Command Line Arguments - CS50 Shorts

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CS50 SHOP
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Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International Public License
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David J. Malan
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[@chihab37]

that pause at 1:24 was so intense he looked straight in my soul and made me reconsider my whole life, questioning my beliefs and values..

[@fakrulotaku5655]

Bruh 😂😂

[@DesislavaDicheva]

I love the Harvard tutorials. That's why they have the best professors and gradates. They explain everything very simple and detailed. Great job! Thank you!

[@TheElhombremacho]

1:27 “it’s an array” the line is so well delivered

[@WicCaesar]

It's an arRAY! ♥__♥

[@bikdigdaddy]

the deathstare was legit

[@hayleybarbara1589]

​@@bikdigdaddyand in that moment, Doug stared into my soul.

[@李海君-j1c]

1:24 , i was scared for a moment, haha.

[@rashaadgibbs2759]

lol me too

[@maxim5519]

Command Line Arguments scare me much more...

[@delfimassa7645]

Does anyone else jump every time with the music at the beginning? lol For some reason youtube is always way louder than spotify in my computer

[@AfzalAlis]

had to replace my eardrums after that 🔊🔊🔊

[@nblsilent]

I simply hate this intro.

[@maxim5519]

@@nblsilent

[@bigbucksbuzz]

This would have been nice to know for the credit problem.

[@kaviyas4762]

Thank you!

[@shoppingvlogs1555]

Super but show us with an example Plz

[@RajanKumar-yy9pj]

Perfect

[@cagatayerdogru628]

great explanation

[@kornmc]

simple and detailed!

[@thibdeved]

If 'argv' is an array of string, in the example at the end of the video, argv[3] shouldn't be the character NULL (\0) ? We saw in the lecture Null is always the last element of the array to a string array

[@badrmahmoud4437]

Null is the last element of a string not any other array. That’s because any other array already has a size.

[@maxim5519]

@@badrmahmoud4437 ok, But in this video Doug said that argv - argument vector is just one more name of array, equal to array.
It means that: string argv[ ] in the end must have \0.

[@freerights6695]

@@maxim5519 no. the \0 is used for strings, not arrays of strings. That means that argv's last element will be a string, not \0. However, the string elements themselves will end with \0.

[@alimaher1]

@@freerights6695 same thought came into my mind. thanks for the explanation.

[@AlanMars]

Why would the compiler even let you go beyond the bounds of the array?

[@carlosvalle9868]

Thank you

[@seanlee566]

0:38 doesn't Doug mean before runtime? Doesn't runtime mean the time the program is running?

[@gardenvariety-]

what is reference 50?

[@nadiarusiecki5785]

I thought argv[3] would be null

[@fokkenhotz]

obviously you're not going to show us twice so to get it we will have to look back. Y? bcoz the flipping screen keeps flipping away when you ask if we "SEE" something check that!

[@rojinphilip2909]

Next: th-cam.com/video/vK_naJkrtjc/w-d-xo.htmlautoplay=1&rel=0