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Good solution, thank you.
Very satisfying problem
🎉😊
Sdh lah rumus sek yg lm tulis
X=1/3
(x⁷+x⁵+x³)/(x⁶+x⁵+x⁴)=81/27(x≠0, both divide by x⁵)(x²+1/x²+1)/(x+1/x+1)=3Let x+1/x=t, x²+1/x²=(x+1/x)²-2=t²-2(t²-2+1)/(t+1)=3(t²-1)/(t+1)=3(t+1)(t-1)/(t+1)=3t-1=3t=4x+1/x=4x²-4x+1=0x²-4x+4-3=0(x-2)²-3=0x-2=±√3x=2±√3
Good solution, thank you.
Very satisfying problem
🎉😊
Sdh lah rumus sek yg lm tulis
X=1/3
(x⁷+x⁵+x³)/(x⁶+x⁵+x⁴)=81/27
(x≠0, both divide by x⁵)
(x²+1/x²+1)/(x+1/x+1)=3
Let x+1/x=t, x²+1/x²=(x+1/x)²-2=t²-2
(t²-2+1)/(t+1)=3
(t²-1)/(t+1)=3
(t+1)(t-1)/(t+1)=3
t-1=3
t=4
x+1/x=4
x²-4x+1=0
x²-4x+4-3=0
(x-2)²-3=0
x-2=±√3
x=2±√3