I am impressed by the number of disciplines you cover, and the quality of your coverage. You not only know the solutions, and present them in a clear and understandable manner, but you also teach why the solutions are what they are. You have a pleasant voice on top of it.
I have not studied math at the university, and I would say, it is material from my high school. I have had a difficult period in life, and thought, that I have to find something, which would give me some stability in its repetition. I have tried music, books, and everything, but remembered, that many years ago, matrices has been my beloved part of math in high school. After downloading the College Algebra, 11 Edition, I started the 8th chapter, and could not understand 70% of it. As a person, who, despite the formal methods at the university has not had any math for more than 10 years, I would say, it is a perfect explanation for beginners. I could follow EVERY lesson. This is amazing. I do understand, that the formulas and equations are elementary, but it somehow brings me joy to solve them. Thank you very much for the perfect and logical work done! Wish you good luck with this channel. However, with 5,41 Million subscribers you do have one!=) I will follow this and the next playlists as well.
I spent a full hour trying to solve one of these and was on the verge of losing my mind because my professor wanted me to get my diagonal ones by multiplying the rows by the inverse (fractions make everything so much harder). I was about to skip both problems because I was having no luck, but then stumbled upon your video and got both of them right! Thank you so much!
I just loved it. Man you are such a saviour. I have been stressing out for the last two weeks and I didn't know how to do this. I was just about to lose my mind. Thanks for your video. My God bless you.
gosh i was going all the way to reduced row echelon form... but i'm glad to see i'm not the only one who takes 20 minutes (usually more) to solve these things
MR. Organic Chemistry Tutor, thank you for massive concentration of Gaussian Elimination with Four Variables Using Row Operations. This material is fairly simple, however the probability of making an error is high.
Thank you so incredibly much for your well timed video. Trying to solve a university assignment, and your video has taught me this so much better than my university lecturers!
18 minutes is unacceptable for the real world; however, the instruction is beneficial to know where the computer had made a mistake. Awesome 😀😀😀 Thanks!
Thanks for the video. Could you please help when we encounter any zero already present on the row before any operation for the next new..as we could not write R4--> -11R3+17R4 if R3 has already zero at 3*3 then its not possible. to get the new element 13:00
i remain confused. whats the point of matricies? why not just do all those operations directly on the equations?? for example if we have 2x +3y = 11 x -y = -2 why put them into matrices? why not just apply the changes directly like this: R2 = R2 -(1/2)*R1 2x +3y = 11 x -y = -2 + -(1/2)(2x +3y = 11) 2x +3y = 11 x -y = -2 + (-x -(3/2)y = -(11/2)) 2x +3y = 11 -(5/2)y = -(15/2) which has same effect as [ 2 3 | 11 ] [ 0 -(5/2) | -(15/2) ] then R2 = R2/(-(5/2)) or R2 = -(2*R2)/5 2x +3y = 11 y = 3 which has same effect as [ 2 3 | 11 ] [ 0 1 | 3 ] then R1 = R1/2 x +(3/2)y = (11/2) y = 3 which has same effect as [ 1 (3/2) | (11/2) ] [ 0 1 | 3 ] and boom. same exact result except i saved time by not translating the equations into matricies and back. i just applied the changes directly on the equations. y = 3 so x +(3/2)(3) = (11/2) x +(9/2) = (11/2) x = (2/2) x = 1 x, y --> 1, 3 why do we need matricies for this???
Teacher, I used this method, but I made a difference in summing the R. However, the result for the variables is correct. Does my answer count as correct?
i tried to make up an example for my self just to practice as usual, but I couldnt get the answer it was almost like its impossible to get the matrix to be in the row echelon form, so i wonder are the impossible to do questions using this technique? or i just suck?
I hate that I need to kind of see the operation in my mind, so that I can make those zeroes, it's difficult and time consuming, but thats probably my brain's fault :/
I'm doing this method, and I seem to not be doing any miscalculations but still somehow get the incorrect answer, I believe they are linear equations so im not sure whats going on? Third year maths degree student.
@@joelp7665 I wasn't being taught it, it was just a technique I needed for a bigger problem I was working on in my dissertation. I learnt it for A-Level Maths, just hadn't seen it in a while. I sorted it though and got it working just fine :)
i think you would still start with getting your leading ones and reducing the numbers under them to 0. the column that doesn't have a leading one will be assigned a parameter like 's' or 't' and the value in that column acts as the coefficient of the parameter
please do a video on G-J elimination when you have 3 equations with 4 variables and have to "solve" using a t. We had a question about a 3x4 matrix with only 3 equations and 4 variables. Apparently you try and make the first 3x3 coefficients into an inverse matrix, but are left with the last column. The solutions as x = 5 - x y = 4-x, z = 2-x but overall there is no solution. HELP PLEASE!!!!! | 1 0 0 x | 5 | 0 1 0 x | 4 | 0 0 1 x | 2
wayy too late but like if you have a system of infinite solutions then you only need 1 parameter...that's the point of the parametric curve, to generalize in terms of 1 variable
is it this solvable? 3x+3y-1z=1 3x-4y-3z=1 3x+1y+1z=-3 3x+1y-2z=4 I tried to answer this in all from of LU, Gaussian and aeigen but its giving me different answer..
Matrices - Free Formula Sheet: bit.ly/3UE9Cmk
Matrices - Video Lessons: www.video-tutor.net/matrix.html
I am impressed by the number of disciplines you cover, and the quality of your coverage. You not only know the solutions, and present them in a clear and understandable manner, but you also teach why the solutions are what they are. You have a pleasant voice on top of it.
I have not studied math at the university, and I would say, it is material from my high school. I have had a difficult period in life, and thought, that I have to find something, which would give me some stability in its repetition. I have tried music, books, and everything, but remembered, that many years ago, matrices has been my beloved part of math in high school.
After downloading the College Algebra, 11 Edition, I started the 8th chapter, and could not understand 70% of it. As a person, who, despite the formal methods at the university has not had any math for more than 10 years, I would say, it is a perfect explanation for beginners. I could follow EVERY lesson. This is amazing. I do understand, that the formulas and equations are elementary, but it somehow brings me joy to solve them.
Thank you very much for the perfect and logical work done! Wish you good luck with this channel. However, with 5,41 Million subscribers you do have one!=)
I will follow this and the next playlists as well.
I spent a full hour trying to solve one of these and was on the verge of losing my mind because my professor wanted me to get my diagonal ones by multiplying the rows by the inverse (fractions make everything so much harder). I was about to skip both problems because I was having no luck, but then stumbled upon your video and got both of them right! Thank you so much!
Fractions, you hate working with fractions?
@@thomasmutiso1181
You can't read?
,😂😂
The organic chemistry tutor helps me so much that I dont skip ads on his channel. Atleast im contributing something
Yes, It is a very good structured and explanatory project.
thank you sir. Without your video, my brain would be leaking out of my left eardrum trying to figure it out. Much appreciated.
God bless y’all! We need to turn to Jesus as Lord and Savior and leave sin behind. Preach the Gospel! John 3:16
Ray Reyes 😂😂😂
Weird analogy but ok
😭😭😭
😆😆😆😆
I just loved it. Man you are such a saviour. I have been stressing out for the last two weeks and I didn't know how to do this. I was just about to lose my mind. Thanks for your video. My God bless you.
gosh i was going all the way to reduced row echelon form... but i'm glad to see i'm not the only one who takes 20 minutes (usually more) to solve these things
You are a genius, thanks for help. Much better than the educators at UNI.
MR. Organic Chemistry Tutor, thank you for massive concentration of Gaussian Elimination with Four Variables Using Row Operations. This material is fairly simple, however the probability of making an error is high.
You hve saved from my upcoming test due on monday
M now ready
God bless you
you saved me i got 93 out of 100 you are the best god bless you
Thank you so incredibly much for your well timed video. Trying to solve a university assignment, and your video has taught me this so much better than my university lecturers!
Thanks for all your videos. They're always clear and easy to understand. Thank you so much 😊
Nigerian?? 👀
18 minutes is unacceptable for the real world; however, the instruction is beneficial to know where
the computer had made a mistake. Awesome 😀😀😀 Thanks!
Thank you so much Julio! Your explanations are absolutely amazing!
This makes sense to me in the sense that the matrix operations are like adding the equations and eliminating variables...
You're awesome at this. Thank you for posting!
mimi munondi gonera zvenyu mudara...Hamuite hamuite.Thumb's up
This was an awesome explanation! You made this very easy to understand.
How does it feel to be one of the greatest public educators ever?
he explains so much better than my professor💯
Eventhough it is complicated, but now i have gotten good hint and idea;and it is too much helpful and i appriciate how the teacher had presented it.
Thank you so much you are a blessing 🥰
Thank you very much I just love the way u explain this video and all of your videos
I'm here again. Thanks for sharing it with us
im sooo thankful u saved my life such a great explanation thank you so much
thank you so much, i was struggling with matrices but now, i can solve
Sir really really thank u really awesome explaning hats off
Thank you for your videos.
Thanks a lot sir ! Just so you know you have fans outside your country too.
You're a god helping us!!
😭😭😭😭 Thank you so much!!!!
GREATLY explained
Awesomely explained, thanks a lot.
this is a masterpiece
thank you so much for easy and helpful solution
Easy to understand
You so awesome 💕
Thank you so much, I understand this now! 😊
tkank you very much
205k views and only 2k likes, come on peeps at least leave a like to this absolute lad
Are you going to focus on changing the numbers into zeros below or are you going to focus on changing the diagonal numbers into ones (1s) ?
Thank you so much for posting. This video really helped me.
Thank you sir
11:07 make zeros frm bottom to top , starting frm 1st column . 16:46. .
Good videos and such a nice explanations
Very useful thnks for sharing brother.....❤
Thanks for the video. Could you please help when we encounter any zero already present on the row before any operation for the next new..as we could not write R4--> -11R3+17R4
if R3 has already zero at 3*3 then its not possible. to get the new element 13:00
hey i know its been long and you probably won't read this but if you did please upload more vidios like on eigenvalues and eigenvectors
thank you so much!that was very helpful
Simply the best
i remain confused. whats the point of matricies? why not just do all those operations directly on the equations??
for example if we have
2x +3y = 11
x -y = -2
why put them into matrices? why not just apply the changes directly like this:
R2 = R2 -(1/2)*R1
2x +3y = 11
x -y = -2 + -(1/2)(2x +3y = 11)
2x +3y = 11
x -y = -2 + (-x -(3/2)y = -(11/2))
2x +3y = 11
-(5/2)y = -(15/2)
which has same effect as
[ 2 3 | 11 ]
[ 0 -(5/2) | -(15/2) ]
then
R2 = R2/(-(5/2))
or
R2 = -(2*R2)/5
2x +3y = 11
y = 3
which has same effect as
[ 2 3 | 11 ]
[ 0 1 | 3 ]
then
R1 = R1/2
x +(3/2)y = (11/2)
y = 3
which has same effect as
[ 1 (3/2) | (11/2) ]
[ 0 1 | 3 ]
and boom. same exact result except i saved time by not translating the equations into matricies and back. i just applied the changes directly on the equations.
y = 3
so
x +(3/2)(3) = (11/2)
x +(9/2) = (11/2)
x = (2/2)
x = 1
x, y --> 1, 3
why do we need matricies for this???
Respect sir ❤
Thank you so much
Bravo!!
Sir g Jis book sy apny ya question liya h us book k name kiya h ?
Thanks a lot sir ❤️
This was really helpful thanks for sharing .
But I have a question,must the row operations be addition ?,can something like R2-R3 be applied ?
Amazing!
Thank you so much!
4 years later and this video is still intense lol
why and how do we decide to convert those numbers (1:42) into zeroes?
can i use this method when solving partial fractions
Thanks a lot
Your voice is so ASMR :)
Thank you sooo much!! This helped me.. Thanks for posting!
God bless y’all! We need to turn to Jesus as Lord and Savior and leave sin behind. Preach the Gospel! John 3:16
What do you do when one of the numbers that your supposed to get to a 1 to accomplish Row echelon form becomes a zero please help.
it mean "no solution" and if it all zero in a row, it mean it is "infinite solutions"
Please does this also apply to 11x11 matrix....I would love to have any suggestions
yes
Youre a god bro
Teacher, I used this method, but I made a difference in summing the R. However, the result for the variables is correct.
Does my answer count as correct?
thank you 8 )
Holly crap I actually got it right?!?!
i tried to make up an example for my self just to practice as usual, but I couldnt get the answer it was almost like its impossible to get the matrix to be in the row echelon form, so i wonder are the impossible to do questions using this technique? or i just suck?
God bless y’all! We need to turn to Jesus as Lord and Savior and leave sin behind. Preach the Gospel! John 3:16
Amazing
Can the operation be done using the second row minus the first row?
Because i observed you were starting from R2+R4. Why sir?
Thank you
What if there are 4 unknowns but only 3 equations given? What will the resulting reduced row echelon form represent then?
Thanks
Perfect
I hate that I need to kind of see the operation in my mind, so that I can make those zeroes, it's difficult and time consuming, but thats probably my brain's fault :/
is it correct if i multiply r3 by 11/17-r4
quick question can Gaussian elimination be 5x5 matrices?
Yep! It's the same process, though you might take 40 minutes to solve lol
Nice
mans gonna carry me through college lmao
Tq sir
what if in the first row on the left ,the first number is zero(0) instead of 1
God bless y’all! We need to turn to Jesus as Lord and Savior and leave sin behind. Preach the Gospel! John 3:16
Korbes I think you stumbled onto the wrong video. It’s Gauss-Jordan, not Gospel-Jesus.
Can you start including time stamps when you cover a large amount of topics in a vid?
I'm doing this method, and I seem to not be doing any miscalculations but still somehow get the incorrect answer, I believe they are linear equations so im not sure whats going on? Third year maths degree student.
You guys learn that in 3rd year math? Lucky!
1st year chem degree, and 2nd semester we already do this in France(sad emoji).
@@joelp7665 I wasn't being taught it, it was just a technique I needed for a bigger problem I was working on in my dissertation. I learnt it for A-Level Maths, just hadn't seen it in a while. I sorted it though and got it working just fine :)
@@robbiebeenham5980 I assume A-level math is high school?
@@joelp7665 here, it goes: school; college and then university. I learnt this in college, so I am not sure of the equivalent.
@@joelp7665 we have learn it in highschool .11th standard 🙀
lucky you
I like that
sooo how can we solve such systems if they’re only 3 equations but have 4 unknowns? which numbers do I convert to zeros?
there’s*
i think you would still start with getting your leading ones and reducing the numbers under them to 0. the column that doesn't have a leading one will be assigned a parameter like 's' or 't' and the value in that column acts as the coefficient of the parameter
please do a video on G-J elimination when you have 3 equations with 4 variables and have to "solve" using a t. We had a question about a 3x4 matrix with only 3 equations and 4 variables. Apparently you try and make the first 3x3 coefficients into an inverse matrix, but are left with the last column. The solutions as x = 5 - x y = 4-x, z = 2-x but overall there is no solution. HELP PLEASE!!!!!
| 1 0 0 x | 5
| 0 1 0 x | 4
| 0 0 1 x | 2
How to do with 9 equations and 9 unknown
You videos are great but man you have to increase your volume,
helppp??? i got a different answer but it still works???? (0,2,3,5) ?
Can a system of linear equations with 4 equations and 4 variables can have 4 parameters in its general solution?
wayy too late but like if you have a system of infinite solutions then you only need 1 parameter...that's the point of the parametric curve, to generalize in terms of 1 variable
is it this solvable?
3x+3y-1z=1
3x-4y-3z=1
3x+1y+1z=-3
3x+1y-2z=4
I tried to answer this in all from of LU, Gaussian and aeigen but its giving me different answer..
3+++±+3---------1≈====1
3----------4---------3=====1
=========///////////////////A1
(9++++++9-------3======3)
(-9+++++12+++9=====-3)
=======
0X++++++21y++++6C====0== ไม้จิง
====
3-------------4---------3====1
3++++++1++++1====-1
=====================A2
(9------------12---------9======3
(-9‐------------3---------3======1)
=====
0X-----------15y-------12C====4
3++++++1++++1===-3
3++++++1-------2=====4
=====================A3
(9++++3++++++3===---9
(-9---------3++++++6==-12
=====
0X++++0y+++++9C=====-----21
=====
3++++++3--------1=====1
3++++++1---------2==÷==4====A4
====
(9+++++9----------3========3
(-9----------3+++++6=======--12
===
0X+++6y-+++++3C=====-----9==A4
=÷==
+21y+++++6C==0
--15y---------12====4
=====
+++6------------6,C======4
++0+++++++9=====---21
===
6++++++++++3====------17
+6++++++++++3====------9
==
12Y++++++++6C===----26
6y+++++++++3"c====---13
6y==----13--3
6y==------16
3y==------8
Y===----8/3=====(ไม้จิง)
===========
3---------3(8/3-----1====1
3-----------8-------‐--1==1
26/3-------8--------1==1
××××××××××××××××××××
3X++++4(8/3)-----3=≈==1
3+++++32/3--------3====1
26++32/3-------------3=
58/3-------------3=========1
×××××××××××××××
3-------8/3+++1=÷====--3
3(26/9)---8/3+1=====---3
26----8/3++1=
18/3++1
=6++++1======7____(--3)××
3------8/3------2====4
3(26/9)----8/3----2=====4
26---8/3--2=
18/3-------2==4
==6---------2==========4
9X===12+14
9X===26
X=26/9
pls speak louder in your videos thank u
If i start with r1+r2 the total solution will be different and will not get the same result whyy
Hmm