I bet your views rocketed this year due to online school. Personally, you just saved my life-I was so lost with maths. I sincerely thank you, your videos have surely had an immense effect on this year's students' competence on math. People like you genuinely have an effect on this world, especially during hard times like this. -Paljon kiitoksia! Greetings from Finland! 🇫🇮
@@MariosMathTutoring Happy to hear that! We take great pride in all the commodities we make and therefore everything produced here is manufactured with great precision, so I can assure you that the very jacket you've bought will last for decades! Merry xmas!
For Q2, I tried setting it up as a combination like you did in Q1. Does it make sense to combine C and P? 4C1* 4C1 / (52P2 since the order matters here King then Ace)
Thank you! The last problem that you explained is in my textbook but I couldn't understand how the author worked it out until I listened to you explain what (or) means in math and the 13 diamonds and 4 Kings. Thank you for making this video!
Can anyone explain why in the first problem we can't do something like 12/52 * 11/51 * 10/50 * 9/49 * 4/48 like how in question 2 it was 4/52 * 4/51? Aren't they both essentially just drawing cards from a deck?
I'm not really sure myself but I think it's because 12/52 * 11/51 * 10/50 * 9/49 * 4/48 is kind of restricting the order, and the problem didn't imply any specific order. The order in which you pick the 5 cards from the 52 cards doesn't matter, but in your denominator 52*51*50*49*48, the order does. ABCDE is not the same as ACBED. Same thing for the numerator. The order in which you pick the 4 face cards doesn't matter.
why you solve ist Q with combination approach can we solve other two Q with combination approach? or can we solve the Ist Q with direct approach as you did in 2nd and 3rd Q?
yeah but I follow only combination. how can we solve other two Q through combination I don't get the exact answer through combination unless divided by 2!
just to consider a different card example, what would be the probability of guessing the right three card combination in a game of clue. the game starts with a blind draw from 3 groups of cards (6 suspects, 6 weapons, and 9 rooms). i came up with 1/324 = 1/6 x1/6 x 1/9; but wanted to confirm. thanks.
Sorry Mario I have another question. “ there is a bag of marbles. 1/2 half of them are red, 1/4 of them are pink, and 5 of them are black. If you reach in and pick two marbles and the first one was red , what is the probability that the other one is also red? Thanks Mario and the answer i got was 47 percent chance. Can you please tell me how to work through this? And by the way I love your videos they are so helpful indeed.
Sir i really found this video prodigiously helpful, Although i have a request for you IF possible can you attach a PDF of some PRACTICE QUESTIONS for students regarding these topics for students to practice and hone their math skills even more?? (Only if you have time) Thank you for making maths easier
I was playing the card game "Old Maid" with family, and I started to wonder about probability in that game. You may already be familiar with the game, but I will describe it as I understand it. There were thirty six cards, and three players. (I'm leaving out finding "the old maid" card.) So, we each had twelve cards. The object was to see how many matches you can find. First, you go through your own dealt cards, pick out the matches that are already there, and put them aside. Then, you try to find matches to the remaining cards in your hand by picking a card, each time it is your turn, from your neighboring player. Of course, the other players are also adding and subtracting from their deck by picking cards from their neighbor, and putting aside any matches they find. At first, everyone has a lot of cards, so there seem to be a lot of possible choices. But, as each person gets down to only a few cards, it starts to seem less likely that you would find a match for your very few cards among the other players few cards that they are holding I'm not sure exactly what I am looking for as an answer. Perhaps it is, what is the probability each time you pick a neighbor's card you will get a match, and does that change as the amount of cards in each person's hand becomes fewer and fewer. Thanks for your time, and excellent videos. I mentioned last time I had a question that I am a semi-retired music teacher trying to learn more about math. Thank you!
mario i have a question with a spinner with 4 sector, but it says sector 1 has twice the area of sector 3 and if the arrow is spun once what will be the probablitiy that the arrow will land in sector 1. thanks
I guess we would need to know the area of the other 2 sectors...but Luke just remember the probability is the area of success divided by the total area and you got it.
Mario I have a question. My question says that “Bob selects a card from a standard 52 card deck . George selects from a separate deck. What is the probability that both picks a queen.” Thank you and can you’ll tell me the answer and how to work through it. I need this quick
Mario please help me in understanding this scenario. You take out 2 cards from the deck of 52 and don't look at them. You have a 2/52 chance of the Ace of Spades. You look at one and it's wrong but now the other card you have has a 1/51 chance instead of a 1/52 chance. This action causes the probability to be slightly better than the original 2/52 and it's really bugging me, lol.
+Klaus 74 the second card has a 1/51 chance but that is approximately .0196 whereas if you consider the original 2/52 that is a .0385 chance so you are right that if you don't draw the ace of spades on the first draw and then consider the probability of drawing the ace of spades on the second draw you are right that your chance is better but not better than the overall chance of drawing the ace of spades with the 2 cards drawn. Hope that helps...
Many hours after your reply it dawned on me that the first card that is flipped is revealed more often than the second one. So if the Ace of Spades has turned up 5 times in the first flip and 5 times in the second flip the higher probability of the second card is offset by the the fact that the first card was flipped 5 more times than the second because the second flip was unnecessary.
I think the answer is too small, or, better maybe, cannot be calculated. There are 52 cards, let's say 36 black balls (the numbers 2..10), 4 blue balls (aces) and 12 red balls (faces). Total is 52 which is ok. Now, we pick up 13 cards assuming 4 players play the game and all cards are in the game. (That's the point I miss in your story. How many players are there?) We calculate P(4 x red, 1 x blue and 8 x black). Which is: ((12 choose 4)*(4 choose 1)(36 choose 8))/(52 choose 13) = 0.09435
Alex watch this video I did...I think it will explain things for you: Permutations Combinations Factorials & Probability th-cam.com/video/TBnPkKxXPu8/w-d-xo.html
I shuffled a deck of cards and pulled the 7 of clubs, then i shuffled the deck again and got 7 of hearts, then i shuffled again and then got the 7 of clubs again. what are the chances of this happening with the number 7 being pulled 3 times in a row.
Mario I have a question. My question says that “Bob selects a card from a standard 52 card deck . George selects from a separate deck. What is the probability that both picks a queen.” Thank you and can you’ll tell me the answer and how to work through it
I recommend watching some of the probability videos in this playlist...then you should be better able to answer this one.... Probabilityth-cam.com/play/PLHRatQsym1_jlUrR1EeB1md7MJbAI93Ve.html
Also I’m stuck on some questions that say “ a hat contains marbles. 1/2 of them are red, 1/3 of the, are green and the rest are yellow. What is the probability of choosing a red marble and followed by another red marble?
@@graciemarshall2447 omg fr. I didnt pay attention in online class (im not good at it) and now i gotta rewatch all this shit or ill fail my first year in hs.
+Poonam Singh maybe this other video I did regarding probability and odds may be of some help to you th-cam.com/video/Vu4x2DKn12g/w-d-xo.html as well as these on permutations and combinations
It’s not really making any sense…The disguising factor of when to use the fraction approach for probability and when to use the combination approach where you 12C4*4C1/52C5 is not clear. Saying that there are baring approaches and sometimes it’s easier to use on over the other is a poor answer. Especially when the probability concept was introduced using fractions.
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It was great that you used & and Or in the same class. It is very confusing. Thank you
I bet your views rocketed this year due to online school. Personally, you just saved my life-I was so lost with maths. I sincerely thank you, your videos have surely had an immense effect on this year's students' competence on math. People like you genuinely have an effect on this world, especially during hard times like this.
-Paljon kiitoksia! Greetings from Finland! 🇫🇮
Thanks for your kind comment Ralf! Funny coincidence... I just bought a winter coat that was made in Finland and I really like it!
@@MariosMathTutoring Happy to hear that! We take great pride in all the commodities we make and therefore everything produced here is manufactured with great precision, so I can assure you that the very jacket you've bought will last for decades! Merry xmas!
although i don't understand the signs used in question 1, this 6 mins rlly help me. Thanks a trillion Sir Mario!!
Thanks for these lecture it helps me alot
Thanks. Thanks for the website suggestion.
This video really helped me.Thanks man!
Glad my probability video helped you Vaishnav!
Very nice concept
I was so confused when I was doing this in robotic class so thanks you for the help
For Q2, I tried setting it up as a combination like you did in Q1. Does it make sense to combine C and P?
4C1* 4C1 / (52P2 since the order matters here King then Ace)
Thank you
Thank you, thank you very much. 👍👍👍👍👍👍👍👍👍👍👍👍
Thank you so much!!!! You make it so easy!
I subbed too!
+SWOCHI your welcome. Glad the video helped make it easier.
+SWOCHI welcome to the group!
Thank you for making this simple, usually it's made difficult and confusing.
That helped me sooo much thx a lot🤗🤗👍🏼👍🏼
+Leela Mahadevswamy your welcome.
Maraming salamat po sir, ( means thank you) love from the Philippines 🇵🇭
You’re welcome Nicole!
Thank you for the slow, clear explanations. I was struggling big time watching other videos and not understanding it until I came across yours.
thank you so much!!!!
+Michael M your welcome!
Thanks, Mary for amazing explanation. I was bewilded about it!
Thank you! The last problem that you explained is in my textbook but I couldn't understand how the author worked it out until I listened to you explain what (or) means in math and the 13 diamonds and 4 Kings. Thank you for making this video!
+Hellokitty53 Taylor your welcome! Glad my video helped you!
Here I am in my middle age studying probability for fun.. strange times.. but thanks so much for your clear explanations!
based
Hi, is the first problem with replacement or without? I was assuming its without replacement
Thank you .Can you help me finding playlist for probability.
+Science Nature here is a probability playlist from my channel
th-cam.com/play/PLHRatQsym1_jlUrR1EeB1md7MJbAI93Ve.html
Thank you 😊
+Science Nature your welcome
Can anyone explain why in the first problem we can't do something like 12/52 * 11/51 * 10/50 * 9/49 * 4/48 like how in question 2 it was 4/52 * 4/51? Aren't they both essentially just drawing cards from a deck?
I'm not really sure myself but I think it's because 12/52 * 11/51 * 10/50 * 9/49 * 4/48 is kind of restricting the order, and the problem didn't imply any specific order. The order in which you pick the 5 cards from the 52 cards doesn't matter, but in your denominator 52*51*50*49*48, the order does. ABCDE is not the same as ACBED. Same thing for the numerator. The order in which you pick the 4 face cards doesn't matter.
Thanks this really helped me this is the first video in your channel and I subscribed
Welcome to the channel Fares! Glad my video helped you!
Thanku sir
+prateek setia your welcome.
thanks sir this helped me very much !! :)
+hardik behl your welcome! Glad it helped you!
why you solve ist Q with combination approach can we solve other two Q with combination approach? or can we solve the Ist Q with direct approach as you did in 2nd and 3rd Q?
Sometimes one method is easier to use than the other...
yeah but I follow only combination. how can we solve other two Q through combination I don't get the exact answer through combination unless divided by 2!
Pretty simple to understand Thanks!
Sir u helped me a lot in understanding probability of cards....thanks
Glad my video helped you!
@@MariosMathTutoring yup
Bien expliquer
just to consider a different card example, what would be the probability of guessing the right three card combination in a game of clue. the game starts with a blind draw from 3 groups of cards (6 suspects, 6 weapons, and 9 rooms). i came up with 1/324 = 1/6 x1/6 x 1/9; but wanted to confirm. thanks.
Sounds correct to me Finus!
@@MariosMathTutoring thanks much!
You’re welcome!
Can I get a hint on this problem?
Thank you so much👍👍👍👍👍👍I really understand it now THANKS!!!!!!!!!
Your welcome!
Thank You soo Much!! helped me a lot
+Shashank Khosla your welcome! Glad the video helped you.
Thanks so much! I just got the explanation that I needed that my statistics professor could not provide.
Glad my video helped you Lena!
Thank u sir
+Rashmi Prakash your welcome
What is the probability that i get a decent grade?
HAHAHHAHAH Here am i again on another exam and watch another video of marios math but its very helpfull thank you marios math🙂🙂🙂🙂🙂
Thanks this helped so much for my homework
You’re welcome Tiara!
I can use a deck of cards to track 1 out of 2 by using red/black. Suits can track 1out of 4. How can I use a 52 card deck to track 1 out of 3?
Watching this before my math exam wish me luck I’ll let you know how i did
How did u do? I have a quiz tomorrow
@@Itsreallyjustme i failed.
Awe sorry to hear that im afraid were going to be in the same boat I don't get any thing I probably watched 10 videos. What grade are you in?
Thank you sir its helping me a lot
You’re welcome Ayub! Glad my videos are helping you!
really really helpful!
Glad my video helped you!
Sorry Mario I have another question. “ there is a bag of marbles. 1/2 half of them are red, 1/4 of them are pink, and 5 of them are black. If you reach in and pick two marbles and the first one was red , what is the probability that the other one is also red? Thanks Mario and the answer i got was 47 percent chance. Can you please tell me how to work through this? And by the way I love your videos they are so helpful indeed.
Any help?
Lol did you find the answer XD
Thanks
+Usama Tahir your welcome
Thanks sir. Please keep it up.
You’re welcome Asad! Glad You like my videos!
eight cards are drawn from a standard deck of 52 cards. how many hands contain exactly 2 spades?
I got stuck in the first exercise when I was calculating the factorial. what is the final ansawer, please?
+Thiago Farias .0007618 or .07618%
Great, I got this answer, but as the result was too small I thought I had made some mistake. Thank you very much, I really appreciate
+Thiago Farias your welcome!
Sir i really found this video prodigiously helpful, Although i have a request for you IF possible can you attach a PDF of some PRACTICE QUESTIONS for students regarding these topics for students to practice and hone their math skills even more?? (Only if you have time)
Thank you for making maths easier
Glad you found the video helpful! Also thanks for the suggestion.
I was playing the card game "Old Maid" with family, and I started to wonder about probability in that game. You may already be familiar with the game, but I will describe it as I understand it. There were thirty six cards, and three players. (I'm leaving out finding "the old maid" card.) So, we each had twelve cards. The object was to see how many matches you can find. First, you go through your own dealt cards, pick out the matches that are already there, and put them aside. Then, you try to find matches to the remaining cards in your hand by picking a card, each time it is your turn, from your neighboring player. Of course, the other players are also adding and subtracting from their deck by picking cards from their neighbor, and putting aside any matches they find. At first, everyone has a lot of cards, so there seem to be a lot of possible choices. But, as each person gets down to only a few cards, it starts to seem less likely that you would find a match for your very few cards among the other players few cards that they are holding I'm not sure exactly what I am looking for as an answer. Perhaps it is, what is the probability each time you pick a neighbor's card you will get a match, and does that change as the amount of cards in each person's hand becomes fewer and fewer. Thanks for your time, and excellent videos. I mentioned last time I had a question that I am a semi-retired music teacher trying to learn more about math. Thank you!
You’re welcome! Glad you are enjoying my videos!
mario i have a question with a spinner with 4 sector, but it says sector 1 has twice the area of sector 3 and if the arrow is spun once what will be the probablitiy that the arrow will land in sector 1.
thanks
I guess we would need to know the area of the other 2 sectors...but Luke just remember the probability is the area of success divided by the total area and you got it.
Mario I have a question. My question says that “Bob selects a card from a standard 52 card deck . George selects from a separate deck. What is the probability that both picks a queen.” Thank you and can you’ll tell me the answer and how to work through it. I need this quick
0064less than 0.0064%
Mario please help me in understanding this scenario. You take out 2 cards from the deck of 52 and don't look at them. You have a 2/52 chance of the Ace of Spades. You look at one and it's wrong but now the other card you have has a 1/51 chance instead of a 1/52 chance. This action causes the probability to be slightly better than the original 2/52 and it's really bugging me, lol.
+Klaus 74 the second card has a 1/51 chance but that is approximately .0196 whereas if you consider the original 2/52 that is a .0385 chance so you are right that if you don't draw the ace of spades on the first draw and then consider the probability of drawing the ace of spades on the second draw you are right that your chance is better but not better than the overall chance of drawing the ace of spades with the 2 cards drawn. Hope that helps...
Mario you are ornament!! Thank-you!
For a while there I thought I wasn't playing with a full deck, so to speak.
Many hours after your reply it dawned on me that the first card that is flipped is revealed more often than the second one. So if the Ace of Spades has turned up 5 times in the first flip and 5 times in the second flip the higher probability of the second card is offset by the the fact that the first card was flipped 5 more times than the second because the second flip was unnecessary.
I think the answer is too small, or, better maybe, cannot be calculated.
There are 52 cards, let's say 36 black balls (the numbers 2..10), 4 blue balls (aces) and 12 red balls (faces). Total is 52 which is ok.
Now, we pick up 13 cards assuming 4 players play the game and all cards are in the game.
(That's the point I miss in your story. How many players are there?)
We calculate P(4 x red, 1 x blue and 8 x black).
Which is: ((12 choose 4)*(4 choose 1)(36 choose 8))/(52 choose 13) = 0.09435
sir What is combination and permulations
Alex watch this video I did...I think it will explain things for you: Permutations Combinations Factorials & Probability th-cam.com/video/TBnPkKxXPu8/w-d-xo.html
I shuffled a deck of cards and pulled the 7 of clubs, then i shuffled the deck again and got 7 of hearts, then i shuffled again and then got the 7 of clubs again. what are the chances of this happening with the number 7 being pulled 3 times in a row.
Mario I have a question. My question says that “Bob selects a card from a standard 52 card deck . George selects from a separate deck. What is the probability that both picks a queen.” Thank you and can you’ll tell me the answer and how to work through it
I recommend watching some of the probability videos in this playlist...then you should be better able to answer this one....
Probabilityth-cam.com/play/PLHRatQsym1_jlUrR1EeB1md7MJbAI93Ve.html
Mario the answer I got was 1/169 but I’m not sure if it’s right
Also I’m stuck on some questions that say “ a hat contains marbles. 1/2 of them are red, 1/3 of the, are green and the rest are yellow. What is the probability of choosing a red marble and followed by another red marble?
Yes that’s correct! You got it!
How to simplify tho?
where is the five coming from
i zoned out after he started saying "factorial"
lol gotta love how you finally understand one topic of math, then they go and change the hell out of it until it's practically another subject.....
@@graciemarshall2447 omg fr. I didnt pay attention in online class (im not good at it) and now i gotta rewatch all this shit or ill fail my first year in hs.
From india
Hello can someone answer my question
i can't understand it. plz help me
+Poonam Singh maybe this other video I did regarding probability and odds may be of some help to you th-cam.com/video/Vu4x2DKn12g/w-d-xo.html as well as these on permutations and combinations
I still don't get it
What?
I dont get it!! cant understand it bruh
Mood
Too complicated for me. Hard to understand. I need help😞
It’s not really making any sense…The disguising factor of when to use the fraction approach for probability and when to use the combination approach where you 12C4*4C1/52C5 is not clear. Saying that there are baring approaches and sometimes it’s easier to use on over the other is a poor answer. Especially when the probability concept was introduced using fractions.
Taklu
Thank you
Thank you
You’re welcome Benudhar!