sir in physical chemistry i am totally dependent on your one shot,,,after doing your lecture and revising lec i am doing allen module is that enough or i have to do ncert intext as well,,,,,,,hope you will reply
don't neglect the standard book NCERT at least finish intext questions, if you do exercise also then it's perfect it's all about my opinion I think still time is there 😊
thank you soooooooo much sir for taking this lecture . for student like me who doesn't know anything can able to solve questions ,after watching this lecture 😊
Sir if 3 or more eq is given then to calculate order we have to consider the slow rxn that type of prblm creates prblm pls explain that in a short video it is not covered here thank you for the session❤❤🌸
Is the differential rate eq is getting divided by corresponding stochiometric coeff because that's the ration inverse of which they get used up in a reaction
Well ya simple ,, first need to find atm by sec as it's convenient due to given data rate = disappearance of reactant/ stoichiometry,, we know here in terms of concentration we use pressure we get 0.1 something,, then p=conc rt ,, p /rt = conc ,, substitute p = 5 and 2.5 seperate and subtract to find difference ,, we get 2.5 by rt multiply by 1 by 2 as rate in mol /l*s..
5:10:16 [A°]=n/V=0.1/2=0.05 M There is no trick n=t*k/0.693 On sub the values : n=1 A(t)=A° / 2^n A(t)=0.05/2 A(t)=0.025 M That's it , If anyone understood what he meant to say ? Please comment
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There was a technical glitch. Couldn’t start the live session. Therefore posted this Chapter in the recorded format. Complete it❤️
ok sir
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ur health our wealth
Ok... Sir... Thnk u so much🙏.... Respect to u... Take care of ur Health... God bless u
1:12:50
Pressure:0.125 atm/s
Divide the above value (RT)
That is ,
0.0821*300
Then in M/s is
Appro: 0.005 M/s
1:20:48 Answer I got X=4 Y=1
It is difficult to resist chemistry when he teaches❤
Welcome back Thalaiva 🔥🔥
King for a reason ❤
Sir please take hydrocarbon chapter
Yes sir
yes sir
Yes sir 😢
It's crystal clear sir🎉🎉🎉🎉 thank you so much 💃💃💃 and I am also suggesting ur videos to my frnds
Where to get the notes?
Sir take hydrocarbon chapter
Thank you so much sir nice explanation fantastic
sir in physical chemistry i am totally dependent on your one shot,,,after doing your lecture and revising lec i am doing allen module is that enough or i have to do ncert intext as well,,,,,,,hope you will reply
don't neglect the standard book NCERT at least finish intext questions, if you do exercise also then it's perfect it's all about my opinion I think still time is there 😊
Is this used for jee
Is this lecture sufficient for neet 2025?
2:55:05 zero order rxn
Finally completed 🎉🎉 almost 7hrs video.. thank you sir❤❤
1:19:13 X=4 and y=1
Yes sir d and f block elements
Is this video useful for jee mains students sir??
Yess
We're surely going to blame only you sir if we got good scores in chemistry 🔥
Super
The way he explains the concepts of physical chemistry is out of the world...
fantastic session sir ultimate 😔😇😇😇🤩🤩🤩🤩🤩🤩
Sir when u r going to start end game 3.0 batch sir
Thank you so much sir 🙏🔥🔥🔥🔥🔥🔥🔥🔥🔥♥️
Sir pls do coordination compound one shot too
Yes sir please do it
Yes we want that chapter otherwise someone tell how to learn that chapter plz🥺
Sir goc part 2
Super explanation sir❤❤❤❤
thanku so much sir
Sir,, where can we get the notes??
Yes sir
Lecture pdf sir......... 😢
thank you soooooooo much sir for taking this lecture . for student like me who doesn't know anything can able to solve questions ,after watching this lecture 😊
Thanks Sir🎉🎉🎉
Yeah d and f
Sir d and f block elements session sir
Organic chemistry sir..
Sir if 3 or more eq is given then to calculate order we have to consider the slow rxn that type of prblm creates prblm pls explain that in a short video it is not covered here thank you for the session❤❤🌸
Hey these r not asked in neet exams those r only for jee advanced
Clear❤❤❤
Is the differential rate eq is getting divided by corresponding stochiometric coeff because that's the ration inverse of which they get used up in a reaction
Telegram channel is it available sir?
Yes given in description
Every thing is complete
May Allah bless you more sir ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Very clear explaination sir😊
Excellent sir hands off
sir is instantinous rrate of rean is k
3:07:15
1.17 min sir log of negative is undefined sir
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DOUBT sir:
sir can i say fpor all decomposition reaxtion molecularity is 1
Sir is this helpful for jee students
Haa Bhai
Sir please ans the question 1:12:49 please
is it 5
Yes 5
How ? Can u pls explain
I got 0.125
Well ya simple ,, first need to find atm by sec as it's convenient due to given data rate = disappearance of reactant/ stoichiometry,, we know here in terms of concentration we use pressure we get 0.1 something,, then p=conc rt ,, p /rt = conc ,, substitute p = 5 and 2.5 seperate and subtract to find difference ,, we get 2.5 by rt multiply by 1 by 2 as rate in mol /l*s..
Pls upload collision theory sir..
Sir do you know telugu so that i can ask doubts in Telugu
5:10:16
[A°]=n/V=0.1/2=0.05 M
There is no trick
n=t*k/0.693
On sub the values :
n=1
A(t)=A° / 2^n
A(t)=0.05/2
A(t)=0.025 M
That's it , If anyone understood what he meant to say ? Please comment
Volume will change , it won’t be 2L. At 250s use V1/V2 = n1/n2. Get final volume and final concentration
Thank you , Sir
@@UANEETEnglishSir ,I still didn't get it.
Could you please provide me the solution?
🔥🔥🔥🔥🔥🔥
Lecture pdf sir
❤🎉
😅
But I got 0.83(100) sir
5:59:48
In denominator, it is not (1+2)
Correct (1+0.2)
%B=83.33%
%C=16.67%
Thank you thank you so very much sir❤🙏🏻
❤