A Very Nice Algebra Problem | Fill in the boxes

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[@davidellis1929]

You can solve the problem with a single variable x representing the lower left box. The upper left box equals 8-x and the lower right box equals x-5. Then the upper right box can be expressed as both 21/(8-x) and 9/(x-5). Equating these two values yields x = 5.9, with the other three boxes equal to 2.1, 0.9 and 10.

[@rosamariavercelloni1719]

Brilhante !

[@greninjamariokartpokemonfan]

A×B=21, C-D=5, A+C=8, B×D=9
(A+C)-(C-D)=8-5
A+C-C+D=3
A+D=3
A=21/B, D=9/B
30/B=3
3B=30
B=10, A=2.1, D=0.9, C=5.9

[@josefsezbrisko9064]

English :
It is simply a system of 4 equations with 4 unknowns.
There are several methods to solve such a system. The simplest is the elimination method.
And perhaps the simplest solution would be to use a spreadsheet calculator. There, you only enter the constants and the solution is in a few seconds.
Czech :
Je to prostě soustava 4 rovnic o čtyřech neznámých.
Metod jak takovou soustavu řešit je několik. Nejjednodušší je vylučovací metoda.
A snad úplně nejjednodušeji by to šlo řešit pomocí tabulkového kalkulátoru. Tam se pouze zadají konstanty a řešení je v několika vteřinách.

[@MrJacks13]

How do you derive to calculating (iii)-(ii)? Why not e.g. (i)+(iv)?

[@すぴか-z1q]

teacher! The number “9” written by the teacher only looks like a lowercase “g”!

[@МишаВасинев]

Incredible!

[@عبدالواسع-س8م]

Excellent.
Thanks so much.

[@lironne882]

що, не побачили в кінці помилку?

[@abbasmasum1633]

"d" must be negative. I used d as negative and it worked, but different result and worked.

[@DanieleBarettin]

Nice presentation. But you need to be more specific: integer, rational...

[@YardenVokerol]

a ↓ 8-a → 3-a ↑ 9/(3-a)
a → 21/a
21/a=9/(3-a), 7(3-a)=3a, 21=10a, a=2.1
(2.1 10)
(5.9 0.9)

[@TBUGRATUIT-dm2vc]

+a×b-c=43
4+8-6+4=10
-d+e×f=15
1×4×8=32
a-8×d=-18
b+e=14
c+f=2

[@onuncukoy3404]

empty works..

[@andryvokubadra2644]

21 = 1*21, 3*7, 7*3, 21*1
9 = 1*9, 3*3, 9*1
But no one equal x + y = 8 or x - z = 5
So the roots ≠ Z 😅😅😅

[@jamesharmon4994]

Nothing said it had to be integers.

[@andryvokubadra2644]

@@jamesharmon4994 yes, But I proof that the root(s) aren't intenger 😊😊😊

[@jamesharmon4994]

@@andryvokubadra2644 oh, ok. I knew that before watching the video. LOL

[@ゆみ-p8b4u]

very easy.

[@abba5512]

So fun

[@freddyalvaradamaranon304]

Muchas gracias por compartir tan interesante video 😊😊. Realmente un sistema de ecuaciones con 4 incógnitas muy bien desarrollado y explicado.❤😊❤

[@olympiadeduworks]

great

[@nicatare2257]

3×3=9
9

[@AbdelaKadir]

Very simple every body