This is so incredibly clear and straight forward it has stunned me. It is EXACTLY what I was looking for. Sincerely THANK YOU for not wasting my time with useless rambling.
When I watch these videos for my final….I feel somehow…everything will all be ok. Maybe it’s because your video on Gauss’s law helped me to get a 95 instead of 50 on my first exam.
0:46 This video is amazing, but I absolutely cannot find any information *anywhere* as to why this dot product's cosθ is never shown. You're taking the magnitude, I believe (and using the RHR for direction), so the closed path integral of B dot dl is supposed to go to |B| |L| cosθ. My question is, where is B parallel to dl, or is it parallel to the normal vector? Maybe I just figured it out lol.
The Amperian path you pick typically either has B in the direction of dL (in which case cos0=1) or B is perpendicular to the direction of dL (in which case cos90=0). In the general case for an arbitrary Amperian loop you’d have to leave cos in there
@@WeAreShowboat Ok that makes more sense, thank you. I also finally noticed the dl *is* the loop, which you show in your diagram-it just didn't register. We good!
Showboat, thank you. But you said early in the video that one "must choose a loop path in which B is constant." Yet later, when doing the solenoid, the loop path cannot possibly have constant B as part of the loop is outside the solenoid. Can you please explain the "choose a loop path in which B is constant." Thank you.
So really I should say “choose a path where B is constant along each part of the loop” For the solenoid we treat the field outside the solenoid as zero so that contribution to the integral is zero. You should imagine breaking the integral into pieces along each constant part.
So my doubt was that can the shape which we decide be three dimensional? So if suppose a few currents were going out and inwards and one was in the plane then could we decide a shape so it enclosed all the currents?
In that case some might not be piercing the area, and the B field would likely not be constant along the Amperian loop or parallel to the loop, but Amperes law should still be true. Just not very useful there.
I'm given a problem to calculate current through a rectangular cross section of a wire and nobody covers how to do this. I don't understand why this is the case.
I don't understand your explanation for the solenoid. Why would a rectangle have constant B? I would have thought you would have to use the magnetic field lines, which have constant B. And if you do need to use the field lines, would you need yet another formula to calculate the length/ shape of those lines?
The lines run straight down the length of the solenoid if it is infinitely long. Outside near the solenoid the field is vanishingly small if the solenoid is infinite.
@@WeAreShowboat I see. Well, that raises another problem for me. Most solenoids aren't very long, so how can we justify approximating them as infinite? I could understand if the solenoid had a million or a billion turns, but they tend not to.
@@johnfist6220 The solution will be a good approximation if the length and number of turns to radius is large then this is a good approximation for the B in the center midpoint of solenoid. NASA has a solution online for the finite solenoid if you want to see it. ntrs.nasa.gov/api/citations/19980227402/downloads/19980227402.pdf
I am literally in love with these worksheets.The perfect summary I've ever seen!
So glad they’re helpful!
@@WeAreShowboat Thank you a lot for helping us for free
You explain it so simply, my teacher explains it so complex that I get confused with everything
you sound EXACTLY like Owen Wilson and I've never been more focused on a physics concept in my life thank you
i was waiting for him to say kachow
i thought i was the only one
This is so incredibly clear and straight forward it has stunned me.
It is EXACTLY what I was looking for.
Sincerely THANK YOU for not wasting my time with useless rambling.
When I watch these videos for my final….I feel somehow…everything will all be ok. Maybe it’s because your video on Gauss’s law helped me to get a 95 instead of 50 on my first exam.
Sir you need to make content for every physics topics
I truly adore your videos. The way you explain these concepts somehow clicks with my brain better than any instructor I've ever had.
I love your lectures. Thank you a lot. Without you I won't be able to understand these concepts.
Absolutely incredible! I was so lost in class this helped immensely. I might pass physics 2 thanks to you
Tienes que hacer review de todos los temas de física están asombroso los videos!! Great job!
I'll always be grateful for these ultimate review videos.
You are seriously very good at teaching... Congrats man, wish you had a million views on this video
thanks man you're saving my life i finally understood what is going on
Man, you explain everything so well, thank you
This is just perfect! I’m gonna print it out! ❤❤❤
thanks so muuch, i was struggling trying to understand this, now is super clear, greetings from chile:)
glad i found ur acc!! thank you for clarifying the things for us
你好We Are Showboat先生，我只想说，你是我的物理爸爸。谢谢你的复习视频。I don't know why I typed that in Chinese, but thank you so much for these videos, sir!!! 😇
Very very good explanation. Soft voice as well haha
Keep making these ! rigourous but not the point where its unwatchable thanks
You are born to teach. Thank you so much.
Monstrous Biot-Savart's law 👽👺💀 0:10
You are literally amazing. Thanks so much.
useful for me, thanks I looking forward for a long time until today.
0:46 This video is amazing, but I absolutely cannot find any information *anywhere* as to why this dot product's cosθ is never shown. You're taking the magnitude, I believe (and using the RHR for direction), so the closed path integral of B dot dl is supposed to go to
|B| |L| cosθ. My question is, where is B parallel to dl, or is it parallel to the normal vector? Maybe I just figured it out lol.
The Amperian path you pick typically either has B in the direction of dL (in which case cos0=1) or B is perpendicular to the direction of dL (in which case cos90=0). In the general case for an arbitrary Amperian loop you’d have to leave cos in there
@@WeAreShowboat Ok that makes more sense, thank you. I also finally noticed the dl *is* the loop, which you show in your diagram-it just didn't register. We good!
omg this is amazing saved my life
Great explanation
Nice video, it helped me understand ampere's law more
Showboat, thank you. But you said early in the video that one "must choose a loop path in which B is constant." Yet later, when doing the solenoid, the loop path cannot possibly have constant B as part of the loop is outside the solenoid. Can you please explain the "choose a loop path in which B is constant." Thank you.
So really I should say “choose a path where B is constant along each part of the loop” For the solenoid we treat the field outside the solenoid as zero so that contribution to the integral is zero. You should imagine breaking the integral into pieces along each constant part.
can you do an ultimate faradays law review
Yes, that’s next on the list
What a saviour bro
Hii could you make a video on ac circuits and phasor diagrams.
Here is the GOAT, THE GOAT!!!1
So my doubt was that can the shape which we decide be three dimensional? So if suppose a few currents were going out and inwards and one was in the plane then could we decide a shape so it enclosed all the currents?
In that case some might not be piercing the area, and the B field would likely not be constant along the Amperian loop or parallel to the loop, but Amperes law should still be true. Just not very useful there.
Ur a gift from god 😃
you need more subscribers
Thank you! Extremely explanatory!
May you provide explanations to Ampere's Law for word problem examples? Thank you for the informative video!
I'm given a problem to calculate current through a rectangular cross section of a wire and nobody covers how to do this. I don't understand why this is the case.
Thank you for this topic.
Can I get a pdf file?
Thanks for this 🙏🏼🙏🏼
I don't understand your explanation for the solenoid. Why would a rectangle have constant B? I would have thought you would have to use the magnetic field lines, which have constant B. And if you do need to use the field lines, would you need yet another formula to calculate the length/ shape of those lines?
The lines run straight down the length of the solenoid if it is infinitely long. Outside near the solenoid the field is vanishingly small if the solenoid is infinite.
@@WeAreShowboat I see. Well, that raises another problem for me. Most solenoids aren't very long, so how can we justify approximating them as infinite? I could understand if the solenoid had a million or a billion turns, but they tend not to.
@@johnfist6220 The solution will be a good approximation if the length and number of turns to radius is large then this is a good approximation for the B in the center midpoint of solenoid. NASA has a solution online for the finite solenoid if you want to see it. ntrs.nasa.gov/api/citations/19980227402/downloads/19980227402.pdf
Where can I find examples of current density which is dependent on an angle ?? Thanks :)
In real life or in textbooks?
Textbooks pls, Ive been having trouble finding any resources
thank you very much man!
Are you aware of ampere's Cardinal law suggested by physics professor Panos Pappas?
No, what is Amperes cardinal law?
@@WeAreShowboat connect the url by removing the parentheses to see the image (https(:)//)files(.)catbox(.)moe/ xzmo67(.)jpg
thank you sir it is useful
how do u make it?
the link doesn't work
I switched it to a pdf form. Does it work now?
@@WeAreShowboat yes, thank you!
how many ebooks did u write
Just one on language
oh thanks, u help me a lot@@WeAreShowboat
you're a legend
Thank you
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very good
AMAZING
HOLY SHIT thank youuu!
i love u king
THANK YOU
if i crush my mcat i owe you brother
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