You totally save me. You know, you just use less than one hour to help me to figure out the materials which I need to spend several hours on by myself! Thank you so much!
1) Why the resistivity of the conductor is not zero at absolute zero temperature? 2) How 0.026meV energy is sufficient to for electron to cover the 1.1eV band gap of Si at room temperature?
Model is drawn incorrectly as a forward bias instead of reverse bias at 38:40 EDIT: THIS COMMENT IS WRONG, SEE BELOW RESPONSES Great lecture though thumbs up on video
Not really... If the semiconductor sample is of n-type , then the +ve terminal with the semiconductor and -ve terminal with the metal is the setup for REVERSED BIAS... And the vice versa is a FORWARD BIAS. The +ve charge appearing on the semiconductor part is after the electron transfer to form the depletion region!!!
@@snehashishbanerjee2575 You're absolutely right! I'm an idiot haha! I did get confused thinking the positive signs he wrote (the DEPLETION REGION) was meaning that the semiconductor was p-type.... thank you!
Hi buddy, Fermi level is always close to electron filled region. Here in metal side electron concentration is high after depletion region formed. So it goes higher to lower side with bending depends on e concentration.
Because the energy function of a material is always continuous. Now energy is just potential scaled by charge and we know that potential is integral of electric field with distance...and integrals are always continuous because they have to be differentiable.
+Memo “MekoxTwiSparkle” Pony In case you were still wondering, I think I can try my hand at explaining it. When a metal-semiconductor junction is formed, electrons flow from the semiconductor to the metal, filling states in the metal's conduction band in order to bring the Fermi energies to an equal level. He states that not only electrons on the surface of the semiconductor migrate to the metal, but some from the bulk of the semiconductor material as well. The depletion region is the region in the semiconductor from which electrons flow into the metal, and as you can see it is not limited to only the surface. Hope this helped, and if anyone spots an error please correct me.
Depletion means deficiency. Electrons move from one material to another so it leaves deficiency in number to its own side. Since no electron we call it holes or. Positive. Combination of this electron and positive holes region is called depletion region.
You totally save me. You know, you just use less than one hour to help me to figure out the materials which I need to spend several hours on by myself! Thank you so much!
This young professor really saved me today. well and understandable
Its an awesome video. One need patience to understand this
sir you delivered this topic in vey conceptual way,,,,,
Metal-Semiconductor @17:24
Thank you!
Thank you
👍
Nice class.Very useful, Thank you sir
Excellent explanation sir...
Nice lecture sir.. really useful..
very very conceptual sir,,,,,,,,,
thanks sir for well explained lecture
Awesome sir.
Very useful video
This video is very helpful...thank you sir
amazing one sir
1) Why the resistivity of the conductor is not zero at absolute zero temperature?
2) How 0.026meV energy is sufficient to for electron to cover the 1.1eV band gap of Si at room temperature?
Ans 2- due to the phenomenon of quantum tunneling where electrons can pass through a barrier more than the energy it has...
nice lecture.we got alot.plz aware us about ptype cases
metal metal junction is also having some junction potential ,so why metal metal junction is not acting as a rectifier.
It may be negligible ☺
Model is drawn incorrectly as a forward bias instead of reverse bias at 38:40
EDIT: THIS COMMENT IS WRONG, SEE BELOW RESPONSES
Great lecture though thumbs up on video
Not really...
If the semiconductor sample is of n-type , then the +ve terminal with the semiconductor and -ve terminal with the metal is the setup for REVERSED BIAS... And the vice versa is a FORWARD BIAS.
The +ve charge appearing on the semiconductor part is after the electron transfer to form the depletion region!!!
@@snehashishbanerjee2575 You're absolutely right! I'm an idiot haha! I did get confused thinking the positive signs he wrote (the DEPLETION REGION) was meaning that the semiconductor was p-type.... thank you!
@@sourcecreator2222 welcome sir!!! Have a nice day
It's a pity that when talking about this topic, they are never discussed the metal/p-type cases.
AcidoNO3 have you already found an example for metal/p type junction?
Because it's more confusing. Even to understand the positive charge or hole movement. That's why they go with electron movement.
Thank you Sir
Thanks too much
May connect with any student to ask him for help?
why do you shift vacuum-levels, they should be equal for all?
Thank you 🎖
Thank you so much!! It's so useful!
Thank you a lot Sir
Nice... however, then bending of the bands has not been explained. Why can't the bands simply fall down without having to bend?
bcs at contact point they remains at previous position.
Paivren Becoz the effect of field experienced by charge in semiconductor is only till bend portion.
Hi buddy, Fermi level is always close to electron filled region. Here in metal side electron concentration is high after depletion region formed. So it goes higher to lower side with bending depends on e concentration.
Because the energy function of a material is always continuous. Now energy is just potential scaled by charge and we know that potential is integral of electric field with distance...and integrals are always continuous because they have to be differentiable.
nice one
why contact potential oppose the motion of electrons?? plz ans
hi sir if its possible please provide notes based on your explaination ... thankyou
where can I find the links for previous lectures?
th-cam.com/video/G41t_0CqPzY/w-d-xo.html
thank uuu
so useful!
Sir why metallic band is not bending while the semiconductor band is bending????
Nice sir
Very good lectute , sir !
Can someone explain to me the depletion region?
+Memo “MekoxTwiSparkle” Pony In case you were still wondering, I think I can try my hand at explaining it. When a metal-semiconductor junction is formed, electrons flow from the semiconductor to the metal, filling states in the metal's conduction band in order to bring the Fermi energies to an equal level. He states that not only electrons on the surface of the semiconductor migrate to the metal, but some from the bulk of the semiconductor material as well. The depletion region is the region in the semiconductor from which electrons flow into the metal, and as you can see it is not limited to only the surface. Hope this helped, and if anyone spots an error please correct me.
Depletion means deficiency. Electrons move from one material to another so it leaves deficiency in number to its own side. Since no electron we call it holes or. Positive. Combination of this electron and positive holes region is called depletion region.
Ofcourse its indian!
Of course it had to be an ungrateful philippine!
Ok 👌👍👏
Nic