I honestly cannot believe that there aren’t hundreds of colleges and universities having a bidding war on Prof. Leonard’s salary in order to secure him as a mathematics professor for their institution right now. This man is an invaluable gift to all learners of mathematics.
As someone else has said, almost all universities/colleges don't give a flying fk about the quality of teaching. They don't. It's not even in their awareness. I did a degree from 18-22, then went back 20yrs later, so I had more maturity and perspective. And I realized how indifferent the "system" really is.
You are singlehandedly the greatest champion of explaining difficult math to the average human being. Thank you so much for existing and doing the things you do.
I liked the video because you went through the nitty' gritty' of the math. I am the kind of person who needs to know who, what, where, when, and why when it comes to math. Thank YOU!
Professor Leonard treats math like a language, teaches you how to speak it, and how to use it. An attribute that is paramount for any professor, but sadly an attribute that most lack.
Great video! Great job! Logistic equation is a hardcore thing indeed. Much more difficult than one may guess, especially when it comes to the general case. This should be the best explanation on the topic I have ever seen so far. However, I must notice there is a sort of EXPLANATORY MISTAKE where it comes to 'explosion/extinct' version of the model at 59:30. No formal mistakes are though. Part 1. Dynamics analysis. Let's look at the equation dP/dt = k*P*(P-M), where k>0 and M>0. We can identify 3 cases. 1) If current value P>M (for instance, as P0>M), then factor (P-M)>0 and the right-hand side (RHS) of the equation gives us dP/dt>0. It means that P(t)->+inf. 2) If current value 0M, but tau0 is region of interest, this issue stays in the shade.
Thank you very much, Sir I (almost) finished them all. They were really helpful. I really appreciate your time and effort to make this possible. Again, thanks.
You guys I have noticed someting off about the explosion condition. It does explode when p0 > m but only at a specific point in the futrue when mtk=ln(P0/m) which gives us zero in the denominator and in return either plus or minus infinity depending if you are approaching the point from the left which gives us plus infinity i.e. the explosion we are talking about. However, if you move a tiny bit in the future you get minus infinity and after a little while it reaches zero and stays there. It was pretty confusing to me at the beginning and needed to spend some time to get it right.
Sir your videos are amazingly helpful, after watching your videos I feel more confident with topics related to differential equations.. Kindly consider partial differential equations next. Thank-you.
1:00:00 if the second term in the denominator is getting larger and larger and we subtract it from Po, wouldn't that mean the denominator approaches negative infinity and therefore P(t) -> 0? The conclusion of P(t) -> infinity makes more sense if the second term in the denominator approaches Po such that the denominator gets smaller and smaller and therefore P(t) larger and larger. Not sure if that is what was meant here.
Sir I think there is a mistake around 58:43. Isn't the limit of P(t) in this case going to be 0, no matter the starting condition? For M>Po, the equation is a scaled version of: P=1/(1-e^t) And for M infinity is 0. Perhaps I have made a mistake?
I notice this also. Even though case 2 where Po>M is suppose to be called explosion but the limit of the resulting function as t approaches infinity would go to zero from the negative P value.
The one in case 2 where Po< M is just alright since it's called extinction and the limit should go to zero as t approaches infinity. The function is decreasing to zero
Yes, I'm confused about this, as well. For an initial population P0 > M, we have (P0 - M)e^kMt = P0 - M < P0, but eventually (P0 - M)e^kMt reaches and surpasses the initial value P0. Furthermore, as (P0 - M)e^kMt < P0 approaches the initial value P0, the denominator tends to zero, and we should therefore have population explosion. We then approach a _bifurcation_ point at time t* such that (P0 - M)e^kMt* = P0, and then for all subsequent points in time t' > t*, we should have a negative population size.
At 20:10 How can B-sub1 be considered a constant, if it inversely varies with the population in a linear fashion? Dr. L doesn't explain this. Then he makes the great leap to the Logistic Equation. A little explanation here would go a long way!!!
If you had been my professor I may have learned something in dif eq. Though I seem to know more than I thought, this was still good to go over. I know in chemistry reactions can reach an equilibria, is this not a term used for your first case?
At the very end when youre explaining how when P > M, P(t) → infinity.... I dont understand how the fraction is shrinking but not going negative. What we have essentially in the denominator is P - (P - M)e^t - so as t increases, e^t is sharply increasing. And P - M is positive since P > M. And no matter how small a positive a value P - M is, since it is being multiplied by an exponential function increasing without bound, its overall value is quickly rising. Then we are subtracting that value from P....so would that not result in a negative number? Some value minus (some value minus a smaller value) times a huge value. For example 10 - (10 - 3)100000 = 10 - (7)100000 = negative. Im sure I am missing something but I was struggling to understand what
Great presentation, BTW. I'm using Boyce and Diprima and learning on my own. It's a tonne of fun, but your presentation is really useful. I'm definitely going to check out your ODE play list. It will be really good reinforcement of what I've read in the text. Thanks for all of this, it's clearly a lot of work.
@Allan 112358 I'm using windows 10 with python. Specifically the anaconda python distribution and I'm doing my coding in Jupyter labs/notebooks. I'm doing a lot of the coding by hand to learn in better detail how to numerically solves systems of ODEs and the various numerical methods that can be used to do that (Fwd/bkwd Euler, Runge/Kutta, Adams-Bashforth, etc). That said, there are some really excellent python packages that will do this sort of thing for you: scipy, sympy, gekko have solves, and numpy is a great support library that is generally useful. For plotting/visualizing results I just use mathplotlib, the python standard. All of this is free, btw, which is an added bonus.
So in the very last bit about the threshold, you basically get an infinitely large population in a finite time... if the denominator were to go negative (after t hits the value at which Po - (Po - M)*e^(mkt) < 0) then the population would suddenly switch to being negative, which makes no physical sense whatsoever. Am I reading that right?
I notice this also. Even though case 2 where Po>M is suppose to be called explosion but the limit of the resulting function as t approaches infinity would go to zero from the negative P value.
The one in case 2 where Po< M is just alright since it's called extinction and the limit should go to zero as t approaches infinity. The function is decreasing to zero
Yes, I'm confused about this, as well. For an initial population P0 > M, we have (P0 - M)e^kMt = P0 - M < P0, but eventually (P0 - M)e^kMt reaches and surpasses the initial value P0. Furthermore, as (P0 - M)e^kMt < P0 approaches the initial value P0, the denominator tends to zero, and we should therefore have population explosion. We then approach a _bifurcation_ point at time t* such that (P0 - M)e^kMt* = P0, and then for all subsequent points in time t' > t*, we should have a negative population size.
He has taught, its linear decrement of birth rate with the size of present population... If it happens to be variable, the differential equation will be more tough.
can someone help me with comparing to another formula found. textbooks and even blackpenredpen, patrickjmt use the formula: dP/dt = kP(1-P/M). Is this the same logistics equation to prof Leonard or not? I dont get where he is getting kP(P-M) where M is So/K
Good mathematics, especially since we can force out any beta sub 1's without any repercussions and even keep factoring these out without any moral compass needed or without violating any youtube inclusivity policy 😂 the more alpha mathematics we do, the stronger and smarter we get my fellow Mathematicians 💪😎🤟
Professor, I'm not sure where Diff. Equatiosn factors (no pun intended) into overall Calculus. If Derivatives are usually taught in Calc I, and Integrels in Calc II, I assume DIfferential Equations are in Calc III? Also....Star Wars Episode IX looks awesome.
DE uses many techniques from calc I, calc II, and some calc III. It is simply impossible to solve differential equations without knowing the techniques used in calculus
Q/solve this question Let P=population of the fish k=carrying capacity of fish α=growth rate of fish Now answer Using the mathematical modeling of fishes (1) If population of fish is small ,p≈0 ? *
I honestly cannot believe that there aren’t hundreds of colleges and universities having a bidding war on Prof. Leonard’s salary in order to secure him as a mathematics professor for their institution right now.
This man is an invaluable gift to all learners of mathematics.
Most colleges and universities don’t care about the quality of the teaching
If universities had him, we the public would miss a brilliant Prof. I know it's bit of selfish thought Lol
As someone else has said, almost all universities/colleges don't give a flying fk about the quality of teaching. They don't. It's not even in their awareness. I did a degree from 18-22, then went back 20yrs later, so I had more maturity and perspective. And I realized how indifferent the "system" really is.
I miss you. My class has gone past your videos and I feel like I need you.
he needs to come back ;-;
it sounds like prof leonard is your ex lol
Did you find videos fit for your class?
@@xantimiki let’s hope, after all that was 4 years ago
You are singlehandedly the greatest champion of explaining difficult math to the average human being. Thank you so much for existing and doing the things you do.
Because of parts of your videos lessons,My GED Math score is 172 which is college ready.
Thank you very much
Nai Mon that awesome! Congratulations, your hard work paid off.
Great Job!!!
I liked the video because you went through the nitty' gritty' of the math. I am the kind of person who needs to know who, what, where, when, and why when it comes to math. Thank YOU!
thank you my teacher from Ethiopia
thats what i was looking for , i have a great respect for him
Professor Leonard treats math like a language, teaches you how to speak it, and how to use it. An attribute that is paramount for any professor, but sadly an attribute that most lack.
Great video! Great job!
Logistic equation is a hardcore thing indeed. Much more difficult than one may guess, especially when it comes to the general case.
This should be the best explanation on the topic I have ever seen so far.
However, I must notice there is a sort of EXPLANATORY MISTAKE where it comes to 'explosion/extinct' version of the model at 59:30. No formal mistakes are though.
Part 1. Dynamics analysis.
Let's look at the equation dP/dt = k*P*(P-M), where k>0 and M>0.
We can identify 3 cases.
1) If current value P>M (for instance, as P0>M), then factor (P-M)>0 and the right-hand side (RHS) of the equation gives us dP/dt>0. It means that P(t)->+inf.
2) If current value 0M, but tau0 is region of interest, this issue stays in the shade.
Thank you for everything. It's funny how things never make sense until they do.
Thank you very much, Sir
I (almost) finished them all. They were really helpful.
I really appreciate your time and effort to make this possible.
Again, thanks.
You guys I have noticed someting off about the explosion condition. It does explode when p0 > m but only at a specific point in the futrue when mtk=ln(P0/m) which gives us zero in the denominator and in return either plus or minus infinity depending if you are approaching the point from the left which gives us plus infinity i.e. the explosion we are talking about. However, if you move a tiny bit in the future you get minus infinity and after a little while it reaches zero and stays there. It was pretty confusing to me at the beginning and needed to spend some time to get it right.
Sir your videos are amazingly helpful, after watching your videos I feel more confident with topics related to differential equations..
Kindly consider partial differential equations next.
Thank-you.
May God be pleased with him,Amen🤲
1:00:00 if the second term in the denominator is getting larger and larger and we subtract it from Po, wouldn't that mean the denominator approaches negative infinity and therefore P(t) -> 0? The conclusion of P(t) -> infinity makes more sense if the second term in the denominator approaches Po such that the denominator gets smaller and smaller and therefore P(t) larger and larger. Not sure if that is what was meant here.
Please donate to this man. Even $1 will help keep these videos coming!
ur the best teacher
All the way up professor!
I don't know how many times i should say thank u.
You can support him financially.
@@onemanenclave which i did
Holy cow. Fantastic. Thank you so much!
The glasses are a disguise. He takes them off to fly around and fight Super Villains. His only weakness is kryptonite.
Sir I think there is a mistake around 58:43. Isn't the limit of P(t) in this case going to be 0, no matter the starting condition?
For M>Po, the equation is a scaled version of:
P=1/(1-e^t)
And for M infinity is 0.
Perhaps I have made a mistake?
I notice this also. Even though case 2 where Po>M is suppose to be called explosion but the limit of the resulting function as t approaches infinity would go to zero from the negative P value.
The one in case 2 where Po< M is just alright since it's called extinction and the limit should go to zero as t approaches infinity. The function is decreasing to zero
Yes, I'm confused about this, as well. For an initial population P0 > M, we have (P0 - M)e^kMt = P0 - M < P0, but eventually (P0 - M)e^kMt reaches and surpasses the initial value P0. Furthermore, as (P0 - M)e^kMt < P0 approaches the initial value P0, the denominator tends to zero, and we should therefore have population explosion. We then approach a _bifurcation_ point at time t* such that (P0 - M)e^kMt* = P0, and then for all subsequent points in time t' > t*, we should have a negative population size.
At 20:10 How can B-sub1 be considered a constant, if it inversely varies with the population in a linear fashion? Dr. L doesn't explain this. Then he makes the great leap to the Logistic Equation. A little explanation here would go a long way!!!
Very hard. Brutal video
Hey professor please do Laplace transforms soon!
Can a threshold value of a population be a rational number, or do I need to approximate the number to the nearest integer while making calculations?
If you had been my professor I may have learned something in dif eq. Though I seem to know more than I thought, this was still good to go over. I know in chemistry reactions can reach an equilibria, is this not a term used for your first case?
At the very end when youre explaining how when P > M, P(t) → infinity.... I dont understand how the fraction is shrinking but not going negative. What we have essentially in the denominator is P - (P - M)e^t - so as t increases, e^t is sharply increasing. And P - M is positive since P > M. And no matter how small a positive a value P - M is, since it is being multiplied by an exponential function increasing without bound, its overall value is quickly rising. Then we are subtracting that value from P....so would that not result in a negative number?
Some value minus (some value minus a smaller value) times a huge value. For example 10 - (10 - 3)100000 = 10 - (7)100000 = negative. Im sure I am missing something but I was struggling to understand what
Great presentation, BTW. I'm using Boyce and Diprima and learning on my own. It's a tonne of fun, but your presentation is really useful. I'm definitely going to check out your ODE play list. It will be really good reinforcement of what I've read in the text. Thanks for all of this, it's clearly a lot of work.
@Allan 112358 I'm using windows 10 with python. Specifically the anaconda python distribution and I'm doing my coding in Jupyter labs/notebooks. I'm doing a lot of the coding by hand to learn in better detail how to numerically solves systems of ODEs and the various numerical methods that can be used to do that (Fwd/bkwd Euler, Runge/Kutta, Adams-Bashforth, etc). That said, there are some really excellent python packages that will do this sort of thing for you: scipy, sympy, gekko have solves, and numpy is a great support library that is generally useful. For plotting/visualizing results I just use mathplotlib, the python standard. All of this is free, btw, which is an added bonus.
@Allan 112358 best of luck with it!
@Allan 112358 a cheap windoze laptop would be fine, it money is an issue that's probably the best option in the short term.
@Allan 112358 all of those techs work great on mac, windoze, or linux so you should be fine.
Hi! Can you upload some videos on DEs solvable for p, x, y
Envelopes, singular solution
Clairauts Equation
Ricatti Equation
Thank you :D
For the explosion model, I see my book as dP/dt=rP, in here, it is dP/dt=kP(P-M), can any tell me how these two equations are interchangeable?
Or can anyone tell me, in the section birth rate proportional to population, why (δ/k) could be equal to M, δ is initial death rate?
Don't remember if you've already mentioned this but will you also make videos on PDE's as well? That would be nice
Amazing Stuff!!
The king 👑
Man I remember everyone hated solving these things. They were just nasty, especially during the test ughhh.
This man is priceless.
Very great
hello sir birth rate per thousand of people per change in time, is it in fraction?
So in the very last bit about the threshold, you basically get an infinitely large population in a finite time... if the denominator were to go negative (after t hits the value at which Po - (Po - M)*e^(mkt) < 0) then the population would suddenly switch to being negative, which makes no physical sense whatsoever. Am I reading that right?
I notice this also. Even though case 2 where Po>M is suppose to be called explosion but the limit of the resulting function as t approaches infinity would go to zero from the negative P value.
The one in case 2 where Po< M is just alright since it's called extinction and the limit should go to zero as t approaches infinity. The function is decreasing to zero
Yes, I'm confused about this, as well. For an initial population P0 > M, we have (P0 - M)e^kMt = P0 - M < P0, but eventually (P0 - M)e^kMt reaches and surpasses the initial value P0. Furthermore, as (P0 - M)e^kMt < P0 approaches the initial value P0, the denominator tends to zero, and we should therefore have population explosion. We then approach a _bifurcation_ point at time t* such that (P0 - M)e^kMt* = P0, and then for all subsequent points in time t' > t*, we should have a negative population size.
Why is B1 a constant with the logistic equation?
He has taught, its linear decrement of birth rate with the size of present population... If it happens to be variable, the differential equation will be more tough.
@@chanakyasinha8046 theres easier ways to see the logistic equation in my opinion...
@@dildobaggins2759 how?
can someone help me with comparing to another formula found. textbooks and even blackpenredpen, patrickjmt use the formula: dP/dt = kP(1-P/M). Is this the same logistics equation to prof Leonard or not? I dont get where he is getting kP(P-M) where M is So/K
Same doubt
You're great
Good mathematics, especially since we can force out any beta sub 1's without any repercussions and even keep factoring these out without any moral compass needed or without violating any youtube inclusivity policy 😂 the more alpha mathematics we do, the stronger and smarter we get my fellow Mathematicians 💪😎🤟
Anyone know of a Number Theory lecture series!
35:00 sc
thanks to him we can now calculate the population of earth that was swiped out after thanos snap 😂😂😂😂🤣🤣😅
Professor, I'm not sure where Diff. Equatiosn factors (no pun intended) into overall Calculus. If Derivatives are usually taught in Calc I, and Integrels in Calc II, I assume DIfferential Equations are in Calc III? Also....Star Wars Episode IX looks awesome.
D.E. follows Calc 3.
DE uses many techniques from calc I, calc II, and some calc III. It is simply impossible to solve differential equations without knowing the techniques used in calculus
Episode 9 looks like the kind of mess you're forced to pick up while walking your dog...
the video image is too poor, you need to fix it more
Q/solve this question Let P=population of the fish k=carrying capacity of fish α=growth rate of fish Now answer Using the mathematical modeling of fishes (1) If population of fish is small ,p≈0 ? *
what do you mean people die
AND THEY'RE DOING WHAT BUNNIES DO!
P goes to zero not in this way
🥵