for f a nice method is plugging in the bound all but one include values less than 45, so sub it in , complete the square and you see the radius is negative.
Correct me if I'm wrong, but I think for part G, in the definition of the function, you replaced all the "x"s with "x - 1"s. Which is what we would do if the input changes from x to x - 1. However, since the input changes from x^2 to x^2 - 1, we can't do something like this. Also f(x^2 - 1) is an even function, hence the sketch can't be correct?
for f a nice method is plugging in the bound all but one include values less than 45, so sub it in , complete the square and you see the radius is negative.
For I, wouldn't x = 𝛑/4 also be a solution?
Correct me if I'm wrong, but I think for part G, in the definition of the function, you replaced all the "x"s with "x - 1"s. Which is what we would do if the input changes from x to x - 1. However, since the input changes from x^2 to x^2 - 1, we can't do something like this. Also f(x^2 - 1) is an even function, hence the sketch can't be correct?
thats wat im saying
why do you say in B that the shape drawn isn't a square?
I didn't say it wasn't a square, I said it was a rectangle
a square is a type of rectangle
@@sanjidahahmed1787 ALL squares are rectangles, not all rectangles are Squares