Razavi Electronics2 Lec12: Large-Signal Analysis of MOS Differential Pair

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  • เผยแพร่เมื่อ 9 พ.ย. 2024

ความคิดเห็น • 36

  • @anaseshmawi568
    @anaseshmawi568 5 ปีที่แล้ว +33

    You are the best professor I have ever learned from. I really hope that all professors do the same and be humble as you. They think all students are as experienced as they. they need to put themselves in our shoes

  • @coolwinder
    @coolwinder 3 ปีที่แล้ว +23

    01:25 - Intro and Review
    04:19 - General Properties of the MOS Differential Pair
    15:00 - Note: CMRR is affected by the tail current output resistance
    15:12 - Rough Differential Behavior of the MOS Differential Pair
    20:12 - Saturation Region of the MOS Transistor
    21:43 - Example: The Minimum Value of the Input Differential Signal when one Transistor Turns Off
    29:00 - Large-Signal Analysis of the MOS Differential Pair
    44:00 - Note: Overdrive voltage is important as it defines largest differential input voltage amplitude

  • @jing-chingchen2333
    @jing-chingchen2333 4 ปีที่แล้ว +7

    thanks for the series of lecture upload in TH-cam!!!!! It could be life saving for an individual trying self-studying electronics alone!!

  • @林佑-z9h
    @林佑-z9h หลายเดือนก่อน

    These lectures save my midterm and they will save me again in final

  • @mnada72
    @mnada72 3 ปีที่แล้ว +7

    Waiting eagerly for circuit theory I & II and the rest of the series.

  • @prashantsharma5618
    @prashantsharma5618 6 ปีที่แล้ว +25

    Excellent Lecture......My humble request to cameraman to please pay attention to the noise comming in between.

    • @zinhaboussi
      @zinhaboussi 11 หลายเดือนก่อน +1

      i think he is filming alone in his house

  • @hemantj675
    @hemantj675 ปีที่แล้ว +2

    Thanks for these videos. Life savers.

  • @felixqi6659
    @felixqi6659 3 ปีที่แล้ว +2

    Thank you so much, Sir!!!! Really love your lecture!

  • @samtiny6332
    @samtiny6332 6 ปีที่แล้ว +4

    thank you sir ,,, u give lots of time

  • @camilotello3296
    @camilotello3296 2 ปีที่แล้ว

    I love your lectures.

  • @gevorggeghamyan1718
    @gevorggeghamyan1718 6 ปีที่แล้ว +3

    Brilliant job!

  • @swarnikashruti5308
    @swarnikashruti5308 4 ปีที่แล้ว +1

    brilliant lecture

  • @12345breakdown
    @12345breakdown 2 ปีที่แล้ว +1

    GOAT

  • @danysharrouf8207
    @danysharrouf8207 5 ปีที่แล้ว +1

    Excellent lecture

  • @zeustheboerboel3794
    @zeustheboerboel3794 5 ปีที่แล้ว +5

    what it must feel like to be a genius like yourself

    • @coolwinder
      @coolwinder 3 ปีที่แล้ว

      Maybe lonely, but absolutely fulfilling!

  • @velmalagangadhar1532
    @velmalagangadhar1532 6 ปีที่แล้ว +1

    brilliant explanation sir

  • @hosseintjk4324
    @hosseintjk4324 6 ปีที่แล้ว +1

    سلامت باشه این استاد

    • @zinhaboussi
      @zinhaboussi 11 หลายเดือนก่อน

      ازيك يا باشه هههه

  • @abdxlive
    @abdxlive 8 หลายเดือนก่อน

    Nice Prof ❤️

  • @Krishnasharma-wc4wo
    @Krishnasharma-wc4wo 5 ปีที่แล้ว +1

    brilliant

  • @DuyNguyen-kh5tk
    @DuyNguyen-kh5tk ปีที่แล้ว

    checked!

  • @prat4142
    @prat4142 ปีที่แล้ว +3

    Bro really wants us to solve the equations at 39:50 💀💀💀💀

    • @e1490807aa
      @e1490807aa ปีที่แล้ว

      The ID1 that I get by calculation is ID1=1/2Iss ± 1/2 Kn(Vin1-Vin2)^2 (don't know if it's correct or not yet.)

  • @engine28111
    @engine28111 4 ปีที่แล้ว +1

    how to get final result of (Id1- Id2)?

    • @alexnoggle1874
      @alexnoggle1874 2 ปีที่แล้ว

      First you have to square both sides where he left off at 39:00 to solve for Id1. Then you must move everything to the same side and multiply everything out. After that, you have to use the quadratic formula where a = -16, b = 16*Iss, and c = 4*(Vid^2)*Iss*kn-4*(Iss^2)-(kn^2)*(Vid^4). Once you have plugged everything into the quadratic formula, simply it as much as possible. Now, repreat all of that to find Id2. Next subtract Id2 from Id1. Both Id1 and Id2 should have a section of their equations where there is a +/-. For Id1, make the +/- a +, and for Id2, make the +/- a -. Once you do this, you can simplify it into the final equation that he provided.
      It's a bunch of algebra, but once you get going it won't seem so bad.

  • @velukrishna808
    @velukrishna808 3 ปีที่แล้ว

    8:20

  • @mrpossible5696
    @mrpossible5696 5 ปีที่แล้ว +1

    16:34

  • @ayshaabdulgani442
    @ayshaabdulgani442 6 ปีที่แล้ว

    When Vgs = 2Vth, what will be the region of operation?

    • @sauravarjun6224
      @sauravarjun6224 6 ปีที่แล้ว +3

      Depends on what is Vds, if Vds >Vgs - Vth, it is in saturation region else triode region.

  • @not_nerd_iitian1764
    @not_nerd_iitian1764 2 ปีที่แล้ว +2

    brilliant way of explanation but please don't write books anymore.

    • @Abhishek_78
      @Abhishek_78 ปีที่แล้ว +2

      Bit rude, but I know what you mean,
      There is decent hand-holding in his videos, but the flow of concepts in the book is not articulated well enough.
      Newbie reader feels like he is being swung from one circuit topology to another, with no support whatsoever.