lab of full wave rectifier using opamp th-cam.com/video/CI1RDShshCY/w-d-xo.html lab of half wave rectifier using opamp th-cam.com/video/EPuV_qJ5shQ/w-d-xo.html
sir , when it becomes a voltage follower , both the inverting and non inverting terminals would have the same voltage and then the output of op amp would become 0 and the diode wont conduct . Where am I going wrong , im confused , please explain
@@ayushagarwal69 the unique behavior of opamp is that at the same time the opamp act as short circuit as well as open circuit. here the opamp that we are considering is not ideal opamp.so, there will non ideal behaviour of oapmp. ideally the input resistance is infinity but practically it is in megaohm. ideally there is no current flow between inverting (-ve) and non inverting terminal(+ve) but the nano ampere of current flow across the inverting and non inverting terminal. so, the multiplication of input resistance (mega ohm) and nano ampere current leads to development vid(voltage difference between +ve and -ve terminal. In the animation it has been shown that the product of open loop gain and vid causes the flow of high current and which tries to run the circuit. the link for animation is given below . th-cam.com/video/ZOwjOBV54VM/w-d-xo.html
lab of full wave rectifier using opamp
th-cam.com/video/CI1RDShshCY/w-d-xo.html
lab of half wave rectifier using opamp
th-cam.com/video/EPuV_qJ5shQ/w-d-xo.html
Thanks sir
Nice sir👍👍👍🔥🔥
Thank you very much for your tutorial.
sir , when it becomes a voltage follower , both the inverting and non inverting terminals would have the same voltage and then the output of op amp would become 0 and the diode wont conduct . Where am I going wrong , im confused , please explain
*in the half wave rectifier
@@ayushagarwal69 the unique behavior of opamp is that at the same time the opamp act as short circuit as well as open circuit. here the opamp that we are considering is not ideal opamp.so, there will non ideal behaviour of oapmp. ideally the input resistance is infinity but practically it is in megaohm. ideally there is no current flow between inverting (-ve) and non inverting terminal(+ve) but the nano ampere of current flow across the inverting and non inverting terminal. so, the multiplication of input resistance (mega ohm) and nano ampere current leads to development vid(voltage difference between +ve and -ve terminal. In the animation it has been shown that the product of open loop gain and vid causes the flow of high current and which tries to run the circuit. the link for animation is given below .
th-cam.com/video/ZOwjOBV54VM/w-d-xo.html