Ampere's Law: Magnetic Field in a Coaxial Cable

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  • เผยแพร่เมื่อ 18 ธ.ค. 2024

ความคิดเห็น • 204

  • @lNDlANSPlCE
    @lNDlANSPlCE 5 ปีที่แล้ว +39

    Why doesn't this have more views... I'm gonna share it with all my emag friends. Thank you, Ninja! When I graduate and have an engineer's salary I will be able to contribute and quantify my gratitude for your videos!

    • @PhysicsNinja
      @PhysicsNinja  5 ปีที่แล้ว +5

      Thanks for the kind words!

    • @dromero8127
      @dromero8127 ปีที่แล้ว +5

      Hope you made it bud

    • @youtuber9409
      @youtuber9409 16 วันที่ผ่านมา

      5+ years later, how are you doing now?

  • @brianrook6207
    @brianrook6207 4 ปีที่แล้ว +25

    An outstanding presentation. It has cleared up all the problems I had understanding the physics behind coaxial cables.
    Thank you
    Brian Rook

  • @hughrountry1281
    @hughrountry1281 6 หลายเดือนก่อน +4

    Audio mixing could be improved, but the content is very helpful.

  • @ronnyalfons7096
    @ronnyalfons7096 4 ปีที่แล้ว +4

    Without watching about 2 minutes of the video, i can already tell that there's good teaching in this video

  • @rifusaki
    @rifusaki 2 ปีที่แล้ว +2

    You've just saved an anonymous student on the internet! This explanation is awesome!

  • @cosmolearner5562
    @cosmolearner5562 4 ปีที่แล้ว +1

    @21:05 Which current is taken positive and which one negative is also included in ampere's law -
    First arbitrarily consider the direction of path that you have choosen (generally taken same as magnetic field)
    The apply right hand thumb rule to the path choosen the direction of thumb is taken as positive that mean on applying RHT rule on path all the enclosed current in the direction of thumb are taken as positive and all other currents opposite to direction of thumb are taken as negative..

  • @libertyprime656
    @libertyprime656 3 ปีที่แล้ว +3

    Excellent video, thank you for creating this. Studying for my E&M final and this has been extremely helpful

  •  6 ปีที่แล้ว +2

    Hey dude I guess you made a mistake. It will be good for you if you check the b

  • @wlk1757
    @wlk1757 หลายเดือนก่อน

    I have question, in the b

  • @gideonkyeremeh868
    @gideonkyeremeh868 5 ปีที่แล้ว +2

    Thanks Ninja... Just got it at the right time for my presentation the next morning

  • @leandrogarcia6396
    @leandrogarcia6396 2 ปีที่แล้ว +2

    This is the best video on the god damn internet

  • @dareadegun2460
    @dareadegun2460 2 ปีที่แล้ว +1

    Thanks for the clear and smooth explanation

  • @etanetan101
    @etanetan101 2 ปีที่แล้ว +2

    I think you just saved me before my midterm tomorrow. 😂 Thanks so much!!!

  • @laisguizelli25
    @laisguizelli25 3 ปีที่แล้ว +2

    Congratulations from Brazil, your video help me a lot!!

    • @PhysicsNinja
      @PhysicsNinja  3 ปีที่แล้ว +1

      Thanks for watching and the support. It's great to hear from students.

  • @piao-o3w
    @piao-o3w 2 ปีที่แล้ว

    It is the best video for a college student studying electromagnetism. It was very helpful. Thank you.

  • @rodolfogarcia6263
    @rodolfogarcia6263 6 ปีที่แล้ว +1

    Would a

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว

      This is done @ 10:44. In this case the field is not 0 because the Amperian loop will enclose all of the current within the small wire in the middle.

  • @kabandajamir9844
    @kabandajamir9844 7 หลายเดือนก่อน

    The world's best teacher thanks sir

  • @karthikkrishnan7558
    @karthikkrishnan7558 4 ปีที่แล้ว +1

    simple explanation...helped me a lot.. Thank you Sir

  • @HakaiShakai
    @HakaiShakai 3 ปีที่แล้ว +1

    Literally saved my life
    God bless your soul

  • @jennykeeling747
    @jennykeeling747 11 หลายเดือนก่อน +1

    This was explained so well thank you so much!

  • @monoinluv4894
    @monoinluv4894 3 ปีที่แล้ว

    13:23 does the direction of the current matter in terms of the sign for B? would dl and b be in the same direction?

  • @HuFocus-f2y
    @HuFocus-f2y หลายเดือนก่อน +1

    Why cant my professors make videos like these!!! Thank you

  • @lagado1lag
    @lagado1lag 2 ปีที่แล้ว +5

    Amazing! I really understood the exercise. Thank you!

  • @cnnn7885
    @cnnn7885 5 ปีที่แล้ว

    for b < r < c situation, why is it (r^2 - b^2) but not (r - b)^2 , same as (c^2 - b^2)

    • @PhysicsNinja
      @PhysicsNinja  5 ปีที่แล้ว +1

      Because the area will be the difference between r and b. Pi- r^2 will be area. Of entire circle then take away area of inside part Pi-b^2. The area is not pi- ( r-b)^2

  • @salmamahameed2160
    @salmamahameed2160 3 ปีที่แล้ว +1

    this isn't an empty cable right? like it's not a shell of a coaxial cylinder cable? and if that was the case shouldn't the magnetic field in the r

  • @bobross5716
    @bobross5716 5 ปีที่แล้ว +5

    Thank you so much! Not even Griffith’s could properly go over these types of problems

    • @estebansingh9411
      @estebansingh9411 3 ปีที่แล้ว +1

      In my experience TH-cam tutorials work better than books. At least better than griffiths, purcell and thermodynamics books

  • @igorsantos-qj3zd
    @igorsantos-qj3zd ปีที่แล้ว +1

    Thx from Brazil!

  • @JH-ux1re
    @JH-ux1re 2 ปีที่แล้ว +1

    Perfect! I was always confused by these things. Thank you very much! Saved me!

  • @lilac.2858
    @lilac.2858 9 หลายเดือนก่อน +1

    So well explained!

  • @shaunwu3609
    @shaunwu3609 6 ปีที่แล้ว +1

    Thanks for going into the details! You have a nice voice as well!

  • @ShrabantiDeb
    @ShrabantiDeb 2 ปีที่แล้ว +1

    better explanation than books..

  • @sor3na369
    @sor3na369 ปีที่แล้ว +1

    Thanks for great explanation.

  • @asgoodasbread5559
    @asgoodasbread5559 2 ปีที่แล้ว +1

    Great Explanation !! TY

  • @brayschway6746
    @brayschway6746 3 ปีที่แล้ว +2

    This was beautifully done. Thank you.

  • @뿌엥-w7d
    @뿌엥-w7d 3 ปีที่แล้ว

    You’re better than my professor, thank you

  • @sanskararora6425
    @sanskararora6425 4 ปีที่แล้ว

    as the inner cylinder is a conductor so all charges would be at the surface of the cylinder and hence the current should flow through the surface (as current is the flow of charges) so I would be zero for r

  • @juliazhang3600
    @juliazhang3600 4 ปีที่แล้ว +1

    simple explanation! I love it!

  • @Arif.mohmand
    @Arif.mohmand 2 ปีที่แล้ว +1

    Very nicely presented, at the end you said, it was a special coaxial cable with the both the same currents, thats is why B is zero, wasn't it zero because they were different currents in the direction?

    • @PhysicsNinja
      @PhysicsNinja  2 ปีที่แล้ว

      Same current, different direction will result in 0 field outside of cable because total current enclosed is 0.

  • @aprilsianpi7973
    @aprilsianpi7973 4 ปีที่แล้ว

    i don't think you have to include the interior of I at 13:20 minutes in region (b

    • @PhysicsNinja
      @PhysicsNinja  4 ปีที่แล้ว +1

      Yes you do, it’s the total current enclosed by the loop.

    • @PhysicsNinja
      @PhysicsNinja  4 ปีที่แล้ว +1

      Superposition of fields

    • @aprilsianpi7973
      @aprilsianpi7973 4 ปีที่แล้ว

      @@PhysicsNinja Thank you. You clear up all my confusion.

  • @thuonghoang530
    @thuonghoang530 3 ปีที่แล้ว

    thank for your lectures, I am a teacher, I would like to know exactly the divide you (everyone) used to draw lectures beautifully?

  • @Mehmetalp99
    @Mehmetalp99 หลายเดือนก่อน +1

    Great explanation

    • @PhysicsNinja
      @PhysicsNinja  หลายเดือนก่อน

      Glad you think so!

  • @boysenbeary
    @boysenbeary 3 ปีที่แล้ว +1

    Great explanation!

  • @pierretobgui1792
    @pierretobgui1792 5 ปีที่แล้ว +1

    Really helpful

  • @sealol5209
    @sealol5209 6 ปีที่แล้ว +1

    Thanks man! Was having trouble understanding this question!

  • @rakibuddin385
    @rakibuddin385 5 ปีที่แล้ว +1

    Thank you so much .you explained so easily

  • @johnkay1952
    @johnkay1952 3 ปีที่แล้ว +2

    Just wondering, does this implication of the magnetic field being 0 outside the outer loop bypass the limitations of really small computers? I remember hearing somewhere that there's a limitation of how small circuit elements can get because their magnetic field would induce currents in nearby circuit elements.

    • @TheLeontheking
      @TheLeontheking 2 ปีที่แล้ว

      Good question! I'm not educated enough to answer it, but I would guess that for these small scales the classical theory presented here does not longer hold.

  • @RicktokSV
    @RicktokSV 6 ปีที่แล้ว +2

    Hi ninja ninja leader. Cheers!!. I have a question, what is the difference between magnetic field and magnetic field intensity? Thank you.

  • @jorgemillan4041
    @jorgemillan4041 5 ปีที่แล้ว +1

    these are great please make more

  • @km-sc4kz
    @km-sc4kz 4 ปีที่แล้ว

    is there any possibility of electric field being produced by this coaxial cable (atleast in a

  • @maxdougherty3429
    @maxdougherty3429 4 ปีที่แล้ว

    Great explanation! I wish I had you teaching my physics class!

  • @yusufkeskinoz9740
    @yusufkeskinoz9740 5 ปีที่แล้ว +13

    Sound needs to be fixed but other than that lecture is okay

  • @user-ny1vt3ek4i
    @user-ny1vt3ek4i 4 ปีที่แล้ว

    Thank you Physics Ninja!!!!

  • @linjisoo9975
    @linjisoo9975 3 ปีที่แล้ว

    Very helpful video!

  • @masouddayaghi5923
    @masouddayaghi5923 6 ปีที่แล้ว +4

    Thanks a lot man, it was wonderful.

  • @EnzoChai
    @EnzoChai 5 ปีที่แล้ว +1

    Tq very much man...save my day 🙌🙏

  • @uchennaubeh9498
    @uchennaubeh9498 5 ปีที่แล้ว +3

    Thanks so much, this clarified my Delima about the magnetic field everywhere in space.

    • @lukedimitriades9835
      @lukedimitriades9835 5 ปีที่แล้ว

      Now your only dilemma is learning how to spell dilemma 😂

  • @MayankLC93
    @MayankLC93 5 ปีที่แล้ว +1

    GREAT HELP SIR !!!
    💞INDIA

  • @taladiv3415
    @taladiv3415 4 ปีที่แล้ว

    Thank you for this clear solution.

  • @hasranman
    @hasranman 5 ปีที่แล้ว +1

    This really helped me. Thanks!

  • @ferhat_ee-76
    @ferhat_ee-76 3 ปีที่แล้ว

    man you are the best, I tried to find the answer to the same question

  • @JamBergMann
    @JamBergMann 2 ปีที่แล้ว

    Great explanation! Thank you. Can we also calculate the B-Field for high frequency currents taking the skin effect into consideration with this method?

  • @akibmostabe98
    @akibmostabe98 6 ปีที่แล้ว

    Well explained,but when u do the closed integration it should be integration over rho product with dfi according to cylindrical co-ordinate system(Here rho is a product with dfi because rho is the perimeter across the arc dfi).Above all its good.
    Another thing is that u may use H(Magnetic field intensity) instead of B (Magnetic flux density) because when we r considering free space only then they aren't equal that is B=meu(o).H.But in practical cases medium may vary according to products choice

  • @saffyt348
    @saffyt348 6 ปีที่แล้ว +1

    This was so helpful! Thank you!

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว

      Glad the video was helpful for you.

  • @fatmanur5409
    @fatmanur5409 ปีที่แล้ว

    Could you please also calculate the current density for each interval?

  • @allendeguzman6771
    @allendeguzman6771 6 ปีที่แล้ว +1

    wow. you nailed it,, well explained.. Wonder if you could make videos about magnetic moments for rotating charge disk, spheres, etc.

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว +2

      Thanks for the comment, i'll make a video tomorrow night comparing the magnetic moments of a disk, spherical shell, and a uniformly charged sphere. Physics Ninja loves requests!

    • @allendeguzman6771
      @allendeguzman6771 6 ปีที่แล้ว +1

      cant wait to learn form that video..
      ,,,
      this might be too much but it will makes sense if there is also a great video about electric fields, (gauss law) or gaussian surfaces to see connections to amperes law(amperian surfaces.

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว +2

      i have a few videos on Gauss' Law. Here's the first of the series. th-cam.com/video/fGB1csk7tX8/w-d-xo.html
      I'll try to finish the one on magnetic moments soon. Physics Ninja is a busy guy!

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว +2

      Here's the first part of magnetic moment series. I'll add the other 2 parts tonight. Happy Learning! th-cam.com/video/4F0p_VvYvMc/w-d-xo.html

  • @yamaan93
    @yamaan93 3 ปีที่แล้ว +1

    it's a good video and good explanation but the microphone popping makes it quite difficult to listen to

    • @PhysicsNinja
      @PhysicsNinja  3 ปีที่แล้ว

      Thanks. Ninja has a new microphone now.

  • @nabeelljassim6652
    @nabeelljassim6652 2 ปีที่แล้ว

    Great good teacher

  • @matthew_bang
    @matthew_bang 4 ปีที่แล้ว

    Fantastic work

  • @yigitarsoy1944
    @yigitarsoy1944 5 ปีที่แล้ว +1

    This is awesome!

  • @THEWouter1212
    @THEWouter1212 2 ปีที่แล้ว +1

    Thanks a lot!

  • @kholoudhakim7887
    @kholoudhakim7887 5 ปีที่แล้ว +1

    thanks so much

  • @RinaNewhouse
    @RinaNewhouse ปีที่แล้ว

    Do you know why it matters to take the fraction of the AREA of the cylinders when finding the B field in situations 1 and 3?

  • @asem-n1c
    @asem-n1c 4 ปีที่แล้ว

    That video saved my life

  • @betulguncaldi4676
    @betulguncaldi4676 4 ปีที่แล้ว

    Beautiful explanation! You're great! :)

  • @johngordon8513
    @johngordon8513 2 ปีที่แล้ว +1

    ur a legend

  • @joepaschal6426
    @joepaschal6426 4 ปีที่แล้ว

    How could you do this same problem butt starting from the magnetic energy density of a ideal solenoid and combining that with amperes law to find the density as a function of distance radial out from the axis and use this to find the inductance in the cable. thank you.

  • @peytonkliewer1997
    @peytonkliewer1997 3 ปีที่แล้ว

    Thank you so much! This was very helpful!

  • @birahnugmedhin1934
    @birahnugmedhin1934 ปีที่แล้ว

    You are special❤❤❤❤❤

  • @teambananakinns
    @teambananakinns 6 ปีที่แล้ว

    what if the equation was asking for r

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว

      I think the solution cover all values of r. Maybe i don't understand your question

  • @JD867
    @JD867 4 ปีที่แล้ว

    You're awesome. This helped me a lot.

  • @aysenuratagun
    @aysenuratagun 4 ปีที่แล้ว

    Thanks a lot, this video helps me a lot anytime i need :)

  • @MaDcAmStErGaming
    @MaDcAmStErGaming 6 ปีที่แล้ว

    Thanks physics ninja, you might help me not fail uni xxx

  • @kateystevenson7912
    @kateystevenson7912 3 ปีที่แล้ว

    Great video, thank you!

  • @asmartguycodename4721
    @asmartguycodename4721 3 ปีที่แล้ว

    Thanks for this great help. 😃

  • @ozanyldz445
    @ozanyldz445 3 ปีที่แล้ว +1

    thanks a lot

  • @syedmuhammadhaziqbinsyedah767
    @syedmuhammadhaziqbinsyedah767 3 ปีที่แล้ว +1

    Thank you :3

  • @aryanviolett4606
    @aryanviolett4606 4 ปีที่แล้ว +1

    Nice! Thanks alot :)

  • @ezefferth
    @ezefferth 3 ปีที่แล้ว

    Brasil love's you!! grateful!!

  • @Zakirhossain-wx8qc
    @Zakirhossain-wx8qc 3 ปีที่แล้ว

    Thank you ♥️♥️

  • @eckardbezuidenhout
    @eckardbezuidenhout 5 ปีที่แล้ว

    Hello sir, thank you for your thorough explanation. I just need to understand something please. Let us for now consider only the small conductor (gold). Seeing that it is a conductor, will all the charge/current not be located on it's surface only? Ergo, a proper Amperian loop would be such that it goes around the entire conductor and not inside the conductor. This would then change the outcome of this part and the rest of the problem. I need to understand this because there are so many people on the internet doing their own thing and in the end the information conflicts in the small but very necessary details.
    Thank you again for this explanation.

    • @braceyourselvesfortruth2492
      @braceyourselvesfortruth2492 5 ปีที่แล้ว

      Not 100% sure but you may be confusing current (moving charges) with static charges. Current is based on cross-sectional density so the amount of the wire we draw our loop around determines the total enclosed current.

  • @antiquarian1773
    @antiquarian1773 5 ปีที่แล้ว +1

    what would happen if the currents aren't flowing in the opposite directions? would that mean the current is doubled when r is greater than c?

    • @PhysicsNinja
      @PhysicsNinja  5 ปีที่แล้ว

      Yes you are correct, the field would be be different inside the outer shell and outside of both the field would that of a wire with current =2I

    • @antiquarian1773
      @antiquarian1773 5 ปีที่แล้ว

      @@PhysicsNinja thank you for the quick response!!

  • @griffithfimeto3387
    @griffithfimeto3387 8 หลายเดือนก่อน

    Why there is current in outer conducter current oppsite to inner ? Please answer

    • @elimiNator345
      @elimiNator345 8 หลายเดือนก่อน

      Because coaxial cables work so that the magnetic flux density cancels and doesn’t interfere with its surroundings. To do that the currents must be opposite

  • @lauraaconceptslk
    @lauraaconceptslk 4 ปีที่แล้ว

    Nice one

  • @3washoka
    @3washoka 5 ปีที่แล้ว +1

    Thank you 🙏🏼

  • @killirina
    @killirina 4 ปีที่แล้ว +1

    dude, thank you!

  • @martinsibanda8026
    @martinsibanda8026 4 ปีที่แล้ว

    thank you well explained

  • @abhishekpawarpoems
    @abhishekpawarpoems 6 ปีที่แล้ว +1

    Thanks brother!

  • @shimabarati7963
    @shimabarati7963 5 ปีที่แล้ว +1

    tnx a lot! very well !

  • @fatmanur5409
    @fatmanur5409 ปีที่แล้ว

    Why do we ignore the outside thin hollow cylindrical conductor in which the current goes into the page?

    • @PhysicsNinja
      @PhysicsNinja  ปีที่แล้ว +1

      Amperes law states that it’s only the current enclosed in the loop that will contribute. You only include the outer shell if you are calculating the field outside the coaxial cable.

  • @BehnoudMaleki-r6f
    @BehnoudMaleki-r6f 3 หลายเดือนก่อน

    love you man