This January, I'm sending daily e-mails with A Level Physics Questions, how to answer them and bits of revision. Sign up here if that sounds useful: zphysicslessons.net/about
Vector triangles are much more useful when you have nontrivial geometries, and it can give you a good numerical solution to a problem using scale diagrams. It also gives you a better understanding of what happens when various magnitudes or angles are changed as you can tell from the diagram.
1:33 hello, im confused, shouldn't the force F=mg/sin30 because in the right angled triangle the opposite side is weight(mg) and the hypoteneus is F so since sin=opp/hyp then sin30=mg/F and rearranging gives F=mg/sin30=156.96N ?? pls let me know if im wrong.
no problems! So I have actually filmed this in detail the actual derivation here: th-cam.com/video/GqyI3zl9P_o/w-d-xo.htmlsi=pl2-Kw7M5IRlS_BR. In practice it's worth remembering in the exam that along the slope the component is m*g*sin(theta) Hope this helps!
6:54 “The only available force with a component towards the centre is F so F must increase” why is this? Why does it increase?? To stay on the conveyor? Or because it’s turning?…
if it's turning the only thing that can have happened is for the force F to have increased as it's the only force which has a component towards the centre of rotation. Hope this helps!
The mass is constant and so is its weight. Hence Wcos30 and Wsin30 won’t change. So friction F is the only force that can increase and act as a centripetal/resultant force, which causes it to turn!
So, there must be a force directed towards the centre if it's moving at a circular motion. This has to be from one of the forces present, the only one which has a component directed towards the centre of rotation is F. Hope this helps!
for question (i), i would have thought that r would be 2 / cos(30) due to the angle of the circular motion, could you explain why this is not the case?
excellent question. It's hard to visualise in a comment without a whiteboard, but we are assuming the suitcase rotates around the point directly horizontally across the radius given. And it is not rotating at an angle with respect to a point below it. Hope this helps!
@@zhelyo_physics that's cool sir, even tho I couldn't able to solve much questions from morning books and level 3 of Sashi Bhushan Tiwari but it's pretty interesting in there
This January, I'm sending daily e-mails with A Level Physics Questions, how to answer them and bits of revision. Sign up here if that sounds useful: zphysicslessons.net/about
Vector triangles are much more useful when you have nontrivial geometries, and it can give you a good numerical solution to a problem using scale diagrams. It also gives you a better understanding of what happens when various magnitudes or angles are changed as you can tell from the diagram.
Resolving forces much better than vector triangle
agreed
Nice video (and hoodie!) :D
thanks! Got it from CERN : )
@@zhelyo_physics was just about to comment I saw them in the shop there on a school trip!
I love the cern hoodie, big fan!
1:33 hello, im confused, shouldn't the force F=mg/sin30 because in the right angled triangle the opposite side is weight(mg) and the hypoteneus is F so since sin=opp/hyp then sin30=mg/F and rearranging gives F=mg/sin30=156.96N ?? pls let me know if im wrong.
no problems! So I have actually filmed this in detail the actual derivation here: th-cam.com/video/GqyI3zl9P_o/w-d-xo.htmlsi=pl2-Kw7M5IRlS_BR. In practice it's worth remembering in the exam that along the slope the component is m*g*sin(theta) Hope this helps!
@@zhelyo_physicsah thank you so much, i didnt see that the weight was acting from the centre pf the box😊
6:54 “The only available force with a component towards the centre is F so F must increase” why is this? Why does it increase?? To stay on the conveyor? Or because it’s turning?…
if it's turning the only thing that can have happened is for the force F to have increased as it's the only force which has a component towards the centre of rotation. Hope this helps!
The mass is constant and so is its weight. Hence Wcos30 and Wsin30 won’t change. So friction F is the only force that can increase and act as a centripetal/resultant force, which causes it to turn!
@@YumnuP legend
Also, is the reason that the vertical component of F must also increase because the vector must stay in the same direction parallel to the conveyor?
So, there must be a force directed towards the centre if it's moving at a circular motion. This has to be from one of the forces present, the only one which has a component directed towards the centre of rotation is F. Hope this helps!
sir could you provide me these questions paper in pdf or you can tell me their year on each questions so i can find them myself thanks
hello, they are linked in the description : ) Hope this helps!
@ thank you so much sir
anytime!
I’m gonna miss hearing your voice in class sir😭
is this in the aqa a level physics paper 1 2024 paper? i remember doing it
@szmasclips1774 it's an OCR paper from 2019, I guess similar questions/situations reappear between exam boards.
@@zhelyo_physics ok thanks very much sir, great video!
Vector triangles are garbage. Resolving forces is the way.
for question (i), i would have thought that r would be 2 / cos(30) due to the angle of the circular motion, could you explain why this is not the case?
excellent question. It's hard to visualise in a comment without a whiteboard, but we are assuming the suitcase rotates around the point directly horizontally across the radius given. And it is not rotating at an angle with respect to a point below it. Hope this helps!
helpful as always, KEEP EM COMING YOU LEGEND 🙏🙏
By the way, whats the official name of these types of questions? i needa practice more on it
thank you so much!
I've a rotational motion question can you please make a solution video of that question I didn't found it's answer anywhere can you help?
sure, I can have a look! I can't promise a solution or a video unfortunately as I'm doing quite a lot of projects at the same time.
@zhelyo_physics ya sure whenever you are free, but where can I send it?
please try sashi bhusan tiwari it has got great problems
Yes agreed😊
thank you for the suggestion!
@@zhelyo_physics if you want I can share the pdf
@@JamesBond-db5zxplease share
Questions looked easy if the basics are known
for real, but when your in exam stress you kind of mess up and make silly mistakes alot
I think the start is quite okay, the last 4 marks are tricky to put into words/what the mark scheme expects exactly.
@@Tin-m5cyeah agreed with that
@@zhelyo_physicsyeah it can be confusing if we couldn't visualise or understand the wording of the question
Please try sashi bhusan tiwarI, DAVID MORINN, KROTOV
Morinn's Classical Mechanics book is one of my favourites! : )
@@zhelyo_physics that's cool sir, even tho I couldn't able to solve much questions from morning books and level 3 of Sashi Bhushan Tiwari but it's pretty interesting in there
What is A level physics?
It's a national exam in Physics in the UK that you undertake after your studies. Hope this helps!