You are the best professor I have ever learned from. I really hope that all professors do the same and be humble as you. They think all students are as experienced as they. they need to put themselves in our shoes
01:25 - Intro and Review 04:19 - General Properties of the MOS Differential Pair 15:00 - Note: CMRR is affected by the tail current output resistance 15:12 - Rough Differential Behavior of the MOS Differential Pair 20:12 - Saturation Region of the MOS Transistor 21:43 - Example: The Minimum Value of the Input Differential Signal when one Transistor Turns Off 29:00 - Large-Signal Analysis of the MOS Differential Pair 44:00 - Note: Overdrive voltage is important as it defines largest differential input voltage amplitude
First you have to square both sides where he left off at 39:00 to solve for Id1. Then you must move everything to the same side and multiply everything out. After that, you have to use the quadratic formula where a = -16, b = 16*Iss, and c = 4*(Vid^2)*Iss*kn-4*(Iss^2)-(kn^2)*(Vid^4). Once you have plugged everything into the quadratic formula, simply it as much as possible. Now, repreat all of that to find Id2. Next subtract Id2 from Id1. Both Id1 and Id2 should have a section of their equations where there is a +/-. For Id1, make the +/- a +, and for Id2, make the +/- a -. Once you do this, you can simplify it into the final equation that he provided. It's a bunch of algebra, but once you get going it won't seem so bad.
Bit rude, but I know what you mean, There is decent hand-holding in his videos, but the flow of concepts in the book is not articulated well enough. Newbie reader feels like he is being swung from one circuit topology to another, with no support whatsoever.
You are the best professor I have ever learned from. I really hope that all professors do the same and be humble as you. They think all students are as experienced as they. they need to put themselves in our shoes
01:25 - Intro and Review
04:19 - General Properties of the MOS Differential Pair
15:00 - Note: CMRR is affected by the tail current output resistance
15:12 - Rough Differential Behavior of the MOS Differential Pair
20:12 - Saturation Region of the MOS Transistor
21:43 - Example: The Minimum Value of the Input Differential Signal when one Transistor Turns Off
29:00 - Large-Signal Analysis of the MOS Differential Pair
44:00 - Note: Overdrive voltage is important as it defines largest differential input voltage amplitude
thanks for the series of lecture upload in TH-cam!!!!! It could be life saving for an individual trying self-studying electronics alone!!
These lectures save my midterm and they will save me again in final
Waiting eagerly for circuit theory I & II and the rest of the series.
Excellent Lecture......My humble request to cameraman to please pay attention to the noise comming in between.
i think he is filming alone in his house
Thanks for these videos. Life savers.
Thank you so much, Sir!!!! Really love your lecture!
thank you sir ,,, u give lots of time
I love your lectures.
Brilliant job!
brilliant lecture
GOAT
Excellent lecture
what it must feel like to be a genius like yourself
Maybe lonely, but absolutely fulfilling!
brilliant explanation sir
سلامت باشه این استاد
ازيك يا باشه هههه
Nice Prof ❤️
brilliant
checked!
Bro really wants us to solve the equations at 39:50 💀💀💀💀
The ID1 that I get by calculation is ID1=1/2Iss ± 1/2 Kn(Vin1-Vin2)^2 (don't know if it's correct or not yet.)
how to get final result of (Id1- Id2)?
First you have to square both sides where he left off at 39:00 to solve for Id1. Then you must move everything to the same side and multiply everything out. After that, you have to use the quadratic formula where a = -16, b = 16*Iss, and c = 4*(Vid^2)*Iss*kn-4*(Iss^2)-(kn^2)*(Vid^4). Once you have plugged everything into the quadratic formula, simply it as much as possible. Now, repreat all of that to find Id2. Next subtract Id2 from Id1. Both Id1 and Id2 should have a section of their equations where there is a +/-. For Id1, make the +/- a +, and for Id2, make the +/- a -. Once you do this, you can simplify it into the final equation that he provided.
It's a bunch of algebra, but once you get going it won't seem so bad.
8:20
16:34
When Vgs = 2Vth, what will be the region of operation?
Depends on what is Vds, if Vds >Vgs - Vth, it is in saturation region else triode region.
brilliant way of explanation but please don't write books anymore.
Bit rude, but I know what you mean,
There is decent hand-holding in his videos, but the flow of concepts in the book is not articulated well enough.
Newbie reader feels like he is being swung from one circuit topology to another, with no support whatsoever.