For zener diode[1.27], Vo = -10v Hence, Voltage across 10 ohm resistor is (-10v). While the given break down voltage is 3.2v. 3.2> -10 v. Then, why does the zener diode considered as open circuit with break down? Isn’t it only open circuit?
If you see the operation of Zener diode, it is operated in reverse bias (as a voltage regulator). In the forward bias condition, it will act as a normal diode. In the reverse bias, when the voltage across it is more than the Zener breakdown voltage, it conducts and before that, it remains an open circuit in the reverse bias condition. For more info, please check this video: th-cam.com/video/MZPeRlst8rQ/w-d-xo.html
It’s a Zener diode. In forward direction it works like a normal diode but in the reverse direction when the voltage across it is more than the breakdown voltage then voltage across it remains constant.
For more question on op-amp check this playlist :
th-cam.com/play/PLH9R5x7JVXCFFScqREEGiFCSyKVM3RTM8.html
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In 2:42 sec, why you choose I2 and I3 currents are incoming?
Thanks Sir!in the circuit that the Zener voltage is always exist！
(0-1/1)+(0-Vo/10)+(0-Vo-3.2/10)=0,-2Vo=-13.2,Vo=-6.6v
Thank you for your efforts.....Sir
Amazing
Thanks sir
Could you please specify the simulator you used. Thanks in advance.
Its Multisim
Hello sir 👋
For zener diode[1.27], Vo = -10v
Hence, Voltage across 10 ohm resistor is (-10v). While the given break down voltage is 3.2v. 3.2> -10 v. Then, why does the zener diode considered as open circuit with break down? Isn’t it only open circuit?
Plz suggest me a book for practising this type of problem
The current through zener doide should be from + ve terminal to - ve terminal but u considered current from -ve to +ve .
If you see the operation of Zener diode, it is operated in reverse bias (as a voltage regulator).
In the forward bias condition, it will act as a normal diode.
In the reverse bias, when the voltage across it is more than the Zener breakdown voltage, it conducts and before that, it remains an open circuit in the reverse bias condition.
For more info, please check this video:
th-cam.com/video/MZPeRlst8rQ/w-d-xo.html
Why you were took opposite polarities to diode...
It’s a Zener diode. In forward direction it works like a normal diode but in the reverse direction when the voltage across it is more than the breakdown voltage then voltage across it remains constant.