Smith Chart Example for Transmission line Parameters (VSWR, Reflection Coefficient, Input Impedance)

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  • เผยแพร่เมื่อ 23 ธ.ค. 2024

ความคิดเห็น • 155

  • @EngineeringFunda
    @EngineeringFunda  ปีที่แล้ว +3

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  • @jamiesureshkumar2763
    @jamiesureshkumar2763 3 ปีที่แล้ว +31

    One of the lucid explanations of Smith Chart on TH-cam!! Thankyou Sir!! God bless you!!!

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว +6

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  • @jamgamer
    @jamgamer 9 หลายเดือนก่อน +1

    Most efficient video on learning and reviewing the smith chart

    • @EngineeringFunda
      @EngineeringFunda  9 หลายเดือนก่อน

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  • @smile0619
    @smile0619 ปีที่แล้ว +2

    Wohh kya simple language me explain kiya hai sir app ne...💯❤🙏
    Etna tough topic....😎

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

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    • @smile0619
      @smile0619 ปีที่แล้ว

      @@EngineeringFunda definitely...I'm

  • @benr7867
    @benr7867 ปีที่แล้ว +2

    Thank you for your assistance. You've genuinely helped me figure out an assignment my TA couldn't understand.

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

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  • @dut_uut
    @dut_uut ปีที่แล้ว +1

    ❤❤❤❤❤❤The only video on TH-cam that gives full and necessary information of Smith Chart not roaming here añd there. ❤❤❤❤❤❤❤.

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

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  • @Simon_J_Msenga
    @Simon_J_Msenga 2 ปีที่แล้ว +3

    Thanks for your Assistance...Now I can go to my University Exam

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว

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  • @MICHAELMURITHI-y7y
    @MICHAELMURITHI-y7y 10 หลายเดือนก่อน +1

    Best video on smith chart, thankyou too

    • @EngineeringFunda
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  • @jaliilahyuusuf5756
    @jaliilahyuusuf5756 2 ปีที่แล้ว +4

    Thank u so much am going for an exam now ...
    But uve saved me sir ..
    I really understood it

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว +2

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  • @GokulGokul-iz2to
    @GokulGokul-iz2to หลายเดือนก่อน +1

    Thank you so much from Tamil Nadu

    • @EngineeringFunda
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    • @EngineeringFunda
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  • @NavinYadav79898
    @NavinYadav79898 7 หลายเดือนก่อน +1

    Better explanation thank you sir ❤

    • @EngineeringFunda
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  • @EssayWriting-du3pw
    @EssayWriting-du3pw ปีที่แล้ว +2

    Thank you Engineer

    • @EngineeringFunda
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  • @skks4448
    @skks4448 2 ปีที่แล้ว +2

    Really informative...understood easily

    • @EngineeringFunda
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  • @thelsazzad
    @thelsazzad ปีที่แล้ว +2

    07:06 how did you get L=0.25λ? would you please explain it?

    • @vicallday3325
      @vicallday3325 ปีที่แล้ว +1

      This is luckily discussed in another comment posted earlier

    • @vicallday3325
      @vicallday3325 ปีที่แล้ว +2

      Length in terms of lambda means to express the ratio of length divided by lambda, l/lambda.
      First, solve for lambda and the answer will be some number in SI units, like 10 cm.
      Then, express lambda for 1 cm, rather than 10 cm, as lambda/10 = 1 cm.
      Lastly, plug-in the expression for 1 cm into the length value's unit, as length = 2.5 cm = 2.5 (lambda/10), and this is length in terms of lambda.
      Thanks @kapil1600 ! I followed your idea.

  • @ahsanbaig8569
    @ahsanbaig8569 2 ปีที่แล้ว +2

    Best example ever!

  • @vicallday3325
    @vicallday3325 ปีที่แล้ว +1

    Best of The Best

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว +1

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  • @sitanshupandey9301
    @sitanshupandey9301 2 ปีที่แล้ว +2

    Thank you so much sir for this crystal clear explanation!!

    • @EngineeringFunda
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  • @Bravo_L
    @Bravo_L 2 ปีที่แล้ว +4

    beautiful work thank you professor!!!!

    • @EngineeringFunda
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  • @_SupriyaIngale
    @_SupriyaIngale ปีที่แล้ว +1

    Thank you for the precise lecture, Sir!!
    It really helps alot....

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

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  • @samsunighar8134
    @samsunighar8134 2 ปีที่แล้ว +1

    Sir Really excellent information..Thank you

    • @EngineeringFunda
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  • @shoaibmohammad5652
    @shoaibmohammad5652 2 ปีที่แล้ว +1

    Excellent Explaination Sir

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว

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  • @kamelimoku6025
    @kamelimoku6025 3 ปีที่แล้ว +2

    Great explanation💯

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

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  • @tamziduddin121
    @tamziduddin121 ปีที่แล้ว +1

    Thank you so much from Bangladesh

    • @EngineeringFunda
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  • @euelfantaye1403
    @euelfantaye1403 3 ปีที่แล้ว +9

    Thank you for the clear and precise lectures, sir! You're helping many students.
    About the mobile app, how can IOS users get it?

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว +1

      I have not made it for IOS, sorry but this is free service and IOS is charging for it.

  • @ryansu2254
    @ryansu2254 8 หลายเดือนก่อน +1

    great video!

    • @EngineeringFunda
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  • @akshayapv8774
    @akshayapv8774 3 ปีที่แล้ว +3

    Thank you sir
    Its very clear

    • @EngineeringFunda
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  • @Dude.From.Mars.
    @Dude.From.Mars. 3 ปีที่แล้ว +2

    Sir great video. Subscribed , liked and shared !! Excellent content sir.

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว +1

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  • @ushasr2821
    @ushasr2821 3 ปีที่แล้ว +1

    great help sir.Thank you

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

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  • @nahimulislam9106
    @nahimulislam9106 3 ปีที่แล้ว +1

    thank you.this video very helpful

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

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  • @eliasdetrois
    @eliasdetrois 2 ปีที่แล้ว +1

    Excellent explanation! Thank you

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว

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  • @pavankulkarni544
    @pavankulkarni544 9 หลายเดือนก่อน +1

    nice sir 🙏

    • @EngineeringFunda
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  • @alizashoukat7154
    @alizashoukat7154 ปีที่แล้ว +1

    Perfect 👍

    • @EngineeringFunda
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  • @alsongadizo1692
    @alsongadizo1692 2 ปีที่แล้ว +1

    thankyou sir for the explanation however on finding the wavelength where did the 10 come from

    • @iluvyunie
      @iluvyunie ปีที่แล้ว

      3x10^8/3x10^9 = 0.1m

  • @asish8880
    @asish8880 3 ปีที่แล้ว +2

    If it is towards the generator we have to take VSWR values of left side from center& if it is away from generator we have to take right side values, is it correct?

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

      You should see VSWR on its scale only

    • @asish8880
      @asish8880 3 ปีที่แล้ว

      @@EngineeringFunda which side reading of vswr,can we take for towards lode problems

  • @ayushamanIITB
    @ayushamanIITB 2 ปีที่แล้ว +1

    Sir how do Moving towards the load impedance corresponds to a anticlockwise movement on the Smith chart

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว

      On circle see the scale and move by length in terms of lambda

  • @danu9175
    @danu9175 2 ปีที่แล้ว +1

    Thank you professor ❤️

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว +1

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  • @harshitmishra1261
    @harshitmishra1261 3 ปีที่แล้ว +3

    Great sir thank you

    • @EngineeringFunda
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  • @ibaty
    @ibaty 9 หลายเดือนก่อน

    4:54 drawing line from point you have chosen on the circle to the scales below is wrong. You draw a line from the origin to the point on the circle and then measure this line length with ruler. Place this length onto the scale below and this would be your real reflection coeff value from below scale.

    • @EngineeringFunda
      @EngineeringFunda  9 หลายเดือนก่อน

      This is perfectly correct. 🙏

  • @W8TJM
    @W8TJM 3 ปีที่แล้ว

    Nicely done explanations.

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว +1

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  • @hershebartholomew2534
    @hershebartholomew2534 ปีที่แล้ว

    How did you get the -j0.17 at Zin?

  • @nuruljannah4602
    @nuruljannah4602 ปีที่แล้ว +1

    Thank you😊

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

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  • @jaivikdhebar
    @jaivikdhebar ปีที่แล้ว +1

    Thank you so much❤

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

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  • @VAISHNADEVIGECEUG-
    @VAISHNADEVIGECEUG- 3 ปีที่แล้ว +1

    THANK U SIR🙏🙏

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

      Your positive comments motivates me.
      Teachers like me just wants positive comment from student.
      Love from you guys means a lot to me.
      My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

  • @HeyLee.
    @HeyLee. 4 หลายเดือนก่อน +1

    Perfect ❤

    • @EngineeringFunda
      @EngineeringFunda  4 หลายเดือนก่อน

      Your Appreciations, care and share matters a lot to me. #EnginneringLove.
      All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
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  • @jamshirtangri5757
    @jamshirtangri5757 3 ปีที่แล้ว +1

    Thank you so much sir

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

      Your positive comments motivates me.
      Teachers like me just wants positive comment from student.
      Love from you guys means a lot to me.
      My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

  • @kousartajpatan5643
    @kousartajpatan5643 2 ปีที่แล้ว +1

    Thank you sir

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว

      Your positive comments motivates me.
      Teachers like me just wants positive comment from student.
      Love from you guys means a lot to me.
      My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

  • @drazynx
    @drazynx ปีที่แล้ว +1

    Thank you!

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

      All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
      Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏

  • @ramrathod07
    @ramrathod07 4 หลายเดือนก่อน

    Sir in step 3 we take c as 3*10^8 not 10^10
    as speed of light in vaccum we take c=3*10^8

  • @namugwanyamarypatience7039
    @namugwanyamarypatience7039 3 ปีที่แล้ว +2

    Isn't VSWR equal to 2.3?

  • @happeningnaija1492
    @happeningnaija1492 3 ปีที่แล้ว +1

    How did you get the 10cm? I still don't get that part

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว +4

      C = 3 × 10^8 and F = 3 × 10^9 Hz.
      So lamba = C/F = 0.1m = 10cm

    • @happeningnaija1492
      @happeningnaija1492 3 ปีที่แล้ว

      @@EngineeringFunda Thanks for the clarity 🤗

    • @rickysambora8321
      @rickysambora8321 3 ปีที่แล้ว

      @@EngineeringFunda do we always use C/F to calculate the lambda? are there alternatives formula?

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

      @@rickysambora8321 c/f is wavelength

    • @DAVID-fp8em
      @DAVID-fp8em 9 หลายเดือนก่อน

      @@EngineeringFunda but speed of electromagnetic wave, c = 3*10^8 m/s

  • @mahaboobbasha123
    @mahaboobbasha123 ปีที่แล้ว +1

    Thanks sir

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

      All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
      Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏

  • @wilbertpayamps1115
    @wilbertpayamps1115 3 ปีที่แล้ว +1

    THANK YOUUUUUU!!!!!

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

      Your positive comments motivates me.
      Teachers like me just wants positive comment from student.
      Love from you guys means a lot to me.
      My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

  • @mahaboobbasha123
    @mahaboobbasha123 ปีที่แล้ว +1

    Sir I subscribed ur channel
    Can u help to know how to make app and upload in playstore
    I wNa make some apps to be useful maybe

  • @sherwinmolit199
    @sherwinmolit199 8 หลายเดือนก่อน

    can i ask how did they get this answer from Zin? -j0.17

  • @zongyinchi2956
    @zongyinchi2956 3 ปีที่แล้ว +1

    Thank you!!!

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

      Your positive comments motivates me.
      Teachers like me just wants positive comment from student.
      Love from you guys means a lot to me.
      My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

  • @innocentheart9609
    @innocentheart9609 ปีที่แล้ว +1

    Where can I download PDFs

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

      On my Android Application Engineering Funda

  • @zaheerullah6337
    @zaheerullah6337 3 ปีที่แล้ว

    Assalam o alaikum,how can we draw a lamda value from a given length even though clock wise or anti clock wise ,,,
    Is we subtract or adding lamda value, please guid ??

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว +2

      Lambda can be calculated from frequency.
      Length should get normalized in terms of lambda.
      Eg. If length is 5cm. Frequency is 3Ghz, then lambda = c/f = 10cm.
      Then length = (5/10) lambda = 0.5 lambda.
      Towards the generator is clockwise and towards the load is anticlockwise.

    • @zaheerullah6337
      @zaheerullah6337 3 ปีที่แล้ว +1

      @@EngineeringFunda so how can we draw at circle in Smit chart even though a point value is 2+1.8j so at last point any value at intersection,how this .5lamda added or subtracted and how distance we will covered by compass

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว +1

      @@zaheerullah6337 I have many videos on smith chart go through it and I am sure will get everything

    • @zaheerullah6337
      @zaheerullah6337 3 ปีที่แล้ว +1

      Sir I have downloaded your 13 videos on Smit chart but I don't clear concept at lamda ,how we calculated

    • @zaheerullah6337
      @zaheerullah6337 3 ปีที่แล้ว +1

      Please make one video on them,I will Very thankful,I like your teaching very much

  • @ketanpatil5121
    @ketanpatil5121 3 ปีที่แล้ว

    a transmission line with charetericstics impedance of 692 angle -120 is terminated in 200 ohm resister determine reflection coeeficent and swr used smith chart
    plz solve this problem quickly

  • @AKLESHKUMAR-dr3vm
    @AKLESHKUMAR-dr3vm 3 ปีที่แล้ว +19

    l=0.25*lemda how ??

    • @saisricharankasula5850
      @saisricharankasula5850 3 ปีที่แล้ว +9

      10cm we got and we know that cm=10^-² so 2.5×10^-² is l=0.25

    • @davidjonesgaming5594
      @davidjonesgaming5594 ปีที่แล้ว +1

      Come to near me i will show

    • @Gurpreetsingh2727
      @Gurpreetsingh2727 ปีที่แล้ว +1

      2.5 X 10^-2 is 0.025

    • @kapil1600
      @kapil1600 ปีที่แล้ว +13

      Lemda=10cm
      So, 1cm= Lemda/10.
      Now, length=2.5cm or 2.5x1cm.
      Put 1cm value here.
      Length=2.5xLemda/10
      Length=0.25Lembda

    • @n_fieldgaming
      @n_fieldgaming 10 หลายเดือนก่อน +1

      10 cm. .....= 1 Lambda
      1cm ........=1/10 Lambda
      2.5 cm.......=2.5/10 Lambda
      =0.25 Lambda
      ........,..................................
      .................. understand?

  • @ss-es1xo
    @ss-es1xo 2 ปีที่แล้ว +1

    How lamda is 10 Cm

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว

      From Frequency we can calculate it as per Lamda = C / Frequency

  • @iclassic94
    @iclassic94 ปีที่แล้ว +2

    Deeper the accent. Harder it gets

    • @vicallday3325
      @vicallday3325 ปีที่แล้ว

      Go to another video, then, sir

  • @mrinnervoice9035
    @mrinnervoice9035 3 ปีที่แล้ว

    Calculation of lambda? Can u explain?

  • @atambaasiimwe9618
    @atambaasiimwe9618 ปีที่แล้ว

    I can hardly stretch the straight line

  • @jannatul_tamanna
    @jannatul_tamanna 2 ปีที่แล้ว +1

    Input impedance didn’t understand

  • @ZollMisc-c1w
    @ZollMisc-c1w 3 หลายเดือนก่อน

    Chadrick Gardens

  • @CaptainIndia-jt8sc
    @CaptainIndia-jt8sc ปีที่แล้ว +1

    Sexy explanation as always 🔥🔥

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

      Your Appreciations, care and share matters a lot to me. #EnginneringLove.
      All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
      Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏

  • @Rohit45230
    @Rohit45230 11 หลายเดือนก่อน

    Please talk in Hindi for better understanding 🙏

    • @EngineeringFunda
      @EngineeringFunda  11 หลายเดือนก่อน

      My hindi is very bad and I am only conformable with English language. Believe me, engineering learning is good with English language only.

    • @roluahpuiajathang618
      @roluahpuiajathang618 9 หลายเดือนก่อน

      Anyone who doesn't know hindi! How can they understand 🤣

  • @AgnesBoyd-w9s
    @AgnesBoyd-w9s 2 หลายเดือนก่อน

    Adrien Estate

  • @ConnieBlake-r3p
    @ConnieBlake-r3p 3 หลายเดือนก่อน

    Rowe Mall

  • @swapnanenavath8271
    @swapnanenavath8271 3 ปีที่แล้ว +1

    Clrty ledu padu chii ne explanation tagalayya

  • @sudeepkulkarni7593
    @sudeepkulkarni7593 3 ปีที่แล้ว +1

    Your great sir, thank you so much🙏🙏

    • @EngineeringFunda
      @EngineeringFunda  3 ปีที่แล้ว

      Your positive comments motivates me.
      Teachers like me just wants positive comment from student.
      Love from you guys means a lot to me.
      My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.

  • @rutujasandbhor1077
    @rutujasandbhor1077 2 ปีที่แล้ว +1

    Thank you sir

    • @EngineeringFunda
      @EngineeringFunda  2 ปีที่แล้ว

      All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
      Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏

  • @Absolutes.2
    @Absolutes.2 ปีที่แล้ว +1

    Thank you sir

    • @EngineeringFunda
      @EngineeringFunda  ปีที่แล้ว

      All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
      Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏