What is the yellow area??

This problem had lots of different solutions. Can you find just 1 of them? If you worked it out in a different way to me make sure to share it in the comments below! What did you think of my solution? Let me know below!
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[@ibechane]

very nice using the scaling factor! To be honest, I got stumped and ended up figuring it out analytically lol

[@zdrastvutye]

answer: calculate the coordinates of the intersection and use either the gauss formula or input known surfaces, see line 120:
10 print "mrtalbotmath-what is the yellow area?":dim x(6,2),y(6,2)
20 l1=8:l2=6:l3=4:@zoom%=@zoom%*1.4:rem den schnittpunkt berechnen ***
30 xg11=0:yg11=0:xg12=l1+l2:yg12=l2:xg21=l1:yg21=0:xg22=l1+l2-l3:yg22=l2+l3
40 a11=yg12-yg11:a12=xg11-xg12:a131=xg11*(yg12-yg11):a132=yg11*(xg11-xg12)
50 a21=yg22-yg21:a22=xg21-xg22:a231=xg21*(yg22-yg21):a232=yg21*(xg21-xg22)
60 a13=a131+a132:a23=a231+a232:ngl1=a12*a21:ngl2=a22*a11
70 ngl=ngl1-ngl2:if ngl=0 then print "keine loesung":end
80 zx1=a23*a12:zx2=a13*a22:zx=zx1-zx2
90 zy1=a13*a21:zy2=a23*a11:zy=zy1-zy2
100 xl=zx/ngl:yl=zy/ngl:print "x=";xl;"y=";yl
110 xi=xl:yi=yl:a1=yi*(xi-l1)/2:atr=(yi+l2)/2*(l1+l2-xi)
120 a6=l3^2/2:atr2=(l2+l3)/2*(l2+l3):ages=atr2-a1-atr-a6
130 print "die gesuchte flaeche=";ages
140 x(0,0)=0:y(0,0)=0:x(0,1)=l1:y(0,1)=0:x(0,2)=xi:y(0,2)=yi
150 x(1,0)=l1:y(1,0)=0:x(1,1)=xi:y(1,1)=0:x(1,2)=xi:y(1,2)=yi
160 x(2,0)=xi:y(2,0)=0:x(2,1)=l1+l2:y(2,1)=0:x(2,2)=xi:y(2,2)=yi
170 x(3,0)=xi:y(3,0)=yi:x(3,1)=l1+l2:y(3,1)=0:x(3,2)=l1+l2:y(3,2)=l2
180 x(4,0)=xi:y(4,0)=yi:x(4,1)=l1+l2:y(4,1)=yi:x(4,2)=l1+l2:y(4,2)=l2
190 x(5,0)=xi:y(5,0)=yi:x(5,1)=l1+l2:y(5,1)=l2:x(5,2)=l1+l2-l3:y(5,2)=l2+l3
200 x(6,0)=x(5,2):y(6,0)=y(5,2):x(6,1)=x(3,1):y(6,1)=l2:x(6,2)=x(3,1):y(6,2)=y(5,2)
210 masx=1200/x(2,1):masy=850/y(5,2):if masx
run in bbc basic sdl and hit ctrl tab to copy from the results window