Boolean algebra #2: Basic problems

visit www.keleshev.com/ for structured list of tutorials on Boolean algebra and digital hardware design!

[@ReginaYe]

You're so much clearer than my professor! Thank you.

[@TheAhernFamily1]

Thanks Vlad for the tutorial finally you explained it in "dummie" terms so I could understand it finally! Subbed.

[@WeaponOfKnowledge]

Thank you so much for posting these videos. I am watching every single one of your series, it is extremely helpful and actually useful. Kicks my textbook's ass. And my teachers.
Please keep exploring the world of electronics by posting videos. We need them.

[@Caleb6801]

Have an exam tomorrow. My professor actually recommended over viewing this series. Fingers crossed haha

[@krshah2008]

thanks :)
I have exam in one hour :P

[@triton62674]

Haha

[@125dudeman]

So do i lol

[@Alhussainba]

How did you do in yours ? Mine is in 4 hours.

[@ROFEL]

he failed

[@simba7161]

How'd it go :)

[@CeleryBruh]

I don’t know normal algebra very well, only really focused until 8th grade but I got the hang of these basic problems very easily due to your teaching

[@VictorTorres-fi7mu]

wow this was insanely helpful i had no idea what my teacher was talking about today and now I get it after this subbed and liked!

[@marceloebordajr.7010]

thanks for the video tutorial vladimiar. your so good about making it simple to explain the boolean algebra method... thanks a lot. you make the method easier to understand good job sir

[@devendrabhagat2480]

Great Video, A lot of thanks for a simple way to understand this algebra.

[@iantaiahn7022]

Thank you for being so clear with the explanation!

[@esoesminombre7056]

Awesome man! You're making so much more sense than my teacher!

[@johnny6041]

11 years later and I found u to be my savior
btw I'm majoring in computer science

[@Deliryz]

Thank you SO MUCH for taking the time and making this videos, I understand everything now :D

[@Knightmetal]

Hey man, I've been watching your videos for about 2 weeks now, I have an exam this Friday and I'm happy to have found someone who could explain this thoroughly, I haven't found anyone on TH-cam who has done this way, I finally understand boolean algebra, thanks.

[@amanturabdykarov2116]

did you pass the exam BRO!?

[@monjasonsteng7861]

You explain boolean algebra well. Thank you a lot

[@faryzryz1482]

Woahhh ,your video make it easier to understand... Thanks !

[@vishalmurali7595]

I REALLY UNDERSTOOD BOOLEAN WELL BECAUSE OF THESE VIDEOS.......
THANK YOU

[@siphiwejoyce3880]

Wooow...this totally Helped Me. Thanks A Lot.

[@yashasvis7275]

I'm so happy you posted this, this saved my life for my test tomorrow :)

[@abualasif]

sameeee

[@LamiereByM]

Thank you so much! This has been so helpful.

[@kokhonghean5621]

Your explanation is awesome!

[@mairt100]

Thank you so much! I have an exam on this tomorrow and up til now I didnt understand one bit of it but now it makes sense! Thank you!

[@milvertonzumba1634]

greatest video of all time thank you

[@krikkaa]

Thanks for the easy explanations!

[@TheShukladhvaj]

Your explanation is really good.

[@tangsongyao5893]

thanks it makes me more understanding.

[@gilgamesh2399]

Thank you, I can now understand my class!!

[@damien200984]

great stuff... keep them coming

[@FearDaPanduh]

Thanks for the great explanation, subscribed and liked

[@Mopzboy]

I had no problems throughout the semester but this is great revision for the exam, thanks heaps!

[@maquinadeescreverdig]

Thank You Very much Vladimir!Your explanation is clear,I wish you were my professor!

[@InCog2020]

This is the first time I've ever actually GOT this. Thanks so much for posting these!

[@abualasif]

fax this guy is the goat

[@TANUJKUMARPandey9999]

It helped me a lot...thanks a lot man..gravity be with you 👍

[@SeidenFisk]

great tutorials, thank you very much

[@waelbadria9385]

You are the best sir. Thank you

[@mawadaxx457]

Thank you this helped me a lot

[@MrJAlabaster]

OMG!!! You are a lifesaver!!!

[@2happyfeet3]

thank you vladimir, really pulling through 10 years later

[@kairiannah]

Thank You!!

[@kyriacosh4569]

you just save me mate ! really thank you!

[@yashwanthroyal5728]

Thats a great video sir i didnt found it anywhere

[@EvanDinelli]

cool stuff, thanks for the good explanations

[@officiallymervii8008]

I learnt a lot from this honestly

[@pkyoupvp]

Thank you so much for this!!!!

[@UMLRAI]

You sound like Russian..well i have exam tomorrow and if i pass and if someday if we met then my friend the Vodka is on me

[@NikhiLPandargE300597]

😀😀😆😝

[@raficn9277]

Did u pass? Lol

[@samgrey3221]

Shit I wanna know too

[@arasseyoo]

How was it!? 😂

[@pickle5337]

He left us on a cliffhanger

[@dsshashank9651]

i dint understand dis chapter in college...but u teached me lyk a game!!!

[@mailong9173]

Thanks! Very Useful to me

[@kk2586]

Thank You Once Again Sir!!!

[@KavinduJayanga]

thanks for the lesson..really helpful (y)

[@ClarityJustin]

THANKS! YOU SAVED MY LIFE

[@ibrahimballa20]

Thank You these video made it easy

[@MrRykooo100]

Thanks, great video!

[@mollovg100]

Hello and thank you very much for this video its very easy to understand. I dont have a problem with A(1+B) for example but what if you have AB + A'B I saw that it works like A(B+'B) but is that a rule as a whole when you have another letter after the initial (in this case A) and only if there are repeating letters like in this case A and A and B or B. I guess what I am trying to ask is in which cases the expression can be simplified in this way? Thanks again

[@ItsTheLyricalMC]

Great work thanks

[@gorgeousbe8605]

Good job! Thank you so much

[@giorgosma]

very good videos you rly helping me a lot

[@fidelpecout2289]

Superb video, thank you very much

[@rakib17874]

awesome..tryingdays to learn..but now with this im done under half hour

[@shahebmiah2492]

Great explanation

[@TwiStedTentom]

The problem at 8:15. Did you use absorbtive law to get rid of that second A, or what that factoring? Or?

[@michelletheatom]

A'+BA'= A'(1+B)
So, the answer is: A'

[@malikanas6445]

Yes

[@abualasif]

Thanks a lot. Much appreciated

[@RedOkamiDev]

Thanks!! exam is next week XD so helpful

[@ajaykrishna5367]

you could use 1and0 insted A AND B

[@matokaz]

thanks vlad ur my boy

[@maloemalhen]

you are so helpful

[@xasma.x1786]

Thank you so much

[@NOKIAisFINLAND]

Thanks alot sir.

[@FidesNigeria]

PLEASE HELP ME WITH A SOLUTION, WHAT IS THE RESOLUTION FOR (AB)' +AB THANKS

[@hananwebb2443]

thank you😍😍😍your amazing

[@ClarkDroneFilms]

thank you sir

[@milannekuhh9818]

You saved my examn, thanks

[@nomannmaheri]

Thanks so much man, I can finally understand this lol

[@markoticinovic6626]

Thanks a lot man.

[@moazelsawaf2000]

Thank you sir ❤

[@jackzheng8535]

Thank you king

[@ayushthaper9601]

Great video, Thanks :)

[@hckr_-gh7se]

So for the last problem I found A-negated, is that right?

[@jcr4745]

Very good video

[@andrewmartin9440]

At time code 0:28, why is it assumed A is 1? Thanks for the great videos!

[@andilechoko9686]

A is actually A * 1...I think that is what the man was explaining

[@Likoko1000]

HI, I WANT TO KNOW IF U LEAVE AN EXPRESSION LIKE THIS; NOT A+A NOT B NOT C, IS IT SIMPLIFIED? OR CAN IT BE SIMPLIFIED FURTHER BECAUSE THERE IS A and NOT A?

[@4cheech]

thanks,boss!

[@Moneytipsbyfess]

good job!!!

[@Dra60oN]

Why you didnt answer call from dimochka?

[@ashrafulrabbi]

dimochka is dirsturbing бообще !!

[@SarahGuadagnin]

How do I know that A is actually multiplied by one and I can take it out of brackets?

[@SirTravelMuffin]

Sarah It's because anything multiplied one still equals itself: 3*1=3 0*1=0 A*1=A
So A+A*B can be written as A*1+A*B
A can then be factored out leaving A(1+B)
If that still doesn't make sense, distribute A to both terms in the parentheses

[@TheAhernFamily1]

This whole time it wasn't making sense when my teacher was explaining it.. but the light just clicked on when Vladimir was explaining it.

[@mario6279]

A+0=A, A+A=A, A×A=A so why would I specifically choose A+1=A??

[@snowwcone]

+Sheldon Cooper its multiplication (AND operator) not addition (OR operator). A*1 = A every time. if A=1 then 1*1=1 if A = 0 then 0*1=0

[@mario6279]

Braedon O thank you teachers feel the need to prove their intelligence so they over complicate things when they are talking to someone with the brain the size of a peanut. They could be talking to someone with down syndrome and pull out big words and numbers out their ass

[@Saralcfc]

Thanks a lot :)

[@SANJANASINGH-gp3wh]

good work,sir!

[@indrajityadav1280]

SANJANA SINGH
Can you tell
A'+B'=A'B'
This is equal or not.

[@sohailhameed5140]

thx great video

[@Mrdachs88]

Thank You

[@GamesAddictHD]

Thanks to you sir :)

[@english1ize]

ur the best man

[@keleshevCOM]

@Supermanu15 You are welcome :-)

[@lukasscharmitzer5606]

good job

[@mwmaes]

I am not understanding your first step in how you are getting A + AB = A(1+B), can you please explain how you get the 1 in that function. Thanks

[@mrpapabear4138]

can you help me with a problem?

[@abualasif]

Is the answer to the last question 'not A' ?

[@IxnoIxno]

good material sir

[@MN-gp2cu]

Hi, first example A+AB = A+A=A then we have only one A and expression of B in brackets 1+B but why???

[@bearythemp5kpro541]

but how did A get multiplied by 1?

[@bobmarley8644]

In Addition if one of the values equals 1 than the result always eqals 1 and in multiplication if both eqal 1 then the result is 1 other wise the result is 0...

[@stanmoonie6508]

A + A*A' should it not be A*A' = 0 using the complement law and A + 0 = A?