balancing a redox reaction / oxidation number method

Dr. McCord works through the oxidation number method of balancing a redox reaction. The reaction here is the permanganate/iron(II) reaction in acid.

[@ladyanne1378]

I FINALLY UNDERSTOOD THIS, NEVER THOUGHT IT WAS THIS EASY, THANK YOU SO MUCH❤️

[@синиякрыса]

simple and straightforward . i thought id NEVER understand this . thanks a lot sir u really helped

[@stacksborrow1510]

Dr McCord you just balanced my grade! Thank you sir!

[@Mauvebts444]

Thank you so much for teaching! U help me understand how the method work by the simple way.

[@iceberrymusicltd.408]

best chem guy on yt

[@mgk012xyz]

*HE TALKS A LOT ABOUT SCIENCE STUFF PROFESSOR DAVE EXPLAINS*

[@yesyes-vt9eg]

that was clear and extremely helpful with the steps. thank u

[@sivu727]

TQ so muchhhh...I wasted 30 minutes before watching this vedio..in search of this concept

[@vsvlohith.07]

Video*🤓

[@atcomputer1976]

thank you!! I finally understand and I'm so relieved I want to cry

[@maryokunwaye9437]

Thanks for this diluted easy video

[@kneause]

what a fucking king, I love you Dr. McCord

[@Julux_28]

Wow, thank you so much!! I understand it so well now :)

[@randomgames7931]

Thank you, sir. You helped me before my exam

[@Jaqueveonthesecond]

thank you so much saved me for finals

[@tatyanafrancis5293]

Thankyou soooooo much. I watched many videos but not this simple thankyou once again❤

[@yashchoubey6763]

Thank you sir, really helped a lot

[@MsAngelHarshini]

thank u so much... understood the concept easily

[@christiansinamano4827]

thank you bro. you just saved my average

[@dreampeak9364]

Thankyou sir you made it so simple brilliant.

[@varnijakannan8124]

thank you sooo much for the best explanation ever!!

[@wanipakowalska776]

I never got this from class..
Thanks u Ve really done a great favour..
🙏

[@camillecondron4342]

How do you figure out how many electrons are canceled out?

[@WalterWhite-nx5ti]

This was soo helpful!

[@commanderlightgaming8315]

Thank you very very much made it very simple 🙏🏻🙌🏻✨✨💫

[@gouthamraj7449]

Thank you so much for this video 💯👍🏻😀

[@محمدبنوالي-ظ2ح]

Was pretty helpful

[@cricket2928]

Nice explained

[@moonlitsky9321]

This is so awesome! I even understood when I have nothing to do with Chemistry! I got interested and was thinking, what if one of the half reaction’s change of charge is 0? I figured the 8step method does not work in that case. Then we cannot put coefficients to balance it out. Is there an easy step by step way for such a case?

[@anonymousone3024]

If charge change would be 0,will it remain as a a redox half reaction?

[@uvinduranga2896]

too cool
keep up the good work

[@generald5036]

Brilliant Video

[@Mahesh_2800]

thank you sir

[@alankuo2727]

the best method!!

[@bookandart371]

understood perfectly !

[@vanitasz]

Thank you🙏🏿🙏🏿

[@kureishimitsuyo5379]

how is the MnO4 is +7 like how we knew that please answer

[@Unq]

I gotchu, since the MnO4 has a negatice sign “-“ it means that the total charge is -1.
Oxygen is -2 charge so -2x4 = -8
Since we know that the charge of the entire atom is -1 Mn has to be +7 because +7 + -8 = -1

[@Meh_Moody]

@@Unq what if I take 2O2 on the right hand side instead of H2O?

[@utsavroychowdhury133]

@@Meh_Moody You don't. Just follow the method, use H2O

[@hottpotato6865]

Nice. Thanks a lottt

[@chibuikeigwe5589]

Well understood now

[@abel_kidus]

This method looks very similar to the ion electron method

[@esatacikgoz2016]

thanks

[@danielbrantley6158]

Thank you!!

[@bimsararanasinghe6454]

Thank you soo much sir ❤

[@bmzaron713]

Since hydrogen is more electronegative than manganese, how is it that hydrogen seemingly displaces managanese in forming water/ hooking up with oxygen.?. I could be way way off in what's actually taking place. Same thing with iron. It is more electronegative than manganese, so why would it be oxidized and manganese reduced? This is a pretty freaky reaction to me. Does it have to do with the reaction occuring in an acidic solution?

[@flamingninjas7856]

GOOD VIDEO

[@theyouproject]

where did u get the oxidation number of Mn

[@Mohamed___Adhil___]

The oxidation no. for one oxygen is -2 ..for 4 oxygen is -8 and a negative ion above the oxygen should be added so that -8+1=-7 .....therefore mn 7+

[@theyouproject]

@@Mohamed___Adhil___ oww get it, tnx

[@Mohamed___Adhil___]

@@theyouproject welcome

[@RabiuRamadan-r3q]

Wow 🔥🔥🤩

[@xanzuss5916]

thank you bro

[@gileet4924]

Thank you sir❤

[@flou_rish]

Thankyou so much!!!!

[@anonymousagent398]

Thanks a lot

[@mohammadnaeemahmed3521]

Thankssss brooooooooooo

[@swagcookie_xo6243]

How do you know which oxidation to use?

[@indranilsingh2682]

If you mean the oxidation number then you'll have to find the oxidation number of each molecule. First you'll have to learn how to find out oxidation number then you can balance chemical equations using his method .

[@leenaalabdulhadi715]

Thank u soooo much !!

[@orangecaprinun]

SOMEBODY HELP!
@ 0:55 If there isn't the same number of atoms of species that are not O or H like in:
N2O4 + Br^- > NO2^- + BrO3^-
What do i do???
i tried just multiplying NO2^- times 2 without changing anything else including the difference in oxidation numbers (+4 - +3 = -1), and the other difference of Br being -1 - +5 = -6, i ended up having to multiply the reduction half reaction by 6, so 6N2O4 and 6(2NO2^-) = 12NO^-, but eventually the charges on the two sides did not match taking into account the protons and all

[@Mohamed___Adhil___]

Bro/sis ....it can be easily done by the ion electron method....try it

[@Meh_Moody]

What if I take 2O2 on right hand side instead of 4H2O

[@aarushigullia7670]

Thankss❤

[@nombuleloncube-sr2hh]

How do l know that manganese oxide is going to be decomposed to manganese 2+

[@Mohamed___Adhil___]

It's the charge already given...in question....if not then the oxidation number of manganese metal is zero[0]

[@MeghanaBaggam-j9u]

Tq sir ......😊

[@cubingandgaming6158]

Humble is that you..?

[@lawrence_enzo3665]

Thank you chemistry jesus🙏🙏

[@leaquarm6768]

Thank you I love u

[@yomiyualemayehu1398]

The Same To You

[@flaxschoolacc1193]

2:29

[@jezabelespila8419]

Omgg cool

[@mohammedomarxxd1059]

j

[@AdekunleMubashir]

.pls I have a question how did mno4 is +7 Pls explain

[@adityakumarchoubey3875]

Thanks