☑️20 - Maximum Power Transfer Theorem: Solve using Thevenin's Equivalent Circuits
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- เผยแพร่เมื่อ 31 ก.ค. 2024
- In this lesson, we shall learn how to determine the maximum power delivered to a load by a source.
Maximum power transfer theorem states that: the maximum power delivered to a load by a source is obtained when the load resistance RL is equal to the Thevenin's resistance Rth.
For maximum power to be delivered to the load:
RL = Rth.
1. Remove the load resistance and find vth
2. Deactivate independent sources and find rth
3. For maximum power to be transferred, RL = RTH, Pmax = (Vth)^2/4Rth
00:00 - Maximum Power Transfer Theorem
03:44 - Example 1
Playlists on various Course
1. Applied Electricity
• APPLIED ELECTRICITY
2. Linear Algebra / Math 151
• LINEAR ALGEBRA
3. Basic Mechanics
• BASIC MECHANICS / STATICS
4. Calculus with Analysis / Calculus 1 / Math 152
• CALCULUS WITH ANALYSIS...
5. Differential Equations / Math 251
• DIFFERENTIAL EQUATIONS
6. Electric Circuit Theory / Circuit Design
• ELECTRIC CIRCUIT THEOR...
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What if R_TH and R_L are superconductive components?
We're proud of you Sir 👏. We need more videos from you
Aww thanks so much, and noted please
can we do source transformation for 6A and the parallel resistor and switch it to a voltage source with a series resistor?
Of courses
thank you very much!
You are most welcome
Where do you watch me from
How do not take into account the sign of the 10V source when you calculating the KVL loop?
It was considered
All your videos
Sir in this video in both cases or loops the values of Vth is compulsory that the same in both cases ??
Yes, it is compulsory to game same value of vth regardless of the path you consider
Could I ask; what do you use to write your work? Any external board?
Yes please, vison graphics tablet
Sir please let me know the value of Vth is same in both cases or not???
Yes, in both cases the value of vth is same
Please sir here am seeing it is from 20 where are the others????? Please!
I just want to follow from the first❤❤❤
Will be uploaded
We can see what you write
Can or can't?