This question has been bugging me for an hour and I can't believe it was so simple. I was making it so much harder than it needed to be. Bless this page!!
In Figure a uniform beam with a weight of 60 N and a length of 3.2m is hinged at its lower end, and a horizontal force F of magnitude 50 N acts at its upper end. The beam is held vertical by a cable that makes angle ? = 25° with the ground and is attached to the beam at height h = 2.0 m. What are? (a) The tension in the cable and (b) The force on the beam from the hinge in unit-vector notation?
When doing torques of the beam, you must use the perpendicular component of the forces to the surface then multiply it by the distance from the point of rotation. This perpendicular part comes from the definition of torque being the cross product of the position vector and force.
sir i still don"t understand how the two angles equal each other and also why not Lsin120 but Lsin60 because as usual the T=f*L*sin theta(the angle btw the force and perpendicular force
This question has been bugging me for an hour and I can't believe it was so simple. I was making it so much harder than it needed to be. Bless this page!!
Lucky you, just an hour, mine was since yesterday.
Such an underrated channel for physics. Blows my mind
yeah he actually shows how to do these questions in a short amount of time unlike other ones
amazing explanation (=
I had try it and it work correctly .
+zezoow alketbi Thank you for the compliment!
Thanks. Realized my mistake right away, I forgot to account for the vertical component of the hinge force!! I have a final tomorrow lol.
how was it?
@@washingtonsibusisosanga2087 It went pretty well, thanks for asking
@@Zephyr-tg9hu thats great!!!! congratulations!!
In Figure a uniform beam with a weight of 60 N and a length of 3.2m is hinged at its lower end, and a horizontal force F of magnitude 50 N acts at its upper end. The beam is held vertical by a cable that makes angle ? = 25° with the ground and is attached to the beam at height h = 2.0 m. What are? (a) The tension in the cable and (b) The force on the beam from the hinge in unit-vector notation?
u are a fucking legend wny.
When he finds Vertical Force of the hinge, why isn't the weight halved again? like how he did when finding the tension of the wire.
thank you!
great video!, curious though. How come we use sin60 for the W*(L/2)sin60 and sin30 for T*L*sin30. Thank you
When doing torques of the beam, you must use the perpendicular component of the forces to the surface then multiply it by the distance from the point of rotation. This perpendicular part comes from the definition of torque being the cross product of the position vector and force.
How do you know the weight causes it to move CW?
you rotate clockwise but why is it negative tho????? it should be positive
i was baffled too but that's how it works, its in relation to the XY plane plotting that mathematicians use.
This question is from which book ?
this is wrong if you work with different angles.
sir i still don"t understand how the two angles equal each other and also why not Lsin120 but Lsin60 because as usual the T=f*L*sin theta(the angle btw the force and perpendicular force
sin120 and sin60 are the same
love you :**
+Abdullah altamimi Oh . . .thank you!