SAT - Remainder Questions

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  • เผยแพร่เมื่อ 23 ธ.ค. 2024

ความคิดเห็น • 65

  • @katy1by6
    @katy1by6 10 ปีที่แล้ว +7

    man, i thought remainders were the toughest shit to figure out!!! but they're SOOO EASY now that you've explained it!

  • @ahmedabdulla1568
    @ahmedabdulla1568 9 ปีที่แล้ว

    I will tell all my friends to follow you , you deserve it !!

    • @RadicalPrep
      @RadicalPrep  9 ปีที่แล้ว +1

      Ahmed Abdulla thanks a lot, hope you did well on your exam

  • @bregychow1584
    @bregychow1584 12 ปีที่แล้ว

    thanks for your help, this really boost my morale, I thought these questions were like messing up my rhythm in the SATS.

  • @marconeves9338
    @marconeves9338 11 ปีที่แล้ว

    i'll just watch a bunch of your videos like a day before the test so i can remember your examples and tips

  • @romulonasc
    @romulonasc 5 ปีที่แล้ว

    Abou the last exercise in which you affirm that x*y > 6, I disagree because the number 4 is a counterexample, since 4 divided by 5 is 0 and the remainder is 4. So there is a number that is less than 6 and still the remainder of the integer division by 5 is 4.

  • @trueMoney11
    @trueMoney11 10 ปีที่แล้ว +2

    For the last question i was puzzled!... The answer you said was xy>6... But what if xy is 7(which is greater than 6) should that be false as well?

    • @mukundprabakar780
      @mukundprabakar780 10 ปีที่แล้ว +3

      when he says that xy>6, he means that xy has to be above 6, but that doesn't mean it is ALL the numbers above 6, only the ones that apply. For example, he showed that if xy = 19, the remainder is 4, so it works. At the same time, if xy = 7, like you say, then the remainder is 2, so it doesn't work. The question asks you to assume that the numbers in question all lead to remainder 4 when divided by 5.

  • @waseemq1522
    @waseemq1522 4 ปีที่แล้ว

    should I check or is it always correct

  • @TheFran34
    @TheFran34 11 ปีที่แล้ว

    how did it go?

  • @Dakota2147
    @Dakota2147 13 ปีที่แล้ว

    man you make it look so easy

  • @jonohashmo849
    @jonohashmo849 10 ปีที่แล้ว

    i have a question. i have a question here that reads
    "when 15 is divided by the positive integer k, the remainder is 3. for how man different values of k is the this true?"
    i was wondering if you had any tips on how to solve this without trying to list all the possible numbers..?
    thanks for your help

    • @salsadancer00
      @salsadancer00 9 ปีที่แล้ว

      Jonathan Hashmonay I remember this question from the SAT Blue Book and I don't think there's a better way to do the problem other than quickly running through the numbers up to 15.

    • @jim73527
      @jim73527 9 ปีที่แล้ว

      +Jonathan Hashmonay
      15-3 is 12, so any factors of 12 will work, 12,6,4,3,2,1. However, the remainder is 3, so 1,2,3 will never have a remainder of 3. so 12,6,4 are the answers.

  • @EytanWallace
    @EytanWallace 12 ปีที่แล้ว

    also, on the last one, can't you just read the options and identify the last one is impossible right away?

  • @mcreator2151
    @mcreator2151 9 ปีที่แล้ว

    At the last why E? 7 and 8 does not work.If I started at E, I could easily cross out E and go for D. Reply would be grate.

  • @EytanWallace
    @EytanWallace 12 ปีที่แล้ว

    Can number one also equal 7?

  • @QINNIYQ
    @QINNIYQ 9 ปีที่แล้ว +1

    What about the fact that you subtracted when the variable was on the bottom and then you added when the variable was on top.

    • @mustardscroll7
      @mustardscroll7 9 ปีที่แล้ว +1

      QINNIYQ Interesting thing, you actually don't have to add when the variable is on top--you can subtract in both scenarios. If you chose to subtract in the second problem, it would look like this:
      k - 2 / 3 = 2
      k = 8
      and 8 divided by 3 still gives a valid remainder of 2
      2k = 16
      and 16 divided by 3 also gives a remainder of 1
      Not sure why he chose to add :T

  • @gamernr247
    @gamernr247 11 ปีที่แล้ว

    Great tutorials, keep up the good work!
    There's one little thing that I don't get though:
    What if you would divide 4 by 5? (xy = 4)
    Wouldn't that end up with 0 rem 4?

    • @romulonasc
      @romulonasc 5 ปีที่แล้ว

      I totally agree

    • @moeberry8226
      @moeberry8226 2 ปีที่แล้ว

      The answer to this question is no solution. None of these statements are true.

  • @ayanafletcher7897
    @ayanafletcher7897 9 ปีที่แล้ว

    for the K divided by 3 problem.
    I got 14 divided by 3 equals remainder 2
    2(14)=28
    28 divided by 3 equals remainder 1
    Is it still right?

  • @salsadancer00
    @salsadancer00 9 ปีที่แล้ว +1

    For the last one, xy could equal 4. 5 goes into 4 zero times with a remainder of 4. If you wanted to fix this problem you could say that x and y must be unique numbers.

    • @bremulate5318
      @bremulate5318 9 ปีที่แล้ว

      salsadancer00 it still wouldn't work; 4 = 4x1 .: x & y are unique

    • @salsadancer00
      @salsadancer00 9 ปีที่แล้ว

      Samuel Hošovský you're right. This problem's screwed!

  • @FsimulatorX
    @FsimulatorX 9 ปีที่แล้ว +1

    Here is one I found
    Step 1: Perform the division in your calculator: 14/4 = 3.5
    Step 2: Multiply the integer part of this answer by the divisor: 4*3 = 12
    Step 3: Subtract the above result from the dividend to get the remainder:
    14 - 12 = 2.
    Thus the remainder is 2.

  • @hipgirl25
    @hipgirl25 12 ปีที่แล้ว

    got a 510 need a 700 in two days. THANK YOU SIR

  • @suyashpanthi6540
    @suyashpanthi6540 9 ปีที่แล้ว

    if 16 is divided by 6 then the remainder is still 4... can this one be correct???

  • @nicolesmith2782
    @nicolesmith2782 10 ปีที่แล้ว

    This helped a lot!!Thank you c:

  • @FusionX65
    @FusionX65 10 ปีที่แล้ว +1

    for the last question, the correct answer is a rather than e in my opinion

  • @ahmadsaeed3864
    @ahmadsaeed3864 10 ปีที่แล้ว +1

    I think in the last question (e) option i.e xy>6 is also wrong RadicalPrep

  • @SweetieXoX27
    @SweetieXoX27 11 ปีที่แล้ว

    Thank you so much!

  • @TheGamingGrunts
    @TheGamingGrunts 11 ปีที่แล้ว

    I understand it now, but once I take the test I'll probably forget these techniques :P

  • @ronaksteal
    @ronaksteal 11 ปีที่แล้ว

    1 is the remainder when 10 ism divided by 3. 9/3 is 3 and then 1 is left over

  • @CatchHellMoto
    @CatchHellMoto 12 ปีที่แล้ว +1

    I always get these wrong, thanks!

  • @KissTheR1an
    @KissTheR1an 9 ปีที่แล้ว

    Thank you so much!! :)

  • @rosemaryochoa5911
    @rosemaryochoa5911 9 ปีที่แล้ว

    5/3 is not giving me a remainder of 2, it's giving me 1.6 please explain, thank you D:

    • @fervunk1143
      @fervunk1143 9 ปีที่แล้ว

      +Rosemary Ochoa lol. remainder only is given when you do LONG division. he said in the video to not use the calculator. it wont give you the remainder

    • @rosemaryochoa5911
      @rosemaryochoa5911 9 ปีที่แล้ว

      +Frank Lopez OMG i feel dumb. I was stressed out when xD thank you

    • @fervunk1143
      @fervunk1143 9 ปีที่แล้ว +1

      +Rosemary Ochoa no problem. good luck on the test, im taking mine tomorrow lol

    • @rosemaryochoa5911
      @rosemaryochoa5911 9 ปีที่แล้ว

      +Frank Lopez me too, I don't feel prepared at all, but lets do it. hope you do great too

  • @helloitsme.8264
    @helloitsme.8264 10 ปีที่แล้ว

    Hey guys think about the first question. The value of x can be 6 as well. Six times two equals 12 leaving a remainder of 4. So the value of x+1 can also be 7.

    • @bremulate5318
      @bremulate5318 9 ปีที่แล้ว

      Aditya Ram that is correct. There are infinite possible answers for that question but it asked which number is one of the possibilities.

    • @happyguy650
      @happyguy650 9 ปีที่แล้ว

      Samuel Hošovský sorry but i think x can take only two values 6 and 12 to satisfy the above condition not infinite values... cheers

  • @Shuru10
    @Shuru10 11 ปีที่แล้ว

    I still don't understand the last one. Like, it says which of these must be true? But aren't they all true? Kind of a stupid question for me to ask though. Should know by now. :/

  • @RB3Vids
    @RB3Vids 11 ปีที่แล้ว

    The last one was probably the easiest :)

  • @alaness31
    @alaness31 13 ปีที่แล้ว

    the last one in my opinion was easy 6 divided by 5 can never have a remainder of 4, so it had be be higher.

  • @planetpeter917
    @planetpeter917 12 ปีที่แล้ว

    the last example was actually wrong. xy can equal 4. 4 divided by 5 yields a remainder of 4.

  • @samwebber2668
    @samwebber2668 9 ปีที่แล้ว +1

    Cant XY = 4? X=4 Y=1
    XY/5 = 0 remainder 4

  • @pleeppleep
    @pleeppleep 12 ปีที่แล้ว

    What if, for the last problem, xy = 4? 5 divides evenly into zero, which is 4 less than 4. I believe you got that wrong. The correct answer was F) None of the above.

  • @ksnarayanan5281
    @ksnarayanan5281 6 ปีที่แล้ว

    Last question : 4 divided by 5 gives remainder of 4.
    So xy > 6 CANNOT be the answer.
    According to me, Option A is the correct answer because 9/5 definitely gives a remainder of 4.

  • @Shuru10
    @Shuru10 11 ปีที่แล้ว

    Oh wow. I just realized why I didn't get it. It's cuz' it HAS to be it. Wow.

  • @marshallhyasi6213
    @marshallhyasi6213 10 ปีที่แล้ว

    thx alooot

  • @kimmykyms
    @kimmykyms 12 ปีที่แล้ว

    the first problem i divided 16 by 6 and got a remainder of 4 and got x+1=7

  • @bloomprinceton
    @bloomprinceton 11 ปีที่แล้ว +1

    EXAM TOMORROWWWWWWWW YIKESSSSSSSSSSSSSS

  • @Syvmana
    @Syvmana 12 ปีที่แล้ว

    I was doing this question with my brother who had a 600 on the Math Portion on the SATs and this got him angry . Lol

  • @Minecrafter289
    @Minecrafter289 11 ปีที่แล้ว

    SAT tomorrow damn im scared

  • @escarface
    @escarface 10 ปีที่แล้ว

    I am lost with number 1

  • @HateItOrLoveIt101
    @HateItOrLoveIt101 12 ปีที่แล้ว

    Omg you rule

  • @MegaSuperfab
    @MegaSuperfab 12 ปีที่แล้ว

    i understand it. its not that hard.

  • @meetadityanihlani
    @meetadityanihlani 10 ปีที่แล้ว

    these questions are WAYYYYYY to easy for me.
    You know why? Because i'm an Indian and India is in Asia.
    (no squinty eyes though)

  • @Bianca-ol7wz
    @Bianca-ol7wz 10 ปีที่แล้ว

    can you be a teacher at my school please we'll pay you with money and food

  • @mrsmileycorps
    @mrsmileycorps 11 ปีที่แล้ว

    no lol because 5 doesn't fit in 4, you have no remainder