Japanese | Can you solve this ? | A Nice Math Olympiad Problem

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[@minkyu0716]

It all depends on what the question is. Real numbers or all roots.

[@jonathanr520]

My answer: 3/2

[@ganapathip6129]

Hi

[@АлексейГолубев-п3ц]

А вот и нет. Уравнение третьей степени имеет три корня.

[@milankumar3785]

3/2 in two seconds. Take cube roots on both sides

[@ganapathip6129]

Nice

[@ganapathip6129]

Welldone

[@daniellerosalie2155]

That is what I did.

[@ManojKumar-e3h5c]

K^3 = 27/8 = k^3 = 3^3/2^3 = k^3 = (3/2)^3 = power 3 is cut = k = 3/2 is answer

[@ganapathip6129]

@@ManojKumar-e3h5c oh!

[@camlienphuocnguyen5739]

😮 is my face when i see how you solve it. K =3/2, in seconds

[@susanarendas]

Dude you did way too much work for a problem that takes two seconds.

[@rajeshvyas934]

1.5

[@ganapathip6129]

Hi

[@ГульнараБуркутова-ф9ю]

1,5

[@maximcaulfield5083]

Это только один из ответов. Очевидный

[@ganapathip6129]

@@ГульнараБуркутова-ф9ю nice

[@1234larry1]

Why not multiply the quadratic through by 4 to eliminate the fractions?

[@MryM70]

it is very simple : 3/2

[@ganapathip6129]

Yes

[@15thillizon]

3/2 ... simple

[@ari345n]

Bro why are you making this easier solution to much complex. I can guess the answer only seeing the question which are : 3/2; 3/2* omega; 3/2* omega^2.
Where omega=( -1+√3i)/2

[@ganapathip6129]

O!

[@pattithompsett9540]

this is why i make paint for a living

[@leepeeka]

Уравнение 3-й степени, значит должно быть 3 корня, один очевиден, а еще 2 комплексных. Хотя в школе такому не учат.

[@ganapathip6129]

Ok

[@АлексейГолубев-п3ц]

Хоть кто-то с мозгами нашёлся.

[@AbdurahimKarimov-xo4vs]

Осмелюсь внести поправку: уравнение 3-й степени имеет максимум 3 корня.

[@АлексейГолубев-п3ц]

@@AbdurahimKarimov-xo4vs строго говоря, всегда три, просто два или три могут совпадать.

[@范宏銘-g6w]

K=3/2

[@НатальяБерлизова-ц1с]

3/2 или 1,5

[@小瑋-p7y]

2／3

[@DelinaLeake]

You can do easily by doing cube root of 27/8=2/3 Why are using this method?

[@antoniosalvadorcotesgimenez]

Una ecuación de grado 3 tiene 3 soluciones. Usted y todos vemos la real de manera obvia. Se está centrando en calcular las raíces complejas.
En mi opinión sería más rápido resolver con la forma polar

[@lvn_11]

To find complex solutions i guess

[@drroullette1218]

Very easy. Why he is making it very long and difficult?

[@ganapathip6129]

We can find the other complex soln.

[@1234larry1]

Because according to the Fundamental Theorem of Algebra, when you have a leading term with a power of 3, you must have at least 3 solutions, some of which may be complex.