All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Hello, Sir. I'm really grateful you with your job. I just wanted to say Thank so much. Besides that, I have noticed a mistake in this. When you find the Input Impedance, you said that it's 2.8, but it's 2.6 since the chart smith over there goes from 2 in 2 by line. Hope you are fine, and I'll be waiting you answer.
@@EngineeringFunda Oh, well, I'm sorry then. I thought that the line that was before the 3 is 2.8, and the one that is before the 2.8 is 2.6, which is where the interception point is in the video.
When you making Input impedance real why you did not multiplied with Zo here ????? Purposely??? Or you forgot to multiply???? ByTheWay Thank you to My favourite Virtual Teacher ❤❤ keep Going Sir....
Your Appreciations, care and share matters a lot to me. #EnginneringLove. All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Hello, Liran Cohen. Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)
Towards the generator means clockwise rotation. See the question in which it is given that move by 0.1Lambda from the load. Here from the load means towards the generator.
Hello, Pseudo Hawk1. Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)
*🔥All Premium Courses Link of Engineering Funda🔥*
docs.google.com/spreadsheets/d/1LeLxZPGiMB_ZDZggbZp3P7fK516pXYhVgZA__djNkWM/edit#gid=0
Sir videos are super and simple explanations 😍
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Thank you, sir. again a Great lecture
Your positive comments motivates me, Thanks and welcome 🙏
⬇ *Premium Courses of Engineering Funda* ⬇
✅ *༺🚩ARM Processor 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7nFEozQhZDZDSm09SwqbGP.html
✅ *༺🚩Microprocessor 8085 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5vHwmowy_kGtjq9Ih0FzwN.html
✅ *༺🚩Microprocessor 8086 🚩༻* - th-cam.com/play/PLgwJf8NK-2e4oAeDid0hwuiol_RJdscrp.html
✅ *༺🚩AVR Microcontroller 🚩༻* - th-cam.com/play/PLgwJf8NK-2e55CdbY_WnY6pejPHoojCkJ.html
✅ *༺🚩8051 Microcontroller 🚩༻* - th-cam.com/play/PLgwJf8NK-2e49i6neo70aGtFLvKeZ3IQD.html
✅ *༺🚩80386 & Pentium Processor 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7f4yPj6AbrUoburKwX0fFA.html
✅ *༺🚩Embedded System 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5xvXygtghfi-tzyeACx7CO.html
✅ *༺🚩VLSI 🚩༻* - th-cam.com/play/PLgwJf8NK-2e6au9bX9P_bA3ywxqigCsaC.html
✅ *༺🚩Digital Electronics 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7nYSG31YWEUfwgAp2uIOBY.html
✅ *༺🚩Network Theory 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7AccPu8mUhhsJNol9uIKTJ.html
✅ *༺🚩Control Engineering 🚩༻* - th-cam.com/play/PLgwJf8NK-2e43et6qbo4IqYSJCv-6kN90.html
✅ *༺🚩Electromagnetic Theory 🚩༻* - th-cam.com/play/PLgwJf8NK-2e4I_YltJja47CwZJkzNWK89.html
✅ *༺🚩Power Electronics 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5Hnu82T1CYLZ8kbZs4Jx8x.html
✅ *༺🚩Basic Electronics 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5G05PTgyTTSVyzTOKRfmTn.html
✅ *༺🚩Signal and System 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7VdLw7PebRTcZXb_4nKeVh.html
✅ *༺🚩Optical Communication 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7CDIWsh61eItP9iRw1EIQc.html
✅ *༺🚩Analog Communication 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7uyUYrpgUUQowmRuKxRdwp.html
✅ *༺🚩Digital Communication 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5PngHbdEadEun5XPvnn00N.html
✅ *༺🚩Antennas & wave Propagation 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7tzLIDL4aXUbtRFY3ykmkT.html
✅ *༺🚩Microwave Engineering 🚩༻* - th-cam.com/play/PLgwJf8NK-2e6A4Mtxud6xPHE1UecxWsHW.html
✅ *༺🚩RADAR Engineering 🚩༻* - th-cam.com/play/PLgwJf8NK-2e4KmA52Jw3-JhDhFIDQZ9Bv.html
✅ *༺🚩Audio Video System / TV 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7EJcPI0P_DMw49ufTYfuOz.html
✅ *༺🚩Engineering Drawing/ Graphics 🚩༻* - th-cam.com/play/PLgwJf8NK-2e79xuABrIQeXYlGuuickEz7.html
✅ *༺🚩Basic Mechanical Engineering 🚩༻* - th-cam.com/play/PLgwJf8NK-2e7Fe4vAYDaL0bpseGNhc9on.html
✅ *༺🚩Mechanics of Solid 🚩༻* - th-cam.com/play/PLgwJf8NK-2e53xcLCS7ay2iLRolNxyxFk.html
✅ *༺🚩Theory of Computation 🚩༻* - th-cam.com/play/PLgwJf8NK-2e6GfXdwqWX5YmszV2KGv-yl.html
✅ *༺🚩Java Programming 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5BeN1WTXg1ENPtkRR3SfCI.html
✅ *༺🚩Python Programming 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5pY2eB-Lht2_CerQue0Xo4.html
✅ *༺🚩Placement Test series on C 🚩༻* - th-cam.com/play/PLgwJf8NK-2e5ovLgoJkv0Pn58UrucrTPt.html
✅ *༺ Please Share it with your friends to support us. ༻*
👉 *༺ You can also support us by joining us ༻* : th-cam.com/channels/dlnqMpRrMcClK2fT6z8EEw.htmljoin
Amazing Video
Your positive comments motivates me, Thanks and welcome 🙏
great work sir which is very helpfullll!!!!!!
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
very helpful lecture sir......
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Thank you so much sir
Very good video doubt is clear thanks ❤️
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
How did u move and place 0.1 lamba ?
The input impedance is normalized, to find the real value, it needs to be multiplied by z0.
Thank you very much
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
@@EngineeringFunda 🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸🌸🌺🌸🌺🌸
Hello, Sir. I'm really grateful you with your job. I just wanted to say Thank so much. Besides that, I have noticed a mistake in this. When you find the Input Impedance, you said that it's 2.8, but it's 2.6 since the chart smith over there goes from 2 in 2 by line. Hope you are fine, and I'll be waiting you answer.
Solution is perfectly correct as it is computerized solution dear.
@@EngineeringFunda Oh, well, I'm sorry then. I thought that the line that was before the 3 is 2.8, and the one that is before the 2.8 is 2.6, which is where the interception point is in the video.
Sir, why we take load towards the generator to find Vmax and Vmin?
When you making Input impedance real why you did not multiplied with Zo here ????? Purposely???
Or you forgot to multiply????
ByTheWay
Thank you to My favourite Virtual Teacher ❤❤ keep Going Sir....
Actual value will be Zo × Z.
@@EngineeringFunda ok❤️
Tysm
Your Appreciations, care and share matters a lot to me. #EnginneringLove.
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Sir, how can we go towards generator by 0.338*lambda if L=0.1*lambda? it passes it by far.
Hello, Liran Cohen. Hope you are fine. What I understand of this, it's the following:
First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda
Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25.
So,Mathematically speaking you could calculate the location the V_max in this way:
0.25 lambda - 0.162 lambda = 0.088 lambda.
Now, doing this for V_min:
V_min it's opposite to V_max
Then, it's possible to do this:
0.50lambda -0.162lambda= 0.338 lambda
Hope you understand! :)
@@fabregod24very well explained ty ❤
thanks
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
sir could you please tell me that how to calculate vmax 0.88 lamda?in this question
Great lecture! Which software do you use for drawing the VSWR circle and lines?
PPT
How you tell that value of Vmax =0.008 and Vmin value how u calculate sir
Hope you are fine. What I understand of this, it's the following:
First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda
Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25.
So,Mathematically speaking you could calculate the location the V_max in this way:
0.25 lambda - 0.162 lambda = 0.088 lambda.
Now, doing this for V_min:
V_min it's opposite to V_max
Then, it's possible to do this:
0.50lambda -0.162lambda= 0.338 lambda
Hope you understand! :)
sir can you explain how you are moving 0.1lambda value
Towards the generator means clockwise rotation. See the question in which it is given that move by 0.1Lambda from the load.
Here from the load means towards the generator.
@@EngineeringFunda sir how V max is 0.088 lamda !!
@@_KTharun did you solve it? can anyone explain how vmax and vmin calculated? sir please be clear
I want to find input admittance.... whether we can find it extending the line of input impedance
sir please make a video on double stub matching on smith chart
Noted your request
Sir How come Vmax is smaller then Vmin??
Where?
It is location not value
@@EngineeringFunda ok. I got it
Thank u
Sir the distance between load and generator is 0.1
Then how is the V min at a distance of 0.338 from load towards generator
How V max value is 0.088??? Can you explain ..!!
Sir how your measure 0.0338 lembda and all i confused
It's actually 0.088 lambda
It's calculated when u take the distance from zl line on generator to the vmax line
There will be non minimum right? Because 0.388 is not possible on 0.1Lambda line
Hello, Pseudo Hawk1. Hope you are fine. What I understand of this, it's the following:
First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda
Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25.
So,Mathematically speaking you could calculate the location the V_max in this way:
0.25 lambda - 0.162 lambda = 0.088 lambda.
Now, doing this for V_min:
V_min it's opposite to V_max
Then, it's possible to do this:
0.50lambda -0.162lambda= 0.338 lambda
Hope you understand! :)
How 0.088lambda
L=0.1lambda plz reply sir
Data is given in question dear
Hi, how do I find the Zin at the generator?
By moving from the load in clockwise direction we can get Zin
@@EngineeringFunda hi Tks for the response, until which position do I have to move clockwise ? And once I move there how do I find the impedance ?
@@ronaldleon6952 for that I have already made video on smithchart, just go through my playlist
How is Vmax value 0.088 please any explanation
End point minus starting point
Which is 0.25-0.161
how is lamda assumed sir
It is not assumed dear.
how is Vmin larger than transmission line 0.1
It is possible dear
if Z_L = 1+ 1j and Y_L = 1 / Z_L then Y_L = 0.5 - 0.5j not 0.52 - 0.52j
Sir Vmin value is wrong