Is there a way to record video ?? Poor students will get headaches and start hating math because of mistakes or typos mentioned..Please! Amen@@MathBeast.channel-l9i
Very simple, 6^x (36 -1) = 60 6^x = 60/35 = 12/7 Apply logerthms then find x value. xlog6 = log(12/7) We should know logerthm, log inverse values from 1 to 20 while preparing for such exams.
At 0:29 you write a^(m+n) = a^(m*n) which feels terribly wrong, also at 7:40. Luckily, you didn't use this, else you'd have gotten doomed. Am I totally wrong?
Something is wrong! a^(m+n) is not equal to a^(m•n); it is equal to a^m•a^n. The steps he wrote after are correct though
You are right....that is a typo.
I realized it now that was written mistakenly and I'm sorry for that 😔
Is there a way to record video ?? Poor students will get headaches and start hating math because of mistakes or typos mentioned..Please! Amen@@MathBeast.channel-l9i
@@MathBeast.channel-l9isorry re-record and delete video I meant
6^{x+x ➖ }+{2+2 ➖} ➖ 36 =6^{x^2+4} ➖ 36=6^2x^2 ➖ 36 36x^2 ➖ 36={1.24+1.124}=2.48 2.24^24 2.2^12^2^12 1.1^6^6 2^3^2^3 2^1^1^3 23 (x ➖ 3x+2).
O common!!! That can be much shorter!!!
Okay Boss 🙂
Very simple, 6^x (36 -1) = 60
6^x = 60/35 = 12/7
Apply logerthms then find x value.
xlog6 = log(12/7)
We should know logerthm, log inverse values from 1 to 20 while preparing for
such exams.
We can do with simple multiplications and divisions.
@@srinivasch-re2oq Alright Boss 🙂
At 0:29 you write a^(m+n) = a^(m*n) which feels terribly wrong, also at 7:40. Luckily, you didn't use this, else you'd have gotten doomed. Am I totally wrong?
No.
You are totally right Sir.
It's a typo.
Very sorry for that it was mistaken 😔
It's actually a^(m+n) = a^m × a^n
Why u increased unnecessary steps?
To explain well🙂
6^x(36-1)=60
6^x=12/7
x=(log12-log7)/log6
x=1+(log2-log7)/log6
x=1-(log7-log2)/log6