I've been doing this network thing for a while. This is by far the best explanation of subnetting I've seen. I'll be using this method to teach anyone that comes to me for help! Thank you so much! You should have at least 127 thank you's!!!
Very helpful. I have been confused and not able to successfully understand the process. I finally have a good understanding. I made notes detailed for a process using this video and it has helped so much.
Great Method !!! very easy to grasp! with this technique, I will be able to achieve subnetting in 30 seconds which is the goal our teacher gave us. I am very thankful for this video!! thumbs-up from me !!!!!!
to get the /26 number is super easy! each octet is 8 bits, the /x number is simply counting the number of bits turned on, if an octet is 255 its 8 bits. therefore 255.255.255.192 is /26. if you were to break 192 down into binary it is 1100 0000. protip - on class C subnets, just add your turned on bits in your last octet to 24. because 255.255.255.0 is 24
Can sumone plz solve this for me 1) You were given the address range 177.177.200.0, with subnet mask of 255.255.255.128 a) how many IPs are in the range? b) how many usuable IPs are there in the range? c) divide this range into 3 subranges with the first two ranges having 16 IPs. Calculate the following: - Subnet masks of the 3 subranges - Network and broadcast addresses of the 3 subranges
@mikeset116 I don't think what you are asking can be done. 177.177.200.0/25 = 177.177.200. 0 255.255.255.128. Therefore network ranges will be in multiples of 128. Range is 177.177.200.0 to 177.177.200.127. But remember you can't use Network or Broadcast address. 128 - 2 = 126 useable addresses. You can't subnet this in 3 equal ranges. You can subnet into 4 to get the 2 /28s which would give you 16 (14 useable) you are requesting.
Three years ago AwadRao asked why his computer on 173.32.2.62/27 couldn't ping his computer on 173.32.2.65/27. I went by the instructions in the video and this is what I came up with. 173.32.2.62/27 255.255.255.224 Subnet#1 173.32.2.0 Scope 173.32.2.1-173.32.2.30 Broadcast 173.32.2.31 Subnet#2 173.32.2.32 Scope 173.32.2.33-173.32.2.62 Broadcast 173.32.2.63 Subnet#3 173.32.2.64 Scope 173.32.2.65-173.32.2.94 Broadcast 173.32.2.95 Subnet#4 173.32.2.96 So the computer on 173.32.2.62 would be in Sybnet #2 and the computer on 173.32.2.65 would be on Subnet #3. So not being on the same Subnet they would have to go through a router to ping each other, even if they were plugged into the same switch. Why? Because switches are OSI Layer 2 and don't work with IP addresses. He would need a router at OSI layer 3 configured with a route table from Subnet# 2 to Subnet #3. Please correct me if I am wrong, I've only been studying for Network+ a couple weeks.
thanks alot of all the sub-netting video i manage to understand your way of teaching. could you come out with sub-netting of Class A and Class B. thank you sir..
Do you have any video in the works about how IPv6 is going to work and if/how it will be subnetted (if it requires subnetting at all)? I'm trying to get into the network field and i really would like to know how IPv6 works.
Wow!!!!!! You have done extremely well for me. All my doubts are clear about subnetting Class C addresses except for Class A and B. Please help me with the links to any of these Classes subnetting videos if you have. Thanks a million......
All the numbers are made up of octets (8), since he used 6 of the 8 octets, he subtracted 32 - 6, to get the /26. _ _ _ _ _ _ _ _ . _ _ _ _ _ _ _ _ . _ _ _ _ _ _ _ _ . _ _ _ _ _ _ _ _ (32 places in total) I know its 5 years too late, but I figured better late than never.
I still have something I can't get. My isp assigned address subnet mask is 255.255.255.0 by the rule of subnetting this means I can divide the last octet into subnets but my ISP gave me only 1 address so it's obvious I cant'make subnets. So why my mask isn't 255.255.255.255 instead?
Im not sure the Subnet mask is correct even if you go from right to left you need 50 subnets. In this case you will be borrowing 6 bits from the fourth octet if you go left to right you have 2 bits of available host so the value would be 11111100 = 252 the mask should be 255.255.255.252 Network should be 192.168.1.0 to 1-30 192.168.1.31 the next network id should be 192.168.1.32 .........
Can you help me to divide this n/w id 205.67.35.0 in 3 departments where the size is equal of each department using FLS(Fixed length subnetting) we have to determine the mask of each subnet the broadcast address and network address. Also the number of hosts in each subnet... Thanks in advance
Hi Akuma - You caught mistake in the video! Thank you for pointing it out :) The adding was incorrect, but this subnet only supports 62 total usable addresses as the last IP is for the broadcast address. The concept is still the same however for the explanation here. We know that we can support 50 hosts/ip addresses in the subnet.
wtf are you talking about? I did originally read the entire conversation. A classful class A network range is 1.0.0.1 - 126.255.255.254. 127.0.0.0 is reserved for looping back to your own network card.
I need to check this becuase the formula given here doesn't always work (is that or I dont get) So the system says that you should take the first IP given as the first subnet, well I tried to do that with 192.168.40.20/27 but guess whatm the red for this is not the same IP 192.168.40.20/27 as in the video, is 192.168.40.20/27 soooooo what is happening!!
Thanks for this video. Please subnet the following IP address and post the result. 173.32.2.62/27 or 255.255.255.224. Problem is 173.32.2.65/27 PC don't ping 173.32.2.62/27 Router after the following your method.
At last, someone who understands technology AND knows how to explain it in laymen's terms. Great job and thank you for posting!! Very helpful.
I've been doing this network thing for a while. This is by far the best explanation of subnetting I've seen. I'll be using this method to teach anyone that comes to me for help! Thank you so much! You should have at least 127 thank you's!!!
finally someone who says it simply, not flood it with technical crap like cisco does! thankyou sir!
From all of the "so-called" easy videos talking about subnetting, this is the best and easiest to digest one. cheers.
after 5 weeks subnetting cusco routers i finally learned a way to do it without a calculator and actually understood what this is all about. thanks
Very helpful. I have been confused and not able to successfully understand the process. I finally have a good understanding. I made notes detailed for a process using this video and it has helped so much.
Great tip about how to count the values grouped on the right. Love that!
As an IT manager who's a little rusty on networking, this is gold!
This is absolute gold!!! its made something so easy to take in, previous videos/ books just complicate the process unnecessarily 👍👍
Our tutor gave three 4 hour lectures on how to do this; thank you for saving us
Great Method !!! very easy to grasp! with this technique, I will be able to achieve subnetting in 30 seconds which is the goal our teacher gave us. I am very thankful for this video!! thumbs-up from me !!!!!!
Subtract one bit to find the closest value! This just saved me from constantly having to do the long math 1+2+4+8+16...
Thank you sir, I can not understand why several 4hrs classes couldn't accomplish what you just did in 10mins.
I appreciate the posting I'm studying for my ICDN1, math is not my strong suit but this video really makes it allot easier to grasp!
to get the /26 number is super easy! each octet is 8 bits, the /x number is simply counting the number of bits turned on, if an octet is 255 its 8 bits. therefore 255.255.255.192 is /26. if you were to break 192 down into binary it is 1100 0000. protip - on class C subnets, just add your turned on bits in your last octet to 24. because 255.255.255.0 is 24
Great simplification to the way I was taught subnetting. Great video series!
You're a genius!
Can sumone plz solve this for me
1) You were given the address range 177.177.200.0, with subnet mask of 255.255.255.128
a) how many IPs are in the range?
b) how many usuable IPs are there in the range?
c) divide this range into 3 subranges with the first two ranges having 16 IPs. Calculate the following:
- Subnet masks of the 3 subranges
- Network and broadcast addresses of the 3 subranges
u teach better then my networking teacher
excellent for my exam next week
Safiiiiiii
hahahahhaaa umeona eeh Mudzaby
Very well done!
@mikeset116
I don't think what you are asking can be done. 177.177.200.0/25 = 177.177.200. 0 255.255.255.128. Therefore network ranges will be in multiples of 128. Range is 177.177.200.0 to 177.177.200.127. But remember you can't use Network or Broadcast address. 128 - 2 = 126 useable addresses. You can't subnet this in 3 equal ranges. You can subnet into 4 to get the 2 /28s which would give you 16 (14 useable) you are requesting.
I would really like an expanded video that goes into class A and B addresses as well.
Three years ago AwadRao asked why his computer on 173.32.2.62/27 couldn't ping his computer on 173.32.2.65/27.
I went by the instructions in the video and this is what I came up with.
173.32.2.62/27
255.255.255.224
Subnet#1 173.32.2.0 Scope 173.32.2.1-173.32.2.30 Broadcast 173.32.2.31
Subnet#2 173.32.2.32 Scope 173.32.2.33-173.32.2.62 Broadcast 173.32.2.63
Subnet#3 173.32.2.64 Scope 173.32.2.65-173.32.2.94 Broadcast 173.32.2.95
Subnet#4 173.32.2.96
So the computer on 173.32.2.62 would be in Sybnet #2 and the computer on 173.32.2.65 would be on Subnet #3.
So not being on the same Subnet they would have to go through a router to ping each other, even if they were plugged into the same switch.
Why? Because switches are OSI Layer 2 and don't work with IP addresses.
He would need a router at OSI layer 3 configured with a route table from Subnet# 2 to Subnet #3.
Please correct me if I am wrong, I've only been studying for Network+ a couple weeks.
thanks alot of all the sub-netting video i manage to understand your way of teaching. could you come out with sub-netting of Class A and Class B. thank you sir..
Do you have any video in the works about how IPv6 is going to work and if/how it will be subnetted (if it requires subnetting at all)? I'm trying to get into the network field and i really would like to know how IPv6 works.
This is really helping me out! Thanks!
Anyone who understands this method, please do a class A and B version using this method.
WOW just an awesome explanation. Thanks so much!!!
Dude I finally get it THANK YOU!!!!
I'm only getting this 8 years later. haha you probably forgot it!
Thank you so much for these videos!
Bravo Bravo Bravo!
VERY Well Done!!! Thank you very much!!
You are the best!
Thanks for the tips. Thanks to your vid I got a 95 on my exam ;)
Why Cisco books make it so complicated?
thanks for the effective explanation.
super clear perfect
jacob im currently studying networking. can you guide me more often?
What about range 127? To determine which class it is in? You haven't mentioned that.
that is some good teaching right there! :)
Nicely Explained =D
sir, how do you get the /26?
brill vid
best vid about
thanks
Wow!!!!!! You have done extremely well for me. All my doubts are clear about subnetting Class C addresses except for Class A and B. Please help me with the links to any of these Classes subnetting videos if you have. Thanks a million......
My 7 year old self won’t believe he will learn this 14 years later
Can you illustrate an example using a Class B or A?
Thanks!! only video i found was to the point
Thank you. very helpful
Classful class A is 1.0.0.1 - 126.255.255.254. The whole 127.0.0.0 network is reserved for loopback, end of story.
I don't get it :/ were does the /26 come from?
Subnetting is the only thing I don't understand correctly..
All the numbers are made up of octets (8), since he used 6 of the 8 octets, he subtracted 32 - 6, to get the /26.
_ _ _ _ _ _ _ _ . _ _ _ _ _ _ _ _ . _ _ _ _ _ _ _ _ . _ _ _ _ _ _ _ _ (32 places in total)
I know its 5 years too late, but I figured better late than never.
@@jeff51305 lmfao
@@jeff51305 thanks, i need it now
thanks a lot man!
thanks b/c my German instruction is giving me the blues
Ok, wow! Thank you so much!
i still do not understand the slash thing at the end. Can you explain more where the 26 came from?
Yes - it is the number of bits in the subnet mask.
I still have something I can't get. My isp assigned address subnet mask is 255.255.255.0 by the rule of subnetting this means I can divide the last octet into subnets but my ISP gave me only 1 address so it's obvious I cant'make subnets. So why my mask isn't 255.255.255.255 instead?
Thanks !
Im not sure the Subnet mask is correct even if you go from right to left you need 50 subnets. In this case you will be borrowing 6 bits from the fourth octet if you go left to right you have 2 bits of available host so the value would be 11111100 = 252 the mask should be 255.255.255.252 Network should be 192.168.1.0 to 1-30 192.168.1.31 the next network id should be 192.168.1.32 .........
The problem ask for 1 subnet with 50 usable ip addresses,not 50 subnets.
Thank you
What happens when you subnet for thousands of hosts? What would subnet 20 be :)? I only understand subnet for very few hosts - under 254
as long as you find the block size the rest is EZ
@kenchi9999 .127 network is the loop back network. Google loopback and you can read about it.
@cpaloukas91 is there a reason why 127 of all the ranges reserved for local host...and what exactly do u mean by local host?
why does class A does not go up to 127? What is 127? Class A or Class B?
Why does his first subnet start with 172.16.20.0 instead of 172.16.20.20?
What happens when you need more than 128 hosts using this method? Say you need 240 hosts?
SWEET!
Can you help me to divide this n/w id 205.67.35.0 in 3 departments where the size is equal of each department using FLS(Fixed length subnetting) we have to determine the mask of each subnet the broadcast address and network address. Also the number of hosts in each subnet...
Thanks in advance
could you explain at 7:41 again... you counted 32 +16 = 48 then 48 + 8 +4 =60 then 60 + 2+1 = 63 you said 62. Did you subtract something?
Hi Akuma - You caught mistake in the video! Thank you for pointing it out :) The adding was incorrect, but this subnet only supports 62 total usable addresses as the last IP is for the broadcast address. The concept is still the same however for the explanation here. We know that we can support 50 hosts/ip addresses in the subnet.
Not sure why no one caught this...but i think your class A is incorrect..but shouldn't the Range be from 0 - 127 & not 0 - 126?
Watch part 2 of this video. It explains everything.
I Came thats good this was
127 is reserved.
@kenchi9999 127.0.0.0 - 127.255.255.255 is reserved for 'local host.'
wtf are you talking about? I did originally read the entire conversation. A classful class A network range is 1.0.0.1 - 126.255.255.254. 127.0.0.0 is reserved for looping back to your own network card.
thanks!
how is class A ranged between 0-126 and B 128 to 191? Where is the 127????
The entire range that begins with 127 is reserved for loopback.
I need to check this becuase the formula given here doesn't always work (is that or I dont get) So the system says that you should take the first IP given as the first subnet, well I tried to do that with 192.168.40.20/27 but guess whatm the red for this is not the same IP 192.168.40.20/27 as in the video, is 192.168.40.20/27 soooooo what is happening!!
hey could u show how to do this?
172.16.20.20/20 for 885 host and 55 host
how do you find the broadcast using this method?
Broadcast is always the last IP address in the subnet.
Jacob Hess thank you I knew that . I was asking can he so a video of how to get the broadcast
I love you!
audio version of TLDR
Classless ftw.
6INFO ftw!
@kenchi9999 bcuz 127.0.0.0 is the loopback address. google it
I wonder if the world would be better or worse if we started teaching math in base 2 instead of base 10....
I love you too!
128 64 32 16 8 4 2 1 The key for subnetting!!
does this work with class B
Yes, you can check out part 3 of the series for Class B.
Tyyyy
Thanks for this video. Please subnet the following IP address and post the result.
173.32.2.62/27 or 255.255.255.224. Problem is 173.32.2.65/27 PC don't ping 173.32.2.62/27 Router after the following your method.
@DougInAlabama this was so good i came
i dont get the fucking subnets. max number of subnets on a /22 net. max subnets should be 2^14, but how do i get those 14 ????
Am I the only one who can hardly hear this presentation?
@Webon39 cisco
I completely don't understand...
blame yourself.
im going to stick to programming...
Poor voice. Does not seems confident. See how confidently Jacob Hess speaks. Why so many pauses???
The closed captioning is badly garbled. This will be useless to the hearing impaired.