🔴IMPORTANT: A small correction: while calculating the absorption cross-section at the end of the first video, one has to divide it by 1.33, refractive index of water. So the formula to insert at global evaluation would be sigma_abs/1.33.
As you mentioned, we did, but the absorption cross section with the wavelength does not shift depending on the particle size, and only the intensity of the absorption cross-section increases. I would like to as if there is anything I need to change.
Is it matching with an analytically calculated spectrum (my Mie solution) of the nanoparticle? Thats the first point to check accuracy. If it does, changing size should change the spectrum? What kind of sizes are you simulating?
Sir i have a question regarding cross section. what if i am calculating for the cube, would the heat rate still be the cross section of cube? i am wondering if i could still use cross section value for cube or octahedron colloids.
Hello, normally the absorption cross section is the amount of energy absorbed in terms of the area equivalent of intensity. So indeed, you need to calculate the absorption cross section of the structure you are interested in and then multiply it with the applied intensity to find the energy abosrbed. Be sure to be consistent with the units. Hope it helps!
Something I realized later.. I didn't have a proper microphone at that time and just recorded the whole thing at one go with my headphone microphone.. too long to re-record although I have a condenser microphone now. 😐 May be I will do something similar in the future..
@@riturajborah382 Sure, we will be glad if you do something similar. Also, I wanted to see how the temperature profiles (line graphs are computed as shown in the paper ) but you showed the "heat map" instead. Next time, you might consider adding the line graphs to your video. Thanks
🔴IMPORTANT: A small correction: while calculating the absorption cross-section at the end of the first video, one has to divide it by 1.33, refractive index of water. So the formula to insert at global evaluation would be sigma_abs/1.33.
Great work. One comment: please don't use music in the background. But if you insist, please lower its volume. Bests.
thank you for the simulation.
good job
Thank you! :D
As you mentioned, we did, but the absorption cross section with the wavelength does not shift depending on the particle size, and only the intensity of the absorption cross-section increases. I would like to as if there is anything I need to change.
Is it matching with an analytically calculated spectrum (my Mie solution) of the nanoparticle? Thats the first point to check accuracy. If it does, changing size should change the spectrum? What kind of sizes are you simulating?
please provide PDF based on waste water treatment by nano membrane ,its simulation by comsole
Hello, can you send me the analytical solution, diagram and conclusion🙏🙏
Sir i have a question regarding cross section. what if i am calculating for the cube, would the heat rate still be the cross section of cube? i am wondering if i could still use cross section value for cube or octahedron colloids.
Hello, normally the absorption cross section is the amount of energy absorbed in terms of the area equivalent of intensity. So indeed, you need to calculate the absorption cross section of the structure you are interested in and then multiply it with the applied intensity to find the energy abosrbed. Be sure to be consistent with the units. Hope it helps!
Since I am getting a lot of queries asking for the optical constants of Au. They can be found in Johnson and Christy 1972 Physical Review B. But for the lazy ones, here are the constants :
n
187.8548501 1.28
191.629368 1.32
195.2507103 1.34
199.331513 1.33
203.2527886 1.33
207.3314399 1.3
211.9388052 1.3
216.3773142 1.3
221.400359 1.3
226.2485421 1.31
231.313808 1.3
237.063482 1.32
242.6305305 1.32
248.9642592 1.33
255.1115248 1.33
261.5700444 1.35
268.9462062 1.38
276.1340781 1.43
284.3674336 1.47
292.4155685 1.49
300.9325269 1.53
310.737346 1.53
320.3726126 1.54
331.508559 1.48
342.497793 1.48
354.2405745 1.5
367.9056411 1.48
381.4898494 1.46
397.3852598 1.47
413.2806702 1.46
430.5006981 1.45
450.8516402 1.38
471.4228177 1.31
495.9368043 1.04
520.9420213 0.62
548.6026596 0.43
582.085451 0.29
616.8368212 0.21
659.4904312 0.14
704.4556879 0.13
756.001226 0.14
821.0874243 0.16
891.9726695 0.17
984.0015957 0.22
1087.580711 0.27
1215.531383 0.35
1393.080911 0.43
1610.184429 0.56
1937.253142 0.92
k
187.8548501 1.188
191.629368 1.203
195.2507103 1.226
199.331513 1.251
203.2527886 1.277
207.3314399 1.304
211.9388052 1.35
216.3773142 1.387
221.400359 1.427
226.2485421 1.46
231.313808 1.497
237.063482 1.536
242.6305305 1.577
248.9642592 1.631
255.1115248 1.688
261.5700444 1.749
268.9462062 1.803
276.1340781 1.847
284.3674336 1.869
292.4155685 1.878
300.9325269 1.889
310.737346 1.893
320.3726126 1.898
331.508559 1.883
342.497793 1.871
354.2405745 1.866
367.9056411 1.895
381.4898494 1.933
397.3852598 1.952
413.2806702 1.958
430.5006981 1.948
450.8516402 1.914
471.4228177 1.849
495.9368043 1.833
520.9420213 2.081
548.6026596 2.455
582.085451 2.863
616.8368212 3.272
659.4904312 3.697
704.4556879 4.103
756.001226 4.542
821.0874243 5.083
891.9726695 5.663
984.0015957 6.35
1087.580711 7.15
1215.531383 8.145
1393.080911 9.519
1610.184429 11.21
1937.253142 13.78
For the thermal simulations, you just need to fill in the constants from the video.
Hi i ask for your help
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Please stop background music😢
the background sound is nothing but a distraction
Something I realized later.. I didn't have a proper microphone at that time and just recorded the whole thing at one go with my headphone microphone.. too long to re-record although I have a condenser microphone now. 😐 May be I will do something similar in the future..
@@riturajborah382 Sure, we will be glad if you do something similar. Also, I wanted to see how the temperature profiles (line graphs are computed as shown in the paper ) but you showed the "heat map" instead. Next time, you might consider adding the line graphs to your video. Thanks