In the review slide of Lec3 at 2:40, there is a slight mistake. The transconductance in the voltage gain expression should be of the input transistor i.e. gm2 instead of gm1.
01:25 - Intro and Review 12:22 - Example 1: Change in Cascode Amplifier with Ideal Load when: Bias current is halved, widths are doubled. 18:35 - Example 2: Change in Cascode Amplifier with Non-Ideal Load 27:40 - Quiz: Connecting Input Signal on Cascode Transistor 37:25 - CS Amplifiers with P-Type Input 44:10 - Cascode Amplifiers with P-Type Input
for the Quiz at about 36:00 I assumed r01 to be less than infinity, constructed the SSM and got Gm = gm1/(1+ gm1*r02 + r02/r01) that reduces to Gm = gm1/(1+gm1*r02) when r01 is set to infinity which agrees with the Prof. result. Can anyone else confirm the result with r01 less than infinity?
Thanks dear professor, but I can't find derivation the transconductance of a degenerated transistor Gm = gm1 / 1+gm1*ro2 in Electronics1. Can you help us by saying where it is exactly.
From small signal analysis taking a degeneration into account we have 2 equations :KVL gives Vin = V1 + (gm *r02*V1) , KCL gives : Vout = gm*V1*r02 ,,, cancel Vi from both equations and put both equation in AV form yields : Vout/Vin = gm * r02 /(1+gm*r02),,,, and if we rewrite it in a new form Av = - Gm * Rout gives Gm = gm/(1+gm*r02) Hope it helps
the multiplying factors are not in parallel. If R1 || R2 and both of them being multiplied by some factor x, the overall result is multiplied by factor of x, so the answer is 1/sqrt(2) * 4/sqrt(2) = 2
for the Quiz at about 36:00 I assumed r01 to be less than infinity, constructed the SSM and got Gm = gm1/(1+ gm1*r02 + r02/r01) that reduces to Gm = gm1/(1+gm1*r02) when r01 is set to infinity which agrees with the Prof. result. Can anyone else confirm the result with r01 less than infinity?
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In the review slide of Lec3 at 2:40, there is a slight mistake. The transconductance in the voltage gain expression should be of the input transistor i.e. gm2 instead of gm1.
Yeap!
@@inoth79 yes
Yes
Agreed. Good catch! To spell it out, the equation on the bottom right should be Av ~= -gm2[(gm1*ro1*ro2)//(gm4*ro4*ro3)]
01:25 - Intro and Review
12:22 - Example 1: Change in Cascode Amplifier with Ideal Load when: Bias current is halved, widths are doubled.
18:35 - Example 2: Change in Cascode Amplifier with Non-Ideal Load
27:40 - Quiz: Connecting Input Signal on Cascode Transistor
37:25 - CS Amplifiers with P-Type Input
44:10 - Cascode Amplifiers with P-Type Input
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for the Quiz at about 36:00 I assumed r01 to be less than infinity, constructed the SSM and got Gm = gm1/(1+ gm1*r02 + r02/r01) that reduces to Gm = gm1/(1+gm1*r02) when r01 is set to infinity which agrees with the Prof. result. Can anyone else confirm the result with r01 less than infinity?
Yes bro, i got the same...
thanks prof
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please also do lectures on MIXED SIGNALS , please sir
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Interesting lecture
Thanks dear professor, but I can't find derivation the transconductance of a degenerated transistor Gm = gm1 / 1+gm1*ro2 in Electronics1. Can you help us by saying where it is exactly.
It should not be too difficult to derive using the small signal analysis.
bro as now Vgs= Vin- Iout*r02 thats why Gm is not equal to gm1
@@amitkumar-sh2lk Thanks it helps
From small signal analysis taking a degeneration into account we have 2 equations :KVL gives Vin = V1 + (gm *r02*V1) , KCL gives : Vout = gm*V1*r02 ,,, cancel Vi from both equations and put both equation in AV form yields : Vout/Vin = gm * r02 /(1+gm*r02),,,, and if we rewrite it in a new form Av = - Gm * Rout gives Gm = gm/(1+gm*r02)
Hope it helps
@@mutasemwahbeh6954 Thank you so much!
Thanks
since in cascode, as ID is same, gm of pmons and nmos must be same? why he says change is transcondutance.
Sorry, but am I being ignorant? It seems to me that the big equation for gm for Av in the center of the page should be -gm2 not -gm1.
18:31
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at 25:06, Av=1Av , Because 1/sqrt(2) * [4/sqrt(2) || 4/sqrt(2)] = 1
the multiplying factors are not in parallel. If R1 || R2 and both of them being multiplied by some factor x, the overall result is multiplied by factor of x, so the answer is 1/sqrt(2) * 4/sqrt(2) = 2
@@ozgunyurutken9485 oh, I was wrong
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for the Quiz at about 36:00 I assumed r01 to be less than infinity, constructed the SSM and got Gm = gm1/(1+ gm1*r02 + r02/r01) that reduces to Gm = gm1/(1+gm1*r02) when r01 is set to infinity which agrees with the Prof. result. Can anyone else confirm the result with r01 less than infinity?
30:29