Fanning a Sudoku Spark into a Flame!

แชร์
ฝัง
  • เผยแพร่เมื่อ 12 ก.ย. 2024
  • BremSter solves "Diamond In The Rough" by fjam. An Sudoku using the Sum Lines and Ratio Pairs constraints.
    Solve in Sven's SudokuPad WebApp: sudokupad.app/...
    📋 Puzzle Rules:
    • Normal Sudoku rules apply.
    • Along each blue line, digits in each region must sum to the same total. If a line has multiple disconnected segments within a region, these segments are summed separately.
    • Cells separated by a black dot must contain digits with a ratio of 1:2. Not all dots are given.
    ----------------------------------------
    Check out the BremSter Games TH-cam Channel
    / @bremstergames
    Come join my Patreon, either as a Free Member, or you may support if you wish to.
    / bremster
    You can see a catalogue of Free Sudoku Puzzle Packs at the following links:
    / 110878
    tinyurl.com/Fr...
    You can Join as a channel member on TH-cam to get early access to videos.
    / @bremsterpuzzles
    Check out other content on the channel by visiting the Playlists Page:
    ▶️ bremster.tiny....
    Please come join us in the Puzzle Plaza Discord Community:
    / discord
    You can get Merch with the BremSter Puzzle logo on it from the Spring store.
    teespring.com/...
    teespring.com/...
    If you would like to submit a puzzle for me to cover, you can find my submission guidelines on the following post or described in detail in the following video.
    / 66467875
    • BremSter's Puzzle Subm...
    Find the details of all the puzzles posted on my channel on the following tracking sheet: tinyurl.com/Br...
    If you would like to reach out to me you can.
    I am BremSter on the CtC discord, or you can email bremster@elindal.net
    #sudoku #sudokusolver

ความคิดเห็น • 19

  • @fjam
    @fjam 6 หลายเดือนก่อน +2

    Really nicely done Bremster! There are a few ways to tackle the diamond, which I like as it means that solvers should be able to find some way to get started. Recognising the sum has to be even and then eliminating options is a good choice, as is the trick with divisibility by 5. Neither is right or wrong, what matters to me is that solvers explore and come to understand the pattern one way or another. I wanted the rest of the puzzle to be pretty smooth afterwards, just asking simple questions. I was pleased to be able to find a layout that is completely symmetric apart from box 5, but I also wanted that symmetry to be broken early so I avoided making a puzzle where every cell was a pair for ages (not really my style).
    I enjoyed the singing too, which I hope was the sign of somebody feeling relaxed and enjoying themselves!

  • @ChrisVenus
    @ChrisVenus 6 หลายเดือนก่อน +6

    The way I worked out the central cross is by a kind of set like approach. The cells on the line are R5-R5C5+C5 - R5C5 = R5+C5 - 2*R5C5 = 90 - 2*R5C5. But we know this is 5 lots of whatever the segments add up to. The only way this works is if R5C5 is divisible by 5 and so must be 5. Leaving the segments to then be 16.

    • @blargo
      @blargo 6 หลายเดือนก่อน +1

      This is the way.

  • @anaayoung9142
    @anaayoung9142 6 หลายเดือนก่อน +2

    Your break-in was great, helped me a lot! 😀

  • @StGordo61
    @StGordo61 6 หลายเดือนก่อน +1

    Loved this puzzle and the solve.

  • @eddieharwood7788
    @eddieharwood7788 6 หลายเดือนก่อน

    That was a remarkable setting. I had no real problem with the initial break-in but then baulked at what to do next. Once I realised that 1 was already then taken in box 4, it was clear that the 178 had to go in box 6, and suddenly the whole thing flowed out without any problems.

  • @iuriikononenko9238
    @iuriikononenko9238 6 หลายเดือนก่อน +5

    the nice way to do math on central box, is to see that row sum euqals to yellow+2* yellow+2* yellow=5*yellow, thus 45-central digit should be divisible by 5.

    • @danielszanto2955
      @danielszanto2955 6 หลายเดือนก่อน

      Exactly, the central line has 5 segments, so the total is 5*x. With the central cell double counted they cover the whole of row5 and col5 which add to 90.

  • @JohnRandomness105
    @JohnRandomness105 6 หลายเดือนก่อน +1

    6:50 I finished the puzzle in about two hours. I went off to pen and paper to calculate what the sum had to be of the principle three-cell segments and the four-cell diamond. The central cell had to be a multiple of five, leading to my first digit.

  • @jimi02468
    @jimi02468 6 หลายเดือนก่อน +2

    Region sum lines are like weird killer cages. One of my favorite sudoku variants.

  • @gdc42
    @gdc42 6 หลายเดือนก่อน +1

    Very nice puzzle. I feel like the breakin might be a bit hard for beginners because it uses geometry but after that I'd encourage new solvers to give this a go. Very instructive and fun deductions throughout the whole puzzle.

  • @user-kt9vr1wj6y
    @user-kt9vr1wj6y 6 หลายเดือนก่อน +1

    31:40 for me
    nice puzzle and solving

  • @annkiitgoel5648
    @annkiitgoel5648 6 หลายเดือนก่อน +1

    With ur help in start.. was able to do in 18 mins..

  • @kana2112
    @kana2112 6 หลายเดือนก่อน +1

    That was a nice puzzle. I wish I would have tried it when my brain was functioning better.

  • @mbakenemdusink9757
    @mbakenemdusink9757 6 หลายเดือนก่อน +1

    Loved this puzzle so much!

  • @adenwellsmith6908
    @adenwellsmith6908 6 หลายเดือนก่อน +1

    Tough break in. I also liked the end and the way it collapsed.

  • @Edos512
    @Edos512 6 หลายเดือนก่อน

    in my case...
    My break in was a bit more brutal
    The Column 5+ row 5 = 90
    x= value of the region sum in each region
    c=central cell value
    a,b,d,e = values of the central rhombus
    a+b+d+e=x
    2x+a+d+c+2x+b+d+c=90 = 4x + a+b+d+e +2c = 5x+2c
    x=(90-2c)/5
    where c is between 1 and 9
    The only value where x is integer is c=5 and x=16
    then the fan blades sum to 32, there are only 2 combinations of 6 numbers that sum to 32 without using the 5, those 2 combinations grouping them in 2 blocks of sum 16 are
    178 349 which leaves a 26 in the middle
    268 349 which leaves a 17 in the middle
    The black kropki removes the 17 from the horizontal center part leaving a 26 in R5C4 and R5C6 and leave a 34 in both R6C4 and R4C6
    And we can't put 178 on the left blade because that would force a 234 in R4C123 and that would conflict with the 34 in R4C6
    And then 178 on the right blade forces 8 to be in R4C4 forcing 9 in R789C4 and that removes 349 from the bottom blade
    From there almost everything is smooth sail

  • @donaldsnyder1543
    @donaldsnyder1543 6 หลายเดือนก่อน +2

    Too tough for me.
    Interesting puzzle tho.
    Settled for a watch.

  • @oldmomj5088
    @oldmomj5088 6 หลายเดือนก่อน +1

    very nice.