#10 PROBABILITY || Bayes' Theorem
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- เผยแพร่เมื่อ 5 ก.ย. 2024
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Addition, Multiplication & Conditional Probability Theorem
• #3 PROBABILITY || Addi...
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Thank you so much sir,,,,❤huge salute to you from Bangladesh 🔥
Most Welcome and Thank you 🙂💫
Probability sirfff aapse smjhh aaya h ...nd i ell never forget ❤❤❤🎉🎉
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Thank you sir i have done my whole the topic of probability in sequence 1st time from your playlist. Thank you so much😊
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Thanku sooo much sir very helpful 🙏
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Thank you sir your teaching is really great 👍
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Thank you sir❤
ANOVA pr bhi video bana dijiye
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Thank you so much sir
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You are too good at probab👍
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@@SameerPandey arry definitely brother .....very good teacher you are ...
Keep it up ❤️👍
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❤ amazing keep it up .. 👍👌🏻😍
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Nice explanation sir
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Great sir u help me lot
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Sir please make a detailed video on conditional probability
Banaya to hai ispar video... pls check playlist...'Probability'.
Sir please make a video on hypothesis testing .. 🙏🏽
Okk noted 👍
Nice sir
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Tx sir g❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️
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Sir, it's important to add all events i.e E1,E2... Some event can't find the probability of A(Total probability theorem) ? It's necessary to be the part of every subset of sample space?
let we divided a sample space into four parts E1, E2,E3,E4, now we have to find the probability of happening event A
And we can find it just by using the probability of E1 AND E2.
🤷🏽🤷🏽
I didn't get your question
@@SameerPandeyTHANK YOU SIR FOR YOUR REPLY, I REALLY APPRECIATE IT. 👏🏼
Sir in total probability theorem we let E1, E2, E3, E4.... En be a partition of sample space S, and suppose that each of the event has nonzero probability of occurrence and they(events E1, E2.. enjoy) are mutually exclusive and exhausting. THEN WE FIND THE PROBABILITY OF AN EVENT let A.
---->> P(A)=p(E1)p(A|E1) + p(E2)p(A|E2) +....+p(En)p(A|En).
If a split a sample space into four parts(E1, E2, E3, E4, which are mutually exclusive and exhaustive) , then it's POSSIBLE that the probability of event A would be
P(A)=P(E1)P(A|E1)+P(E2)P(A|E2)
here in this example I exclude P(E3)P(A|E3), we know that P(A intersection E3) = P(E3)P(A|E3)(BY CONDITIONAL PROBABILITY)
SO MY QUESTION IS, IS THERE ANY POSSIBILITY THAT WE EXCLUDE ANY EVENT PROBABILITY AS IN ABOVE EXAMPLE WE EXCLUDE THE EVENT 3 PROBABILITY BECAUSE THERE IS NOTHING COMMON BETWEEN THE event A AND event E3?
See the events E1, E2, E3 though mutually exclusive but they are a part of the complete sample space in which there is a sub event A is present. So if you want to find the probability of A, then you have to take into consideration all the partition events E1 E2 and E3..
@@SameerPandey Thank you very much sir for clearing this doubt 👌👌
Most welcome 🙂
Sir can you provide me all notes of statistics class 12th
You won't need notes..just watch these videos they contain all the important concept and numerical..
Complete Statistics Playlist
th-cam.com/play/PLH7XtzEtxPEY--2X_yYqSEal3Y2yD2azk.html
But for reference you can also go for 'Statistics for class 12' by Sandeep garg or 'Business Statistics' By Dr. S.M. Shukla
Kcm of 20 and 16...?
What??