Free Body Diagrams - Tension, Friction, Inclined Planes, & Net Force
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- เผยแพร่เมื่อ 2 ต.ค. 2024
- This physics video tutorial explains how to draw free body diagrams for different situations particular those that involve constant velocity and constant acceleration. It explains when to uses forces such as tension, static and kinetic friction, gravity / weight force, and the normal force. Examples include hanging masses, inclined planes, and so much more.
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PDF Worksheet - 10 Practice Problems:
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Forces - Formula Sheet:
bit.ly/4duMv3W
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• Free Body Diagrams - T...
Note: For problem 3d, I forgot to add Fg = mg sin(theta)
Forces - Formula Sheet: bit.ly/4duMv3W
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Direct Link to The Full Video: bit.ly/3Gicv49
on the last question with the rope isnt T=Fk + mgsin(theta)
Can you teach also the Mechanics Engineering 1 and 2?? thanks! 💕
@@drewot9790 I was wondering the same. I was just about to sign up on Patreon until I saw that!
if all the forces are equal how is the box moving
@@Chupappi69 Newtons first law and rules of equilibrium
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Assumptions aren't real
@@RalphC872_e4you and your profile are the embodiment of everything you don't want to be as a person
@@RalphC872_e4I’m trying to revise for my exams, calm down
Hahaha
HAhahaha. I agree , this guy is awesome
I should be paying you for my engineering degree at this point. you teach me more than my professors do.
Freshman in engineering right now - this guy is the only reason I'm passing the weed out classes lol
you do this in engineering classes? I'm doing this in grade 11 physics
@@greenz3480 i’m doing this in 9th grade physics 😭😭😭
Yes, you do this in high school physics courses and in engineering courses in uni. Free body diagrams are the standard for calculating forces in static equilibrium and objects in motion by both engineers and physicists so of course you will see it in entry physics course and entry engineering courses, all the way to more integrated courses like when you start looking at systems as a whole.
@@greenz3480 no matter what grade you are in it's important to always review the basics because they are the foundation of the complex systems
Wow, this is crazy. We just started free body diagrams in class and as always, I check if The Organic Chemistry Tutor has a video and BOOM he made one 2 days ago!
The timing of these vids is amazing
Honestly
my life would be drastically different if these videos didn't exist
Great to see arushi after long time....
And coincident on youtube 🤧
Just wanted to drop my thanks. Doubling up on AP Chemistry and AP Physics C and the teachers haven't been too thorough. Thank you for this simple yet elegant explanation. My gratitude is immeasurable.
Thank you, you are one of the reasons of my academic success.
I didnt understand the last illustration. Shouldnt it be "T - mgsin× - Fk" because there is also an x-component of the weight force?
Yes, there should also be the x-component of gravity.
I take chemistry and physics. Whenever I search for a video on any topic, one of your videos is always there! Real life saver
Did a much better job of explaining this than my professor, took an hour to get through but I'm much more comfortable with the topic now.
Aren't there any gravitational force in the last diagram, or you included it in with the frictional force itself
In the last example Wsin theta also needs to be considered
I was gonna say the same
In 3(d), why Fg disappeared as a force acting on the box?
at the end you forgot about Fg, it suppose to be T= fk + Fg
I think the same. But when adding the Fg, how will the forces along the X-axis be balanced since there is a constant velocity?
For the last example, isn't there also a portion of gravity pulling the object down? So the tension force is overcoming both that and kinetic friction?
Yeah I believe so,
The final equation will be:
T = µkmgcos() + mgsin()
Ok that's what I thought too
Seriously I have been watching since 2018 and I say NO Teacher in the whole world can compare "JG".
Perfect timing, Right when the other free body diagram video got deleted, this was uploaded.
the final case you forgot the component of weight force in x direction
exactly !
I was about to point out until saw your comment
:)
Would the last example not have an x component of gravity acting against tension?
Honestly I was thinking of the exact same thing, in similar cases in other videos he expresses the x component of the weight force + the kinetic opposing the tension force
@@edwinmensah7023 that might be when the block is sliding down the slope instead of being pulled up the slope? I would'nt know, I'm a geology major.
I'm a bit confused about problem D at 29:38. Here the component of weight parallel to the incline (Fg) was not taken into account; was that intentional? Great video by the way :)
Its because the velocity is constant
That sine component of the weight should have been added to the kinetic friction to make the tension. 👌
Great video though.
for the last problem on the incline with the rope pulling the box up wouldn't tension force be the component of gravitation force plus static friction you only included static friction?
My tuition money should be going to you!
Thanks, O-chem Tutor! ❤
The G.O.A.T, thank you for everything!
What a coincidence !!
I just learned this from my teacher a hour ago and this video came up in my youtube feed. Is life really a simulation??
Well actually, the OP is educated, so he knows when and what people are learning, and posting about what people just learned about really catches the views
Also this is like classical mechanics with out calc and one less demension usually
i have tried many times to understand this, asked my lecturer multiple times, but u explained them in much greater detail, thank you... it's a struggle for me to understand the concept of this
U ARE literally an exemplary teacher
wow this is the english tutor i was loooking for
TH-cam is filled with hindi tutors
This is a reupload right. I remember watching the original video back then that was an hour long. The hour long video is now member only.
That sucks.
Sir in problem no. (e) , the acceleration is constant then the net force in the direction of X must be 0 , so why did you draw bigger magnitude of tension T , won't it be as equal as kinetic friction (FK)
There is no net force if VELOCITY, not acceleration, is constant.
Hey tutor I love ur videos but can you increase the volume in which you speak its extremely hard to hear what your saying sometimes, even with headphones.
very thankful for this really helped me study for precomps
=)
i love you for saying this
In 30:00 of the video isn’t mgcosx missing!!
on 3d you forgot to add wx to the forces resisting tension
We can hardly read the question.
You saved me i have an exam rm
how a man could be good at every course?
@30:17 There is a big mistake. I believe because you are running out of time. The Tension is calculated as following: (mgsin A+Fs=T).
you mean mgsin A + Fk = T because there is constant velocity therefore there is kinetic friction.
@@zaidahmed6622 Fs for part B Fk for part A . You missed the point that the mistake occurred when (mgsinA) was not considered in sigmaF .
love you man
I’m soooo mad this would have been great two marking periods ago
I stopped going to confusing lectures and decided this will be my new Physics professor.
Wow free body diagram is important. If get wrong or don’t know how to read the diagram or do then that’s it can forget about the rest of the other steps.
I need this and several other videos you’ve made…I can pick up on things fairly quickly and your videos slowly explain everything so thoughtfully that it’s impossible for me to misinterpret your explanations. I take a test tomorrow to qualify for a nuclear power job for the navy….thank you for these teachings!!
hope your test went well!!
Brother I am studying for the NUPOC phone interviews and DC interviews too!! I wish you the best of luck man!!
The last question part (d), T=mg*sin+fk
Why don't we have Fg on an upward incline(the last question where you have the tension force)
wondering this as well
Same, I'm confused about this part. Isn't the rope pulling not just against friction, but against gravity trying to drag the block down the ramp as well?
@@thedogdogification probably he forgot to seperate the weight into its components in the diagra.
Yeah i believe there was a mistake in the video
hey don't worry.....There's a mistake in last part....
he forgot to resolve the weight component !
20:00 aren't Fg and W the same thing? I'm lost
He meant a component of W
if only i started reviewing 5 days earlier
i would understood the needed lessons in my physics exam through his vids
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"Why do you call me 'Lord, Lord, ' and do not do what I say?
I will show you what he is like who comes to me and hears my word and puts them into practice. He is like a man building a house who dug down deep and laid a foundation on rock. When the flood came, the torrent struck that house but could not shake it, because it was well built. But the one who hears my words and does not put them into practice is like a man who built a house on the ground without a foundation. The moment the torrent struck that house, it collapsed and its destruction was complete. "
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YOU ARE a GOD!!!
I just started 8th Grade, Am i in the right path?
YES. Learn this now and u won't suffer later. You can even move ahead.
Thank you lec, you actually nailed it.. tomorrow am going to have theoretical test
I don't understand y unwanted TH-camrs are getting 100+ million subs while these type of channels are just 5M......maybe only 6M is educated TH-cam viewers and the rest is dumb ones
Thank you I was so confused on how you got sin and cos but then you explained it! I can finally figure out how to get sin and cos!
4 (d) is wrong. T should equal to fk + Fg. Remember part of weight turns into a force down the slope which is Fg. That combined with the friction is in equilibrium with the Tension.
For the first example ("The Box"): the gravitational force and the normal force are *not* equal. W = -Fn
22:10 YES but HOOOW do you konw that is theta?? it could be the other one? i cant find a single video explaining how we know which of the two angles are theta
I would think that the point representing the object has to be in contact with the surface.
In the last part (e) where is the Fg force?
Thank You Sir The way you teach is just Awesome .May you live long
At 3:33 i have a question:
" Traveling with a constant velocity means you're going at the same speed in the same direction continuously. ... A constant acceleration is quite different. If you travel with a constant acceleration, your velocity is always changing, but it's changing by a consistent amount each second."
Constant velocity--(a=0)
this some bull shit wtf
Ratio
Thank you so much. Genuinely, I'm grateful you have this channel.
Rodriguez William Hall Timothy Robinson Matthew
Understanding 11th standard concepts in 9th standard thanks to your simple yet in depth explanations😊
Narayana??
Thank you sir, your videos are real and valuable to help so many people!
in Q1)b) why only 2 forces (gravity and normal)? why no downward force in the ceiling from the pulling force of the rope? and wouldn't there be a reacting force (in upward direction) for that too?
Love this video, but do not understand the very last part. Why is in the Fx direction is: T=fk; instead of 0=T-fk-WSin(theta)
Rodriguez Helen Rodriguez Richard Jackson Linda
So intro problems part (d), so does T = acceleration? Why do we want to quantify T will that give us our constant acceleration?
Brown Frank Jones Nancy Gonzalez Kimberly
Istg i will give u a shoutout on my thank you speech when i win the nobel prize in physics 30 years from now 😅
17:53 i dont understand the last question or how u get ty or tx. and i have no idea where the fuck Uk came from. Someone help?
Uk is the friction constant.
Anderson Patricia Hernandez Anthony Taylor Robert
Williams Angela Martin Steven Garcia Elizabeth
Martinez Jeffrey Clark Mary Smith Edward
In Q3 part D why don't we write Fg force???
Davis Christopher Martin Paul White Eric
Lopez Jeffrey Johnson Scott Thomas Amy
Tq sir
12:06
I can tell you know your shit but please slow down
you are single handedly saving my engineering career rn
How do you know theta is equal to the theta he added in the triangle with gravity as its hypotenuse?
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Thank you so much for doing this video!! It’s really helpful🥹
Wilson Jessica Williams George Perez Mary
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i love u so much
Is there an error on free body diagram (e)? Shouldn’t the net force should carry a negative sign on the equation because of the downward acceleration?
F_y = T - W
-ma = T - W
T = W - ma
T = m(g-a)
this is what i thought
Whar does "MS" mean in this context?
this is quite something.......you will get your reward in heaven
Martinez Melissa Walker Barbara Lee Michael
At minute 21:04 why is Fg = mg sin(@) shouldn't it be Fg =mg cos (@) can someone provide some clarification on that? - Thank you!
nvm he explained it right after lol
i feel like im the only person who didnt take chemistry or physics in high school. not that it would matter at this point since that was now 8 years ago. but taking this in college is an absolute nightmare to me
How’s it going?
Best explanations, very detailed, professors and tutors usually skip these details that make some of us confused but you did great!!!! Thank you
When a force is applied so the body moves at constant speed....how is the friction force equal to applied force cuz if it's equal...how is it moving?
It was already moving. So when the friction force is equal to the applied force the velocity will stay the same.
constant speed/velocity means the acceleration is zero, so it isn’t moving
@@kelsey545 it is moving, it is just not accelerating.
@@kelsey545 its first law newton,
wouldnt T=mkmgSin(x), and not T=mkmgCos(x)