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Solved in 22:04. I didn't need to colour, just looked at the little killer clues. The 9 and 18 give digits right away, and the 7 and 49 are forced.

30:27 here, very nice puzzle with interesting rule set. Thanks BremSter.

A really great set of puzzles, and while some were a bit tricky, they all flowed nicely for me! My times: 4:21 - 3:09 - 4:55 - 3:38 - 6:01, total of 22:04 (conflict checker off), and successfully another 10 hats, whoo! Always enjoy these.

Loved watching you solve this (after your oft mentioned dislike of maths), a great puzzle for a Sunday. Put a hankie on my head, call me Mr Gumbie…”my brain hurts”…but happy! Thanks BremSter

01:07:52 It is moments like these where I just want to thank myself for grinding through a puzzle like this ... well done !!!

You were right there when you figured out that if R5C3 was the anticell then R5C4 had to be a 1. This would mean there would be no anticell in the 9 cage, but also no 1 or 4 and therefore no way to make a 9 cage.

It found the logic not too difficult for the 9 cage in box 1 The reasoning is : if there is no anti celle in R3C3 then the cage cannot be 234 (easy) and must contain a 1 which is therefore in R2C2 This forces 13 in R5C3 which then cannot be an anti-cell which force R3C3 to be an anti cell So if there is no anti celle there must be an anti cell ! The easy part which is easy to miss is that 13 in R5C3 means it is not an anti-cell

Aug 14 - 6:24 Aug 15 - 4:38 Aug 16 - 3:07 Aug 17 - 4:34 Aug 18 - 4:43 Total - 23:26

Hi BremSter, I got stuck for a very long time at the same stage as you (at around 44 minutes in your video). I was finally able to make progress by: Considering the 28 pair in the anti-cell in r2c9. If it would have been a 2, it would have forced the 2 in row 5 in box 6, and then in r4c1 in box 4. Having a 2 in r4c1 would have left no potential anti-cell where to place the 2. The 8 in r2c9 then allowed to solve the cages in box 3 and make easy progress from there. I guess it's one of those cases where the way out appears simple AFTER you've found it. 😀

My initial thought was just "Nope." Then I watched the first few minutes, and saw something that clicked. It took me over an hour, but I really enjoyed it! Now watching how to do it better! Thanks BremSter and Erin Toler! Great fun!

Kept on making mistakes so settled for watching Bremster. Cool puzzle despite that.

Solved in 32 min😊 13 cage in R3 is key in solving x-wing of anti-cells 5-8 pair is not possible in that 13 cage

27 minutes here, thanks BremSter

Erin, love anti value combined with the anti anti knight constraint. Since the tricky bit is resolving the X wing on anti cells, simple giving one of the 4 as the anti or not the anti might reduce the friction. To go along with that, if you coud remove the 4 but add enough not anti clues, that could be really cool. Erin, please make more puzzles with this constraint.

Once you fill in the candidates for the "9" cage, there is a 5,6 pair in column 3. This eliminated all candidates for the anti-cell from r5c3, making r5cc1 the anti-cell. No need for the "1"" bifurcation.

I was stuck in the same position. Well done, BremSter.

9:11 Why can't he put a 9 in the anti-cell of the 0 cage? It isn't a knight's move from any established 9's.

9:57 for me, very cool !!

at 28:56 why can't r2c9 be 6? 72 minutes for me. nice puzzle and solving

Lots of calculations, a spreadsheet is a good help for these kind of puzzles, done in 27:19. @44:00 the easier way is to ask if r3c1 is an anti-cell, it has to be an 8 in this case (the anti cell in box4 will be an 5), Then look what happens to box3: the 13 cage becomes 4-9, the 7 cage 2-5, and the anti cell has no fill (r2c9). That "solve guide" was no good imo.

26.03 for me

What a thumbnail 😂 Very intuitive puzzle, got in 8:13.

You seems to be a very funny guy! 😅 I am pretty sure that, eitheir I tried this one before or watched someone solve it, because I knew what's going on 😂

23:26 - Loved it! Thanks for sharing.

Epic puzzle.

this time I opted for only coloring the high digits, and then towards the end the 12 pairs

37:30 with some video help. Might have been faster had I colored 1/2 sooner. Bremster definitely gave me some ideas on this one. Nice puzzle by Steve. Good solve by Bremster.

That was a nice & easy but not too easy one. Done in 9:12. I also ended up coloring the 12s.

Done in 12 mins

Nice and easy puzzle. Solved it in 10:49.

9:57 for me nice puzzle

Coloring was definitely the way to go here. I didn't color the high-low, which led me to not seeing how the center box was restricted for too long. I did end up coloring 12s to resolve that stubborn last diagonal, though.

17:06 The amunt of colouring I did to reach that conclusion was, ahm, embarrasing? (I might have started in box 7)

I got lucky and looked at the 49 diagonal first, and when I just had all the information needed to solve it.

13:24 to solve. Wonderful puzzle!

9:15, some tricky bits but a nice flow overall.

Ze germans are inventing a drinking game right now. :)

What a great puzzle. I liked the way it always seemed to show a way ahead whenever it seemed to look unlikely.

that was hard

I'm so glad you featured this one, BremSter! I thoroughly enjoyed watching you solve it. Glad you liked it :)

That melted my brain just watching BremSter. And he solved it with ill brain fog... Well done to him, and well done to Math Pesto.

Aug 09 - 4:48 Aug 10 - 5:39 Aug 11 - 6:42 Aug 12 - 3:28 Aug 13 - 8:53 Total - 29:30

Beautiful puzzle and an excellent solve! Solved it in 60:29. In hindsight this was not so terribly difficult, just took a while to find the right deductions.