How to Solve Advanced Inbreeding Problems

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  • เผยแพร่เมื่อ 22 ม.ค. 2025

ความคิดเห็น • 16

  • @justinbasinger7728
    @justinbasinger7728 5 หลายเดือนก่อน

    I tried the loop method here and it worked out to the same number, are there cases where the loop method will not work? Does it so happen that any node's COI can be calculated from it's parents, then used to calculate it's children?

    • @GeneticsLessons
      @GeneticsLessons  5 หลายเดือนก่อน +1

      Correct.

    • @justinbasinger7728
      @justinbasinger7728 5 หลายเดือนก่อน

      @@GeneticsLessons Thanks for the quick reply! So the loop method works on all cases? I'm trying to think of silly inbreeding cases where it fails.

  • @pauljulius7615
    @pauljulius7615 3 ปีที่แล้ว +1

    Wow! Very amazing

  • @chakani0001
    @chakani0001 6 ปีที่แล้ว

    At 15:38 you count "first, second, third, fifth..." Did you skip fourth?

    • @GeneticsLessons
      @GeneticsLessons  ปีที่แล้ว

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  • @TheForrest1996
    @TheForrest1996 4 ปีที่แล้ว +1

    Thank you! Great videos :)

  • @claricegarcia7889
    @claricegarcia7889 4 ปีที่แล้ว

    Why did you use the coefficient 6.25%?

    • @GeneticsLessons
      @GeneticsLessons  ปีที่แล้ว

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  • @pinkybacay
    @pinkybacay 2 ปีที่แล้ว +1

    i do understand your formula, better than my prof. haha...thank u

    • @GeneticsLessons
      @GeneticsLessons  2 ปีที่แล้ว

      Happy to help!

    • @GeneticsLessons
      @GeneticsLessons  2 ปีที่แล้ว

      I have many more problems about inbreeding - check the "inbreeding" playlist on my channel.

  • @hossana842
    @hossana842 5 ปีที่แล้ว

    Hey Nikolay why are you doing (1/2)to the power of 5, instead of to the power of 6? Because you were counting the paths instead of the parents in your previous books. and I thing counting the paths is the correct one implemented in many books.

    • @GeneticsLessons
      @GeneticsLessons  5 ปีที่แล้ว

      You can count passes or nodes - there are two approaches - I show them both in a different videos, both ways are correct.