีที่แล้ว +3

      @@abdelmoumenederoueche369 thank you, but I said I understood the effect of Vcb on base current.
      My question is for a previous video, which is how the decrease of Weff due to increase of Vcb can increase the emitter current I(E).
      Thank you again 🙏

    • @abdelmoumenederoueche369
      @abdelmoumenederoueche369 5 ปีที่แล้ว +1

      @@zeyadahmed731 yes sorry for that. I recommend you watch this video. I had troubles understanding it last semester so don't worry x)
      th-cam.com/video/dA9KgXLVXOc/w-d-xo.html

  • @raunaksahu_IIT-BHU
    @raunaksahu_IIT-BHU ปีที่แล้ว +1

    Here input current (Ib) decreases with increase in Vcb whereas input current(Ie) increases [IN CB configuration] .... its because concepts are same in both just direction of input current in opposite?? Is that so?

    • @aryansahu8614
      @aryansahu8614 9 หลายเดือนก่อน

      same surname

  • @jrithwik7574
    @jrithwik7574 5 ปีที่แล้ว +1

    Sir why are we checking input characters only at diff. Output voltage and output characters only at diff. Input current

  • @bengeo7832
    @bengeo7832 ปีที่แล้ว +1

    Why is Vbb not equal to Vbe? What condition(s) could make them to be equal?

  • @bishwajeetkumar3441
    @bishwajeetkumar3441 6 ปีที่แล้ว +5

    In common base, effective width (reduction in width) cause emitter current to increase (due to conc. Gradient)
    But, In common emitter, why don't effective width ( reduction of width) cause increase in Ib ( input current) to increase

    • @mint7325
      @mint7325 6 ปีที่แล้ว

      Same q.. pls anyone explain us

    • @jayantsharma_
      @jayantsharma_ 6 ปีที่แล้ว +2

      I think emitter current is more significantly because of flow of electrons towards collector region. So by increasing reverse bias voltage, more electrons flow towards collector region and hence Ie is increased.
      But base current was produced because of electrons recombination with holes, decrease in recombination decreases base current. Which means increasing reverse bias Vcb (Vce in case of common emmitter) decreases Ib.

    • @mint7325
      @mint7325 6 ปีที่แล้ว

      @@jayantsharma_ passed the exam.. 😅 thanks tho 😊

    • @jayantsharma_
      @jayantsharma_ 6 ปีที่แล้ว

      @@mint7325 I hope I clear my exam tomorrow 😅

    • @mint7325
      @mint7325 6 ปีที่แล้ว

      @@jayantsharma_ May you get great marks, Ameen. Best wishes!

  • @venkateshanantapalli4343
    @venkateshanantapalli4343 7 ปีที่แล้ว +4

    Current is due to the flow of electrons(or holes) but not a result of recombination of holes and electrons. Since recombination rate decreasing how can we say that there is less base current? One more thing is if a number of recombinations are decreasing means there are more free electrons and holes which much constitute a high current. But the thing here is the number of electrons coming from base to the battery terminal is reducing due to recombination rate. So can anyone explain the relationship between the number of electrons coming out of the base and recombination rate?

    • @saptarshipal7393
      @saptarshipal7393 6 ปีที่แล้ว

      Because for n-p-n transistor the base current supplied the holes in base that were lost due to recombination (along with providing holes that move towards the emitter from base due to diffusion - since forward bias ). As recombination is less, the base current is also less.

    • @as72333
      @as72333 6 ปีที่แล้ว

      one of the reasons for this might be that the base is lightly doped and offers resistance to the flow of electrons so rather than contributing for base current they find it more easier to contribute to the collector current since the charge carriers that were majority have now become minority in the base collector region hence they contribute to collector current more.second point is that the area of the recombination decreases meaning electrons and holes are concentrated in less area than before and there is concentration gradient so they flow towards the emmiter to base and then towards collector .if you wish to find the relationship then alpha can help you as alpha is the range of .95 -.98 so majority cuurent from emmiter goes towards the collector and remaining .02-.05 is for recombination which is evident from the fact the base cuurent is in the orders of nano or micro amperes while collector and emitter currents are of micro amperes(for coomon base)

  • @ManishYadav-gx8ce
    @ManishYadav-gx8ce 6 ปีที่แล้ว +1

    at 3:28; IB should be micro amps instead of milli amps.

  • @arvindaru2250
    @arvindaru2250 6 ปีที่แล้ว +1

    Tq sir 😍😍😍

  • @shahzadnasir1052
    @shahzadnasir1052 8 ปีที่แล้ว +2

    why is input current ib in case of common emitter configuration and ie in case of common base configuration?

    • @udeepshrestha8179
      @udeepshrestha8179 7 ปีที่แล้ว +1

      General convention is
      prefer *Ib* as *input current* if base is *not common* otherwise choose *Ie* as *input current*
      prefer *Ic* as *output current* if collector is *not common* otherwise choose *Ie* as *output current*

    • @cesare4926
      @cesare4926 7 ปีที่แล้ว

      That is confusing. Is there a reason that this is the general convention ?

    • @vinayak5april
      @vinayak5april 7 ปีที่แล้ว +2

      Input current is the current which flows through the input resistor, so Ib is the input current in case of common emitter and Ie is the input current in case of common base

    • @shantanusaha6784
      @shantanusaha6784 6 ปีที่แล้ว +1

      Hi, let me throw some light in order to clear this confusion. For Common Emitter we have emitter terminal is grounded.
      i) If you closely observe the 1st diagram of this lecture, you can see that in input we are having only base and emitter terminal which are biased, so the input current is of course base current.
      ii) Similar logic can be applied for CB mode but here base is grounded so the input current is emitter current.

  • @kameelamareen
    @kameelamareen 7 ปีที่แล้ว

    Man you are the best !!!!!!!!!

  • @420bruce2
    @420bruce2 2 ปีที่แล้ว

    How base width modulation is done @ ce Configuration bcz no reverse bias in cb

    • @420bruce2
      @420bruce2 2 ปีที่แล้ว

      How vcb in ce configuration

  • @aryanpatel368
    @aryanpatel368 6 ปีที่แล้ว

    sir please clear about me that if biasing potential Vbb then why we write Veb(fb)and vccand vcb(rb) please explain

  • @neeharika3433
    @neeharika3433 2 ปีที่แล้ว +1

    How the eq Vce =Vbe+Vcb comes?

  • @UECDishaKhattri
    @UECDishaKhattri 5 ปีที่แล้ว +1

    Amazing got what needed 😘😘😘

  • @afsanaahmed8742
    @afsanaahmed8742 7 ปีที่แล้ว

    Why Micro Ameter is connecting in the input of CE configuration?

  • @sreekumar7177
    @sreekumar7177 4 ปีที่แล้ว

    How we get values of VBE for graph?

  • @amitweb19
    @amitweb19 8 ปีที่แล้ว +20

    Sir, In your Digital Electronics playlist there are two videos which are 'PRIVATE' ( Video no. 98 & 205 )...
    Plz make them public... :)

  • @puneetkumarsingh2989
    @puneetkumarsingh2989 7 ปีที่แล้ว

    Why does on increasing V(CE), V(CB) also increases? Why does nothing happens to the V(BE)? I'm confused?

    • @muhammadnaufil5237
      @muhammadnaufil5237 6 ปีที่แล้ว +1

      VBE is the forward biased diode voltage which is more or less constant all the time which is 0.7 volts

  • @Hmi316
    @Hmi316 5 ปีที่แล้ว +1

    Sir, if on increasing Vce, due to Early effect, emitter current (Ie) increases then shouldn't the forward biasing at EB junction increase and hence, knee or cut-in voltage decrease on increasing Vce? Could you please clarify this ?

  • @UECAshutoshKumar
    @UECAshutoshKumar 2 ปีที่แล้ว +1

    Thank you sir ❤️

  • @kisaflwr
    @kisaflwr 6 ปีที่แล้ว

    Thank you so much!!😃

  • @mohamedosama597
    @mohamedosama597 5 ปีที่แล้ว +3

    Sir how the transister produce ac current in Tesla coil( 2n2222) pls replay sir.

    • @sabbavarapuchandrakala8513
      @sabbavarapuchandrakala8513 5 ปีที่แล้ว +1

      use the app (grammarly) for good english { then reply again } not transister =transistor and not replay = reply

  • @King58468
    @King58468 2 หลายเดือนก่อน

    4:27 early effect

  • @dishantdoshi2133
    @dishantdoshi2133 7 ปีที่แล้ว

    Thanks alot sir💙

  • @Lobiminyo
    @Lobiminyo 6 ปีที่แล้ว +1

    Pls put the series resistance and derive the Ic using kvl and kcl .... that's the part i don't get in class

  • @sidrakhalid9165
    @sidrakhalid9165 2 ปีที่แล้ว

    Thanx♥️

  • @shivangisharma8429
    @shivangisharma8429 3 หลายเดือนก่อน

    thanks sir

  • @himanshushekhardas1730
    @himanshushekhardas1730 6 ปีที่แล้ว

    Why penetration of depletion region is more in base region ?

    • @harshitgupta5053
      @harshitgupta5053 5 ปีที่แล้ว

      because base region is lightly doped hence penetration is more in base region and less recombination will be taking place resulting in lesser base current

  • @ashubabbar3322
    @ashubabbar3322 6 ปีที่แล้ว

    *Base is at lower potential and collector at higher potential* how?
    4:50

    • @amancasula9408
      @amancasula9408 6 ปีที่แล้ว

      Ashu Babbar it is in reverse bias.
      In which P(base) is connected to lower(negative) potential and N(collector) is connected to higher(possitive) potential.

  • @culturechannel4613
    @culturechannel4613 5 ปีที่แล้ว +2

    Usually Base Emitter Current is in microamperes!

    • @yashaditya2107
      @yashaditya2107 3 ปีที่แล้ว

      he has made that correctioin in the end

  • @deependerchauhan-rg5jx
    @deependerchauhan-rg5jx 2 ปีที่แล้ว

    sir why Vbe is not equal to Vbb

  • @praveenchakravarthy1513
    @praveenchakravarthy1513 6 ปีที่แล้ว +2

    Since base is small, a small amount of current is required to break the barrier. So base current should be in micro amperes, not milli...Sir, please change it!!

  • @syedbahr4744
    @syedbahr4744 6 ปีที่แล้ว

    You said ic is output current but here it is entering to collector????

  • @hari8568
    @hari8568 6 ปีที่แล้ว

    How do we know that vce decreases when we go left of the input graph

  • @uzairali6875
    @uzairali6875 7 ปีที่แล้ว +1

    what is difference b/w vbb,vbe and vcc,vce plz answer neso academy i,m cofused

    • @sayansantra955
      @sayansantra955 4 ปีที่แล้ว

      vbb and vcc is more of a voltage source and vbe and vce is potential difference across base-emitter and collector-emitter respectively

    • @TomThomasVempala
      @TomThomasVempala 3 ปีที่แล้ว

      @@sayansantra955 isnt it always 0.7 V ?

  • @iiestphysics
    @iiestphysics 3 ปีที่แล้ว

    Vcc is used to reverse bais the collector emmiter junction

  • @ricnjiiri
    @ricnjiiri 2 ปีที่แล้ว

    Great work. Only the translation text though well intended is hinding the writting of the derivations. If someone had a challenge in hearing, they might not follow your explanation

  • @swetashalini5739
    @swetashalini5739 5 ปีที่แล้ว

    how this equation come?Vce=Vcb+Vbe

  • @RamKubde
    @RamKubde หลายเดือนก่อน +12

    2024 anyone?

  • @reemakumari6454
    @reemakumari6454 6 ปีที่แล้ว

    The two diode connected back to back is "WRONG"..if we replace bjt with two diodes, we assume that there is no interaction between the two diodes expected they r far apart..however in a bjt, exactly the opposite is true for higher performance, The base region is made as short as possible and the two diodes cannot be treated as independent devices..

  • @creative0402
    @creative0402 2 ปีที่แล้ว

    Sir isme Vbb not equal to Vbe or Vcenkt equal to Vcc

  • @dipalichitroda8205
    @dipalichitroda8205 6 ปีที่แล้ว

    Please...
    Make a video on TRANSISTOR APPROXIMATIONs...

  • @boggarapuaravind4299
    @boggarapuaravind4299 5 ปีที่แล้ว

    Super sir

  • @tarishisrivastava192
    @tarishisrivastava192 8 ปีที่แล้ว +2

    Why is the base at lower potential?

  • @Zakaria_122
    @Zakaria_122 5 ปีที่แล้ว +2

    5:10 it sounds like a bubble XD

  • @souvikghata8297
    @souvikghata8297 6 ปีที่แล้ว

    In common base, effective width (reduction in width) cause emitter current to increase (due to conc. Gradient)
    But, In common emitter, why don't effective width ( reduction of width) cause increase in Ib ( input current) to increase??

  • @Vernacularpressact
    @Vernacularpressact ปีที่แล้ว

    why is vce = vcb + vbe

  • @Lucifer-1947
    @Lucifer-1947 5 ปีที่แล้ว

    Why V(BB) and V(CC) not used in common base transistor

    • @Vernacularpressact
      @Vernacularpressact ปีที่แล้ว

      theyre biasing potentials not input and output potentials

  • @s_madhan623
    @s_madhan623 4 ปีที่แล้ว

    Base current is in microampere.

  • @vineethambati1817
    @vineethambati1817 6 ปีที่แล้ว

    Sir explain configurations of pnp

  • @samuelatogyasiotabir9655
    @samuelatogyasiotabir9655 6 ปีที่แล้ว

    God Nesco Academy

  • @kandinaveen9333
    @kandinaveen9333 4 ปีที่แล้ว

    Super bro

  • @nikhilshahare6241
    @nikhilshahare6241 7 ปีที่แล้ว

    Sir the video is fabulous...
    But why the early effect has opposite result as that in common base... Why I(b) decrease here as the effect is same in both cases ?

    • @AdityaFingerstyle
      @AdityaFingerstyle 7 ปีที่แล้ว +8

      In common base, the input current is the EMITTER CURRENT (Ie).
      Since the effective depletion width decrease, very few electrons from the emitter diffuses in the base and majority of them travels to the collector. After reaching the collector, the electron flows back to the emitter.
      If the effective depletion width was wider, more electrons from the emitter would recombine and lesser electrons would circulate in the circuit, hence less emitter current.
      Similarly, in the common emitter, the input current is the BASE CURRENT (Ib). Just as in the case of common base, the effective depletion width decreases, but this time we care about the amount of electrons that donot travel to the collector. Since most electrons passes through to the collector with the increase in output voltage, there's less base current.

  • @iiestphysics
    @iiestphysics 3 ปีที่แล้ว

    0:48

  • @PB_293
    @PB_293 3 ปีที่แล้ว

    Watching in 2021😃😃

  • @akshayraina1298
    @akshayraina1298 5 ปีที่แล้ว

    The base current should be in micro-amps!

  • @alterguy4327
    @alterguy4327 7 ปีที่แล้ว +1

    Eureka✌

  • @GurpreetSingh-yq8wu
    @GurpreetSingh-yq8wu 5 ปีที่แล้ว

    first you say if vbe increases ib decreases and then you plot the opposite

    • @ankitbanerjee879
      @ankitbanerjee879 5 ปีที่แล้ว

      He said when Vce increases Ib decreases ,bro

  • @krishnamurari5553
    @krishnamurari5553 6 ปีที่แล้ว

    Sir pls make videos in Hindi also

  • @sonushaik1218
    @sonushaik1218 6 ปีที่แล้ว +1

    HAII sir
    Can you plz tell some slowly sir plz

  • @janapatichinnavenkateswarl4939
    @janapatichinnavenkateswarl4939 5 ปีที่แล้ว

    In ce there is no early concept

  • @md.rubelrana2119
    @md.rubelrana2119 6 ปีที่แล้ว

    Fine

  • @Nur-zf2kl
    @Nur-zf2kl 6 ปีที่แล้ว

    Diag.helpful

  • @Bandhabi-u2l
    @Bandhabi-u2l 7 หลายเดือนก่อน

    sound volume of videos is very insufficient

  • @mohamedosama597
    @mohamedosama597 5 ปีที่แล้ว +3

    This my great doubt in transistor...

  • @adycerriteno3230
    @adycerriteno3230 ปีที่แล้ว

    how can depletion layer penetrate😠😠😠😠😈

  • @mayankjoshi1502
    @mayankjoshi1502 4 ปีที่แล้ว

    Base emiter junction is reversed biased instead of forward bias lol

  • @kashiusofficial5179
    @kashiusofficial5179 4 ปีที่แล้ว

    There's indonesian subtitle in this video, but am i the only Indonesian here?

  • @nikhilshahare6241
    @nikhilshahare6241 7 ปีที่แล้ว

    Please reply as soon as possible.. I m eager to know.

  • @CM-hn6oc
    @CM-hn6oc 6 ปีที่แล้ว

    😘😘😘😘😘😘😘😘😘😘😘😘😘😎

  • @inspector_Anil
    @inspector_Anil 8 ปีที่แล้ว

    1st viewer

    • @alterguy4327
      @alterguy4327 7 ปีที่แล้ว

      Anil kumar Congrats😅😅

  • @naveenmondru5253
    @naveenmondru5253 7 ปีที่แล้ว +2

    graph iss wrong shold go to right not left

    • @as72333
      @as72333 6 ปีที่แล้ว

      he is decreasing the voltage and on decreasing the voltage current increases so it goes to left

    • @sabbavarapuchandrakala8513
      @sabbavarapuchandrakala8513 5 ปีที่แล้ว

      first you need is graamerly appp