I really do not understand in the beginning of the proof when you say: “if p divides the order of any smaller group…”. Smaller than what? G has order smaller than what? Than p it cannot be because p cannot divide a number smaller than itself… I’m confused about this phrase. Could you please clarify?
This is such a fun approach to group theory -- great balance between theory and examples.
I really do not understand in the beginning of the proof when you say: “if p divides the order of any smaller group…”. Smaller than what? G has order smaller than what? Than p it cannot be because p cannot divide a number smaller than itself… I’m confused about this phrase. Could you please clarify?
Since he is using induction on the order of n, he must assume that the statement holds true for groups of order less than n.
why do we know that we can pick this element q of some prime order?
if you suppose an element a has composite order qc then a^c has order q.
@@98danielray thanx.
You never explicitly state the base of induction...
I noticed that too. The smallest group whose order is divisible by p has order p and is therefore cyclic, so by definition has an element of order p.
complete induction does not need a base case.😀