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Factor to [(b-4)^2-2^2][(b-4)^2+2^2]=0. Write the second factor as [(b-4)^2-(-2^2)]. Factor again to (b-4-2)(b-4+2)(b-4-2i)(b-4+2i)=0. Read out the four solutions: {6,-2,4+2i,4-2i}.
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This is the most complicated solution I ever saw to a simple task like this
no, this is easy dear
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@@AsadInternationalAcademy Of course this is easy. That's why that explaination is too complicated, lol
(b-4)⁴ = 16
(b-4)⁴ = 2x2x2x2
(b-4)⁴ = (2)⁴
b-4 = 2
b = 2 +4
b = 6 ✓
---------------
(b-4)⁴ = 16
(b-4)⁴ = -2x-2x-2x-2
(b-4)⁴ = (-2)⁴
b-4 = -2
b = -2 +4
b = 2 ✓
----------
You missed the other solutions, which can be found using b-4 = 2i and b-4 = -2i. There are four solutions, as expected for a quartic equation.
good job dear
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yes
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b-4= 2 ==> b=6
b-4=2i ==> b=4+2i
b-4=-2 ==> b=-2+4=2
b-4=-2i ==> b=4-2i
Vote for Pedro
ok
Lety= b-4 then y ^4 =16 3:35 3:35 conclude y = 2 or 2* e^( j* pi/2) or y=-2 last solution. Y= 2 * e^(j*3/2pi) then b= y+4
Thats all
thanks dear
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Factor to [(b-4)^2-2^2][(b-4)^2+2^2]=0. Write the second factor as [(b-4)^2-(-2^2)]. Factor again to (b-4-2)(b-4+2)(b-4-2i)(b-4+2i)=0. Read out the four solutions: {6,-2,4+2i,4-2i}.
thank you so much dear
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B=6
genau! Und das im Kopf😁
ok dear
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(b-4)^4 = 16
(b-4)^4 = 2^4
(b-4) = 2
b = 2 + 4
b = 6
Or b = 2
fantastic job dear
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(b-4)^4=16
(b-4)=2 or (-2)
b=6 or b=2
great job, thanks
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16= 2^4 ~ (b-4)= 2
Dans R, oui...
thanks a lot dear
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b=6
beautiful dear
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Qu'est-ce que c'est que cet accent atroce en anglais ?
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easy english dear
b=6 stop haha😂😂😂
ok dear
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B=6
nicely dear
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