วีดีโอ

For the last question from 30:15 u cud just do the chain rule formula with 3 components altogether. Kinda makes it simpler for the last part 𝑑𝑣/𝑑𝑡 = (𝑑𝑣/𝑑𝑥) × (𝑑𝑥/𝑑𝑠) × (𝑑𝑠/𝑑𝑡) and u have already found all of these so just substitute them in

I did really bad on this one got silver in 2023 then bronze in 2024 now I got a participation award in 2025 after studying which is really demotivating.

Found out today I did best in my year and got gold! I even managed to qualify for the pink kangaroo! Only problem is now I have to prepare for more geometry 😭

isnt 0.6g on the far left for your diagram as it is on the bottom for the given diagram?

D1 crashout 😭😭🙏

Can you cover MAT 2024 long questions

can you recommend any D2 books that is part of A level and university Discrete mathematics?

My son did exam on 24th Jan in Thailand, but it’s not this paper! How come!😮

If you know Fermat's Little Theorem, then q21 is really obvious.

i live in hk and I sat for the UKMT Intermediate 2025 paper on the 24th of Jan and I dont remember doing this paper, wait what, something is wrong

Hi, thanks for the video! In Q1 when you said 17 was the largest number you could 'play with', wouldn't it actually be 11- as if you used 6 and 12 they both are LCMs of 3 and 2... Can you confirm this?

One of the easier ones in my opinion

Question 8 is abit baffling. How can the roots of a cubic be vertical, doesn't it always have to be cutting the x axis

can you do Volume scale factor for the last question?

33:37 q5 viii) you start from n=1 not 0 when picking 3, 7 and 11

fm1 fd1 is the best choice because the grade boundaries are low, if you can get ahead of the curve, easy a star.

Why is having two calculator papers bad?

Best TH-camr and obvious extremely talented mathematician

checked the grade boundaries for this... lowest out of all of them, with my choice, 3c3d (mech 1 d1) 220 for astar

himothy

thank you kind sir.

With question 4 part c, the mark scheme says that the vector vL must be a positive multiple of (477i -324j -45k), however in the video your answer is a negative multiple of this. Is this answer still correct, or is the direction relevant?

Great vid, reminds me of 3B1B's recnet vid on how sometimes turning problems into 3D actually makes them easier than in 2D (or accordingly for going into 4D from 3D!)

Are there more step 3 videos to be released?

in question 18 the person's name was Dick Turnip, and their horse was Slack Bess, idk if many noticed but there was a famous highway man in england a few hundred years ago called Dick TURPIN, and his horse was called Black Bess, i just found that interesting

🍫🍫🥧🥧🥧

thanks

Hi sir, can you also do the challenge questions of a level further pure maths? I would very much appreciate it 🙏🙏

absolute fucking legend

Thank u for this video its rlly helpful!! i hope to do well in my imc next week

Isn’t the 1st question the exact same question in the textbook?

never seen an education youtuber with as much sass and personality as you (its amazing)

Do you plan on going back over the MAT long questions that you didn’t do?

Thanks legend

thank you so much this saves my life

you said multiple of 4 when you should have said multiple of 3

THE ukmt imc is in 2 weeks we need you

Ur methods are so much easier wth, what’s all these crazy methods I’ve been learning in schl ://

8 can be done much faster by factoring out the x. 🙂

Right before the TMUA, thank yiu

watching a day to my tmua

Really do love your little ramblings between explaining things, makes it so much easier to keep focused rather than having someone continuously reciting maths/logic. Thanks a lot for the videos, they're very helpful for the TMUA 🙂

Question is quite funny considering it’s literally just like wordle. Anyone whos played the game would see the strategy immediately, i doubt a question like that would show up again

for q9 I thought the derivative of 1/x was ln(x)

oh man i was so gassed when i thought i got 12pi correct for the last one 😭

for q1, if you drew the circles out, you would've noticed that the line going through the intersections actually passes through the midpoint of the line connecting the centre of the circles and therefore you can find the gradient and midpoint of the line connecting both circles therefore find the equation for the other line.

Alternative approach to question 20: In the final expression, (a-3d)/2a = cos X, you can write the whole thing as (1/2) - (3d/2a). Since 3d>2a, 3d/2a will be greater than 1 if you divide both sides by 2a.( we know that a and d >0, so no problem with that). Thus, (1/2) - (3d/2a) can be written as (0.5)-(something bigger than 1), so cos(X)<0. X can't take any values from the first quadrant, and the only choice guarentees this condition is choice E.

Alternative approach to question 19: The x coordinate of the vertex is always equal to the artihmetic mean of the two roots(also meaning that the x coordinate of the vertex lies between the two roots) . So (p+q)/2 = (-b)/2 and we get p+q = -b (which is actually the result of the root sum formula, -b/a). And if we name the roots of the other inequality as a and b, we know that (a+b)/2= (-bc)/2. So (a+b)= -bc and we know that -b= (p+q). Finally we get a+b= cp + cq, so one of the roots is cp and the other one is cq. Since c<0 and q>p, cp is greater than cq. Thus, the answer is qc<x<pc.