... ( Let angle THETA = T, and k an element of the set of integers Z, and consider no restrictions of the possible solutions interval (- inf., +inf.) ).The general solution for the trigonometric equation SIN(T) = C ... 1) for (C > 0): SIN(T) = C T = ARCSIN(C) + k * 360 deg. ( QUADRANT I ) or T = 180 - ARCSIN(C) + k * 360 deg. ( QUADRANT II ) ... 2) for (C = 0): SIN(T) = 0 T = 0 + k * 180 deg. ... 3) for (C < 0): SIN(T) = C T = ARCSIN(C) + k * 360 deg. ( QUADRANT IV ) or T = - 180 - ARCSIN(C) + k * 360 deg. ( QUADRANT III ) ---> Example SIN(T) = 1/2 (C > 0): SIN(T) = 1/2 T = ARCSIN(1/2) + k * 360 deg. ( QUADRANT I ) or T = 180 - ARCSIN(1/2) + k * 360 deg. ( QUADRANT II ) T = 30 deg. + k * 360 deg. ( QUADRANT I ) or T = 150 deg. + k * 360 deg. ( QUADRANT II ) ... ( SUPPLEMENTARY SOLUTION PAIRS ) ... Great presentation c.q. graphics ... Thank you and Happy Easter, Jan-W
@@mathonify 1. Find the coordinate of the point which divides (8,10) and (10,6) internally and externally in the ratio 5:3 2. Find the area of a pentagon whose co-ordinates of the vertices are A (-5,-2) B (-2, 5) C (2,7) D (5,1) and E (2,4).. please sir, I would be super excited if u can solve this for me. I will submit those assignments on Wednesday this coming week unfailingly. Thank u Sir!
Thanks, this was very helpful
Trigonometric circles, ratios, equations, and the trigonometric series.
... ( Let angle THETA = T, and k an element of the set of integers Z, and consider no restrictions of the possible solutions interval (- inf., +inf.) ).The general solution for the trigonometric equation SIN(T) = C ... 1) for (C > 0): SIN(T) = C T = ARCSIN(C) + k * 360 deg. ( QUADRANT I ) or T = 180 - ARCSIN(C) + k * 360 deg. ( QUADRANT II ) ... 2) for (C = 0): SIN(T) = 0 T = 0 + k * 180 deg. ... 3) for (C < 0): SIN(T) = C T = ARCSIN(C) + k * 360 deg. ( QUADRANT IV ) or T = - 180 - ARCSIN(C) + k * 360 deg. ( QUADRANT III ) ---> Example SIN(T) = 1/2 (C > 0): SIN(T) = 1/2 T = ARCSIN(1/2) + k * 360 deg. ( QUADRANT I ) or T = 180 - ARCSIN(1/2) + k * 360 deg. ( QUADRANT II ) T = 30 deg. + k * 360 deg. ( QUADRANT I ) or T = 150 deg. + k * 360 deg. ( QUADRANT II ) ... ( SUPPLEMENTARY SOLUTION PAIRS ) ... Great presentation c.q. graphics ... Thank you and Happy Easter, Jan-W
Hi can you please do a video about the mock set 4 autumn 2018 paper 1 foundation tier today or tomorrow
The most basic starting knowledge of the every areas of the advanced mathematical applications.
Can you please do it I really need it
Can u be glad to solve question for me please? I need to submit it soon
of course! you can post any questions here
@@mathonify 1. Find the coordinate of the point which divides (8,10) and (10,6) internally and externally in the ratio 5:3
2. Find the area of a pentagon whose co-ordinates of the vertices are A (-5,-2) B (-2, 5) C (2,7) D (5,1) and E (2,4).. please sir, I would be super excited if u can solve this for me. I will submit those assignments on Wednesday this coming week unfailingly. Thank u Sir!
11th standard basic mathematics
Some quick mathematics