10th Class Physics Chapter 13 - Exercise Numerical no 13.1 to 13.4 - Class 10 Physics Chapter 4

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13.4 numerical can also be solved as
Data: F1= 0.1N
r1= 5cm or 0.05 m
And F2= ?
r2= 2 cm or 0.02 m
Now as charges are same so q1=q2=q is taken and value of K= 9*10^9 will be same
So as formula
F1=k*q*q/r1^2. And F2=k*q*q/r2^2
F1*r1^2=k*q^2...….I And F2*r2^2=k*q^2.......II
AS R.H.S of both equations I&II same so L.H.S aslo same
So by comparison I&II
F2*r2^2 = F1*r1^2
By putting values
F2*(.02)^2= 0.1* (0.05)^2
F2= 0.1*0.0025/0.0004
F2= 0.62N

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Numerical 13.3 mai Pehlay 8.889 ka square root lo to answer 2.9814 aye ga phir 10^ -13 ka Square root lain gay to 3.1622×10^ -7 aye ga phir in dono answers ko multiply krain gay to 9.42 × 10 ^ -7 a jay ga

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