Use the same method as the item number 8 , then you will arrive at =Lim (x-> -3) (2x+22-16)/(x+3)[(sqrt 2x+22)+4] = Lim (x-> -3) (2x+6)/(x+3)[(sqrt 2x+22)+4] = Lim (x-> -3) 2(x+3) / (x+3)[(sqrt 2x+22)+4) Cancel (x+3) =Lim (x-> -3) 2/(sqrt2x+22)+4 Substitute now the value of x= -3, you will arrive at = 2/(sqrt 16) + 4 = 2/ (4+4) = 2/8 = 1/4
Use the same method as the item number 8 , then you will arrive at
=Lim (x-> -3)
(2x+22-16)/(x+3)[(sqrt 2x+22)+4]
= Lim (x-> -3)
(2x+6)/(x+3)[(sqrt 2x+22)+4]
= Lim (x-> -3)
2(x+3) / (x+3)[(sqrt 2x+22)+4)
Cancel (x+3)
=Lim (x-> -3)
2/(sqrt2x+22)+4
Substitute now the value of x= -3, you will arrive at
= 2/(sqrt 16) + 4
= 2/ (4+4)
= 2/8
= 1/4
How po nagkaroon ng -16?
@@rrennii -4*+4
ang galing magexplain si sir
Right after every new concept there's an example Ideal Boss
1/4, apply L' Hospital's Rule (Indeterminate Type 0/0)
pwede patingin po ng solution mo?
Hello engr. I was not able to answer the last number because I was confused if I will factor out the denominator or not. Hehe
Pasuggest po sana engr. Linear differential equation with constant coefficients
Already uploaded
1/4 Ans.🙂
1/4 po ang sagot Engr. ing calcu ko lang 😊
1/4
how did it become 1/4?
1/4...?
1/4 po
My final answer: 1/4
1/4
1/4
1/4