Evaluation of Double Integral using Polar Coordinates| L46|TYBSc | Double Integration
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- เผยแพร่เมื่อ 25 ธ.ค. 2024
- Evaluation of Double Integration using Polar Coordinates | L46 | TYBSc | Double Integration @ranjankhatu
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Amazing lecture 🎉
sir, u made this topic very easy for me.thanks a lot for this wonderful explianation.
I think solving more examples will help my doubts because i think i understood you but i feel like you should solve more examples to clear my doubts😊
thank you for clearing my doubt
Thank you sooo much sir ❤
Sir you explained well ❤
Useful❤
Thank you sir 🙏
Good teaching and beautiful handwriting 🙏
Thank you
thanks brooooo hi from turkey muğla sıtkı koçman university
super sir
Sir if the limit ranges for -1 to 1 the what will be the area
VERY HELPFUL
Thank you
Why did you get a negative result for area?
Here region lies between x= -1 and x=0. So it lies in left hand side of y axis.
@@ranjankhatu can we get area negative ?
@@ranjankhatusir aapne limits bottom to top and left to right nahi likhi isliye answer negative aaya h
Thank you!
at 6:01 it was integral of r not r^2
Yes I was too confused
Shi kya h ??
Thank you sir 🙇🏻♂️🙏🏻
Most welcome
Sir how to find limit of a parabola in double integral
Why we converted
When we have a circle, it is always better to solve the integration using polar coordinates. To make the solution more simple we converted it in to polar coordinates.
@@ranjankhatu thank you so much ❤️
sir, how to know how to integrate r^2 from pi/2 to 3pi/2 or from 0 to 1?
Limits of theta will be in terms of pi and limits of r will be like 0 to 1 or in terms of theta.
Sir can we take limit from -π÷2 to π÷2 ????
No. We will get right half of a circle for above said limits ( which you are saying). But we want left half of circle. So we should take limits which are said in the video.
Hindi nhi ati hai kya sir
Sir hindi me boliye plzzz😖
.