@@energy-sapped6184 you can't get assigned a degree from TH-cam tho, although I have legitimately thought about just creating my own firm without a degree because if you own the business and know what you're doing, you don't need credentials for the job lol
My professor literall just told us that triangles are better than quadrilaterals for 30 minutes and than said that trig can be used to find little forces in the triangles. And that was it.
This is Amazing! I nearly cried in a 3.5-hour statics class when I couldn't get this topic. Searched TH-cam, got this video..... and in 19 minutes I got my aha moment! And it is free.... who beats that! Thank you, Jeff!
I've never seen an online tutorial for a difficult class laid out so plainly and easy to understand. There were no equations left out that I was expected to just know. I felt like I was kept in the loop of his thinking the ENTIRE time which is exactly what I need when I learn. So thank you Jeff. Absolute life saver
This guy helped me become the structural engineer I am today (3 years practicing), even passed with first class honours. Thanks again Sir, I owe you my skills I have today.
Appreciate all your time in creating quality videos. Going to be sitting for the PE exam this October. Nice to get brushed up on all the methods of solving problems.
my professor for statics is terrible. he changes policy left and right and his lectures are unclear and he does not break down problems properly. i have an exam on monday and i was freaking out, terribly. your videos are saving me and i am beginning to understand trusses now. i love you kind stranger, your videos are saving me. all love from a mechanical engineering student at georgia tech
Thank you so much. My statics teacher doesn't really teach us at all. I bought the teachers solution guide to teach myself from the solutions, but chapter 6 has been really hard for me to figure out on my own even with the guide. Your video's are so helpful.
Thanks so much. This really helped me understand where I was messing up with carrying the negative signs. I now understand that when you go to another joint you carry the magnitude but the positive or negative x,y component is relative to the x,y coordinate of the joint. So if a force is positive on one joint it could be negative on the same line of action at another joint.
Very helpful in breaking down the method. I went and watched the Solids: Lesson 2 traffic light video to better understand the portion during Joint B where he's naming the component vectors (4/5BD; 3/5BD vs. BDcos(53.13); BDsin(53.13). Great for architects studying for their PDD Exam! Thank you!
The method of joints is strongly analogous to node-voltage analysis in electronics; you can sort of think of the forces as "currents", and the joints as "nodes".
DR. Hanson ,thank you for a detail explanation of Trusses and the Method of Joints. Trusses and Joints also relies on past chapters for a solid solution.
Jeff I believe you got your angle at B incorrect at 11:03. That angle should be 53.13 degrees and the angle adjacent to the 4m side should be 36.87 degrees.
@@gaberillman6778 Welp, I survived the class. Thankfully I'm a Computer Engineer and not a Civil Engineer lol. Jeff and "Final Answer" (which is a TH-cam channel) are your only hope! Good luck buddy
@@deepwoodsengineering3763 Hey glad you survived the class man! And wait what were you doing taking Statics as a computer engineer?? Lol. And lol I’m actually a civil engineering major so I gotta know this stuff really well. And yeah thanks man! I’ve been using final answer a lot as well. I’m sure I’ll be okay but this stuff definitely isn’t easy. But having Jeff’s and the “Final Answer” videos do help a lot.
@@gaberillman6778 So for engineering degrees they usually make you overlap to other branches during your sophomore and freshman year. I think Universities want their engineers to be "well rounded" and have a taste of every branch
There is a mistake at the end when we are looking at joint C. Please help In the Y direction we have Fy = 0 = 11 (reaction force) - CDxSin45 = 11 - 0,7CD Therefore CD = 15.56 However Sin 45 = Cos 45 = 0.7 So in X direction we have Fx = 10 (BC) - CDxCos45 = 10 - 0,7 CD Which means CD = 14.28 There must be a mistake somewhere because if the angle is 45, which it is, BC and the 11kN reaction force must be equal. Can someone help me figure it out.
For static equilibrium, the sum of the moments around ANY point, will be zero. For accelerating bodies, it is more complicated, and IMO, you are asking for trouble if you pick a point other than the center of mass, or a fixed rotation axis. Your instinct might be to take moments about a pivot point, but you can really do it around any point that is convenient for you. It is strategic to take moments about a point that allows you to have as few unknowns as possible in the moment balance equation, so a point through where two unknown forces act is a good choice, rather than a point through which just one unknown force acts.
Evaluating the force along the x-axis will give the same answer. It will be as follows: ΣFx = 0 = -BC + (CD)Cos45° => BC = (CD)Cos45° => 11 = (CD)Cos45° => CD = 11/Cos45° => CD = 15.56 kN
Yes it's compressed so it pushes the joint , remember when he said it is a f.b.d of the joint not the member If it's the f.b.d of the member it would be the other side Hope i benefitted you
Jeff, I miss your old videos. You've simplified all your calculations so everything simplifies/cancels out. You actually used to do some tricky problems, but I get it. You had to remake all of these videos for McGraw Hill and I don't blame you for making your job easier. You're only second best to your original videos.
Visually, i dont see how a member in tension would pull on the joint. I can imagine the joint pushing back on the member which i guess is kind of the same thing? But the member pulling on the joint how?
you have been my lecturer for almost 2 years at this point. thanks a lot.
Pay for college, learn from youtube
Hello sir please i need a help
u can stop paying then, unless you unwillingly go to college
@@energy-sapped6184 you can't get assigned a degree from TH-cam tho, although I have legitimately thought about just creating my own firm without a degree because if you own the business and know what you're doing, you don't need credentials for the job lol
@@fosahromeo8322 Can I help?
Facts
This 19 minute video has taught me more about Trusses than my hour and a half class did. Thank you !!
Not really. There's a harder question or problem in MOJ
My professor literall just told us that triangles are better than quadrilaterals for 30 minutes and than said that trig can be used to find little forces in the triangles. And that was it.
I agree🥲
That's because you already had taken a look into the matter
facts
This is Amazing! I nearly cried in a 3.5-hour statics class when I couldn't get this topic. Searched TH-cam, got this video..... and in 19 minutes I got my aha moment! And it is free.... who beats that! Thank you, Jeff!
I've never seen an online tutorial for a difficult class laid out so plainly and easy to understand. There were no equations left out that I was expected to just know. I felt like I was kept in the loop of his thinking the ENTIRE time which is exactly what I need when I learn. So thank you Jeff. Absolute life saver
Who else has statics exams this morning ??
meee hahahahhaha
In 1 hour 💀
@glavnaya_mraz_YouTuba shit…
Unfortunately
In 3hrs
This guy helped me become the structural engineer I am today (3 years practicing), even passed with first class honours. Thanks again Sir, I owe you my skills I have today.
I love you mr Hanson ❤
A student from Iraq 🇮🇶 ❤️
i never knew swag and engineering can be in one dude hahaha anyways thanks a lot sir jeff youre the coolest
kaau
@@VMARIII hahaha hows engineering comrade?
@@jhydpumar3244 nahhh mas maau ang f2f kaysa online kay ang maestro tapulan d mo tudlo.
@@VMARIII kaayo, wala may ayo uban maestro ron uy
You're an absolute boss, Jeff. These videos are better for learning than the $300 textbook and the $1000 class I'm currently taking. Thank you!!!
I've not seen someone like this in my life.. May God reward u
I am become Engineer, practitioner of the Method of Joints. Thank you! This was super helpful!
Appreciate all your time in creating quality videos. Going to be sitting for the PE exam this October. Nice to get brushed up on all the methods of solving problems.
my professor for statics is terrible. he changes policy left and right and his lectures are unclear and he does not break down problems properly. i have an exam on monday and i was freaking out, terribly. your videos are saving me and i am beginning to understand trusses now. i love you kind stranger, your videos are saving me.
all love from a mechanical engineering student at georgia tech
Why would I use McGraw Hill when I have got Jeff Hanson....
Really?
@@abdulmoeiz2672 Tu yahan bhi punch gya XD
Muhammad Ali Shah Ha statics k paper sa pichlay din yaha he ana tha na lol
I honestly don't think i'd be passing this class without these videos. Thank you so much! When I graduate, I promise I will donate to this channel!
And... did you?
@@radolearn considering I posted that 4 days ago, its safe to say I haven't graduated yet
@@terrancepage9163 Sorry man, I misread the days as years XD
Am obsessed with woop voice fr
Tnx for showing it really helped me
Thank you so much. My statics teacher doesn't really teach us at all. I bought the teachers solution guide to teach myself from the solutions, but chapter 6 has been really hard for me to figure out on my own even with the guide. Your video's are so helpful.
This video finally gave me the "Aha!" moment that I so desperately needed! Thank you!
I never comment on videos, but thank you for saving me! This clears it all up.
Am I missing something? Isn't the angle @ joint B tan-1(4/3) = 53.13 degrees?
edit: ah, video clarifies this later. thank you.
hhhhh:)dude so do i
I remember this as angle opposite to 3 is 36.87°... I was like wait, did I forget sthg..
hahaha SAME
bruh i paused at this moment of the video and was starting to freak out I had forgotten trigonometry lmao
use cemal for user name bro :D
You're the GOAT of statics!
I feel like some dad "joint" joke opportunities were missed in this video
Thank you, sir! Your way of teaching is very helpful. I love how you taught us the steps in solving truss. It makes a difference now that i know it.
His videos are more helpful than what my teachers can ever give me
you just may be the best MAE professor I have ever come across.
you are a god for making these videos. unfortunately i still failed my exams tho
I passed static with 100 points. Thx teacher
yalan söyleme Tayfun 25 aldın
@@ozansen9724 kendi notunla karıştırmış olabilirsin 😊
@@tayfunerdogan8644 senin sınavını ben okudum tayfun kes sesini
@@ozansen9724 kafa gitmiş senin. Bı doktora görün.
Really u are so lucky , brilliant.😮
GLAD TO HAVE YOU SIR. ENGINEERING WOULD NOT BE EASY BUT FOR YOU!!
Thanks so much. This really helped me understand where I was messing up with carrying the negative signs. I now understand that when you go to another joint you carry the magnitude but the positive or negative x,y component is relative to the x,y coordinate of the joint. So if a force is positive on one joint it could be negative on the same line of action at another joint.
Perennial thanks to my beloved prof Jeff Hanson making truss analysis so simple and yet made me hooked to your lecture with rapt attention span
Very helpful in breaking down the method. I went and watched the Solids: Lesson 2 traffic light video to better understand the portion during Joint B where he's naming the component vectors (4/5BD; 3/5BD vs. BDcos(53.13); BDsin(53.13). Great for architects studying for their PDD Exam! Thank you!
I checked the other video you mentioned and didn't see him explain this, would you be able to tell me the time where this happens? Thanks!
this did help 😁thank you
these tiny notes between the calculations are gold for understanding
Bro I'm in a high school engineering program and I have my final coming up and trusses have been a struggle for me so thanks for this video!!
Much more enjoyable than my prof who went through the exact same problem, clearer and didn't take an entire hour out of my day.
The method of joints is strongly analogous to node-voltage analysis in electronics;
you can sort of think of the forces as "currents", and the joints as "nodes".
The videos are very good.I was out of these problems since 1986 when I was in the university.I refreshed very well. Thank you
Incredible video, hats off to you Mr. Hanson what a well explained step by step example. Please keep making more videos!
I was so stuck on the idea of compression and tension, thank you so much for clarifying that!
Wish I had this last year, but still great to reference. Thanks!
This video makes this concept so easy to understand, thank you!
Dr. Hanson, isn't the angle of (ABD) 53.13 degree tan^-1(4/3) ?
Oh never mind! =)
i agree
Agree
He correct himself
@@Behindthespheres so do I...
Dr Hanson I'm having trouble finding out how you arrived at 53.13°.
I tried using the cosine rule but just not getting it.
God bless you sir, I don't even know what to say, this clarified a lot for me.
Great content, very helpful.
Huge respect for you sir from uzbekistan. keep creating such amazing videos
D.r jeff Hanson is a God.....love from internationally
DR. Hanson ,thank you for a detail explanation of Trusses and the Method of Joints. Trusses and Joints also relies on past chapters for a solid solution.
Thanks men your lessons on truss did miracles for me in my exams 🙏🏾👍🏾
Confused on how the 5KN force was negative, but it was in the positive x-axis
THIS WAS THE PERFECT VIDEO INTIL THE 14TH MINUTE. TOO MANY SHORTCUTS FOR MY LEVEL
oh my god thank you for helping me out , I have a mechanics final on Monday 🥺
that's a nice session 💯only the part of arctan 4/3which made the calculation confusing
this video is just absoluetely legendary thanks so much for your help
Im so glad i’ve found ur channel
In a world of piss poor professors this man has so far carried me to my senior year in CET, thanks Professor 🙏
AT 11:05 tan-1(4/3)=53.1303 if am not wrong
He corrects it later on.
@@zunaidhassan9662 yeh bro but I was solving it with him step by step . 🙃
Yeah I was wondering too why he was wrong there
wow you have made my life easier Sir, thank you so much
Hey, at 11:13 where you mentioned that I can use tan to get the angle, why did we use 36.87 instead of 53.13? Arctan(4/3) is 53.13.
I got stuck there too and he later corrected it to 53.13°
And why must it be tan?
Sin and cos will also give the same 53.13°
Yeah, he corrected it later on. He used tan as it's opp/adj
May I ask sir why is it 11 N instead of -11 N? Cause if you sum up both negative sign it always ended with negative sign .?
Love and respect from 🇸🇦 💚💚💚💚💚💚
So happy that you got a sponsor!🙌🙌🙌
Just wanted to say thanks for an easy explanation in this video
Thank you very much sir. You are highly appreciated
awwwh I'm so happy Jeff got a sponsor
Wonderful Statics lessons!! really taking the time to explain the problems along with a good sense of humor :))
could you do a video on complex trusses.. when you have more than two unkowns at every joint (like 3 members at each joint)
fantastic presentation . bravo !!!!!
you just saved a life sir thank you, your video is indeed helpful .
thank you so much i have a quiz in an hour and this was perfect
Jeff I believe you got your angle at B incorrect at 11:03. That angle should be 53.13 degrees and the angle adjacent to the 4m side should be 36.87 degrees.
I'm very glad you caught it shortly after, no worries
absolute legend. thank you for the crazy amount of help.
@11:35 invtan of 4/3 is 53.13 degrees, no?
ah he corrects it
I would pay double tuition to have this guy as my professor for all of my engineering courses...
Anyone else here learning 4 chapters the day before the final?
how'd you do on the final bro? i'm here watching Jeff's videos on Trusses while my prof kinda sucks at teaching it lol
@@gaberillman6778 Welp, I survived the class. Thankfully I'm a Computer Engineer and not a Civil Engineer lol. Jeff and "Final Answer" (which is a TH-cam channel) are your only hope! Good luck buddy
@@deepwoodsengineering3763 Hey glad you survived the class man! And wait what were you doing taking Statics as a computer engineer?? Lol. And lol I’m actually a civil engineering major so I gotta know this stuff really well. And yeah thanks man! I’ve been using final answer a lot as well. I’m sure I’ll be okay but this stuff definitely isn’t easy. But having Jeff’s and the “Final Answer” videos do help a lot.
@@gaberillman6778 So for engineering degrees they usually make you overlap to other branches during your sophomore and freshman year. I think Universities want their engineers to be "well rounded" and have a taste of every branch
i would rather to watch this video rather than 2 hour lecture :)
Jeff out here single handedly graduating tons of engineers who struggle in their community college xD
Clear and straight to the point thank you!
on joint C why is the angle 45 degrees?
There is a mistake at the end when we are looking at joint C. Please help
In the Y direction we have Fy = 0 = 11 (reaction force) - CDxSin45 = 11 - 0,7CD
Therefore CD = 15.56
However Sin 45 = Cos 45 = 0.7
So in X direction we have Fx = 10 (BC) - CDxCos45 = 10 - 0,7 CD
Which means CD = 14.28
There must be a mistake somewhere because if the angle is 45, which it is, BC and the 11kN reaction force must be equal.
Can someone help me figure it out.
Thank u sir 🤩u helped me more than my original static teacher🤦♀️
Woah i was struggling to grasp this and u made it so easy
how do you choose the moment at A for calculations, can you do it anywhere? like moment at C?
At A easier because you have 2 unknowns so you will get rid of them
For static equilibrium, the sum of the moments around ANY point, will be zero.
For accelerating bodies, it is more complicated, and IMO, you are asking for trouble if you pick a point other than the center of mass, or a fixed rotation axis.
Your instinct might be to take moments about a pivot point, but you can really do it around any point that is convenient for you. It is strategic to take moments about a point that allows you to have as few unknowns as possible in the moment balance equation, so a point through where two unknown forces act is a good choice, rather than a point through which just one unknown force acts.
My professor's teaching style wasn't working for me but you made everything clear!
you have a fresh mind JEFF
You are an absolute legend!!!!
Thank you so much from Cambodia❤️
Absolutely amazing
Great Lesson!
Excellent 💖💖💖
Hope you describe graphic statics and all about funicular polygons
what is there no force for c in x direction?
Evaluating the force along the x-axis will give the same answer. It will be as follows:
ΣFx = 0 = -BC + (CD)Cos45°
=> BC = (CD)Cos45°
=> 11 = (CD)Cos45°
=> CD = 11/Cos45°
=> CD = 15.56 kN
Thanks. This helped me so much in my Theory of structures unit.
11:25 is a fail, but we get the gist (53.13°*) :)
He later corrected himself, don't worry :)
If it is a pin support, I thought there was no moment about it? Only x and y reactions. How come you use sum of moments if there is no moment?
if there are no forces going right how do you find ax
thanks, man, it helped me a lot.
17:06 why CD is going downward ? I mean isn't it compression in CD
Yes it's compressed so it pushes the joint , remember when he said it is a f.b.d of the joint not the member
If it's the f.b.d of the member it would be the other side
Hope i benefitted you
Jeff, I miss your old videos. You've simplified all your calculations so everything simplifies/cancels out. You actually used to do some tricky problems, but I get it. You had to remake all of these videos for McGraw Hill and I don't blame you for making your job easier. You're only second best to your original videos.
What do you mean he redid his videos?
You saved my life
So we start at Joint A because it has the least unknowns right?
Visually, i dont see how a member in tension would pull on the joint. I can imagine the joint pushing back on the member which i guess is kind of the same thing? But the member pulling on the joint how?