Greetings Sir, i have been following your lectures which re very useful to me. May share my problem . .... i ve been asked to show from the kinetic theory of gases, that K=aCv where K is the thermal conductivity, Cv is the specific heat at constant volume and a is a coefficient of viscosity.
May someone explain what he is exactly trying to convey @3:51 regarding no terms in log of Fourier transform. I have run this several time but no able to understand. May some one explain how would the cumulants vanish. Thanks
d'kar First p(x_1, ... , x_n)=p_1(x_1)...p_n(x_n). When I do forier transform this one, p(k_1, ... , k_n)=p_1(k_1)...p_n(k_n) by independence. (Actually there exist tildes above every p) If I take logarithm, log p(k_1, ... , k_n)=log p_1(k_1)+...+ log p_n(k_n) Each p_i(i=1,...,n) generate cumulants, but there is no crossterm, so every cumulants that has different index vanish.
Oh. No wonder why this wasn't making sense. I'm trying to do chemistry and this is statistical mechanics xD. I'm doing Kinetic Molecular Theory, not Kinetic Theory of Gases xD. I got mixed up because my topic title is "Properties of Gases".
+Manu KUMAR SHARMA You can download these lectures from iTunes U (itunes.apple.com/us/itunes-u/id951892867) and the Internet Archive (archive.org/details/MIT8.333F13/). You could also use a 3rd party video downloader and download the video from TH-cam.
This one should be named Probability Part 3
《粒子的统计力学（共26讲）》
th-cam.com/play/PLUl4u3cNGP60gl3fdUTKRrt5t_GPx2sRg.html
第二章 概率
00:00 中心极限定理
14:34 大数规则
41:21 信息，熵和估计
thanks
It was the end of chapter two,not the beginning of chapter three.
exactly!! :(
Greetings Sir, i have been following your lectures which re very useful to me. May share my problem . .... i ve been asked to show from the kinetic theory of gases, that K=aCv where K is the thermal conductivity, Cv is the specific heat at constant volume and a is a coefficient of viscosity.
41:30 Shannon Entropy and information
39:36 1/N should be just N
May someone explain what he is exactly trying to convey @3:51 regarding no terms in log of Fourier transform. I have run this several time but no able to understand. May some one explain how would the cumulants vanish. Thanks
d'kar First p(x_1, ... , x_n)=p_1(x_1)...p_n(x_n).
When I do forier transform this one, p(k_1, ... , k_n)=p_1(k_1)...p_n(k_n) by independence. (Actually there exist tildes above every p)
If I take logarithm, log p(k_1, ... , k_n)=log p_1(k_1)+...+ log p_n(k_n)
Each p_i(i=1,...,n) generate cumulants, but there is no crossterm, so every cumulants that has different index vanish.
If you expand each p(x_i) and multiply together to get the product, you will get no cross terms like but only terms like .
7. Probability Part 3
good lectures, but the cameraman really should just keep the whole of one black board in view the whole time.
who is filming this omg
Oh. No wonder why this wasn't making sense. I'm trying to do chemistry and this is statistical mechanics xD. I'm doing Kinetic Molecular Theory, not Kinetic Theory of Gases xD. I got mixed up because my topic title is "Properties of Gases".
how can i get first 9 min. of this lecture
+Manu KUMAR SHARMA You can download these lectures from iTunes U (itunes.apple.com/us/itunes-u/id951892867) and the Internet Archive (archive.org/details/MIT8.333F13/). You could also use a 3rd party video downloader and download the video from TH-cam.
+MIT OpenCourseWare thanks,,,,
nice sir
This is a Graduate level Course
nice
PLEASE.. fire that cameraman!!!
Like 🙂
The lecture is perfect but I guess the camera guy got drunk.
He has Einstein like accent, if u agree, confirm with a like 👍