I think you just pick a function that satisfies the point you're looking for the limit at. So in this case it would be any equation where (0,0) is a solution. Then you check multiple functions hoping that your answers are different so you can write that the limit doesn't exist. It sounds like if the functions you choose keep having the same answer, there's another method to determine whether the limit exists using polar coordinates that I'm not familiar with. Hopefully that video will come out soon!
it became plain and simple till after i heard idea of applying the directions. thank you sir
You are an excellent teacher. Thank you for your clear and passionate presentation.
You're the best sir
He’s the goat
Why can't we use l'hopitals rule?
L'hõpital's rule is only defined when we're working with only one variable (and some other conditions).
fan from ethiopia, i am electrical and comp engineering student you've been helpfull very much . i hope you'll make more videos in calculus III
in the 3rd problem, let's have y = x and see what happens.
he has already considered that case
Yeah that's what i did and I got 1/x^2 which is 0 at the end so the limit is 0 I guess
I love this guy's charisma
You always makes it easy
for a generalised answer keep y =mx^3 and u can see that limit doesnt depend on x or y
when limx=limy=n, why wouldn't it make sense to make x=y, since they both approach the same value in the limit?
We are talking about if it will approach the limit. We are checking that not the other way around
8:18 will help you understand
Question: when it comes to limits like those in the third question, how do I know which substitution to make, and how long to keep testing?
I think you just pick a function that satisfies the point you're looking for the limit at. So in this case it would be any equation where (0,0) is a solution. Then you check multiple functions hoping that your answers are different so you can write that the limit doesn't exist. It sounds like if the functions you choose keep having the same answer, there's another method to determine whether the limit exists using polar coordinates that I'm not familiar with. Hopefully that video will come out soon!
best in the job never stop learning
where can i find the 2nd video?? the polar coordinates one
Or you could just use l'Hôpital 6:15 and be done in 7 steps
L'Hospital's Rule only works on single variable functions.
@@wwbbcg01The variables are the same number
i think you should give us a example like the third example but limit exists there
Hi, do you have a link to the puzzle thing you mentioned at 3:27? Best Wishes Peter
Sir you put 0^6=1 But it return zero in Chat gpt
u r second to none.
When we factor out y^2 in the denominator aren't we supposed to get y^3 instead of y^4?
I have to admit, I just love your channel
why did you not take this path method in question 2?
Thanks for the Videos sir!
Only if I could get a sure physics plug like this too😫
great video
Thanks
THANKS
Wish I had seen this about 60 years ago!
Lol 😆
How to use L' hopital's rule here ?
You don't
Great tutorial