Sir, your short tricks are very excited and I'm planning for ssc cgl , so pls upload as much as possible pls..... Since I have very limited time I need to be vry fast in practice
X^148+1/x^148=3 Square both sides X^296+1/x^296+2=3^2__(1) Again take the square of (x^148-1/x^148)^2= x^296+1/x^296-2=3^2-2-2 Take square root on both sides X^148-1/x^148=under root(3^2-2-2)
Sandhyarani Ponnada x^157+1/x^157=5 this is our first equation and square on both sides (x^157+1/x^157)^2=(5)^2 ..(a+b)^2=a^2+b^2+2ab (x^157)^2+(1/x^157)^2+2=25 (x^157)^2+(1/x^157)^2=23 then.... x^157-1/x^157=??? this is our second equation and square it (x^157-1/x^157)^2 (a-b)^2=a^2+b^2-2ab and calculate this =(x^157)^2+(1/x^157)^2-2 from first equation value =23-2 =21 (x^157-1/x^157)^2=21 x^157-1/x^157=square root of 21 in this first question we subtract 2 and second equation subtract 2 then finally we subtract total 4 in the square root
boya rambabu x^157+1/x^157=5 this is our first equation and square on both sides (x^157+1/x^157)^2=(5)^2 ..(a+b)^2=a^2+b^2+2ab (x^157)^2+(1/x^157)^2+2=25 (x^157)^2+(1/x^157)^2=23 then.... x^157-1/x^157=??? this is our second equation and square it (x^157-1/x^157)^2 (a-b)^2=a^2+b^2-2ab and calculate this =(x^157)^2+(1/x^157)^2-2 from first equation value =23-2 =21 (x^157-1/x^157)^2=21 x^157-1/x^157=square root of 21 in this first question we subtract 2 and second equation subtract 2 then finally we subtract total 4 in the square root
Thanks so much Sir,Maths ante bhayam unna vallu me vedios chuste Chalu ,no fear about Maths
Thanks sir for clear explanation
Superoooo suparu.....nuvvu maaku maths nerpe maths devudivi annaa
Sir ,i am very happy i am waiting for chanal which is like yours ,thanks for you backup
Superb trick....sir....
Nice and thank u anna
Nice and very good
Nice, excellent teaching
Sir, your short tricks are very excited and I'm planning for ssc cgl , so pls upload as much as possible pls..... Since I have very limited time I need to be vry fast in practice
Excelent u r maths tric sir
I am new subscribe poor in maths so ur upload very interesting and I follew regular thanks u for redusing question mark
4 eala vachindi
Thank you so much sir
Very nice
It's like a shortcut formule sqroot(n^2+(or)-4
Should we subtract 4 from that is it will change for any question or it is constant
Yes
Annaa oka doubt l.....=1 isthe elaaa cheyaaloo cheppannna
how to find last digit of the problem sir..?? and is this method is applicable to all models
In problem if both get - then what no. We should take....
Time saving shortcut but.it needs proof.
Okavela 2 sides same sign unte ela cheyyali sir???
Trick bagundi sir
Super
Daily ga videos cheyamdi sir please.
Sir you r super
Rey saami....4 endhukocchindhi endhukocchindhi antarenti... Shortcuts cheptunte... Just follow avvandi... Endhukochindho chepthe gani solve cheyara enti ... Excellent shortcut method bro ...keep going on...!!
A wheel travels a distance of 22km in 2500 revolutions what is the diameter of the wheel ? please sir explain this problem
Thank you for giving this trip anna
Trick anna trip kadu
@@luckymahi8681 sorry sister
Supr sir tnk u so mch
Why should take only 4 pls tell me
X^148+1/x^148=3
Square both sides
X^296+1/x^296+2=3^2__(1)
Again take the square of (x^148-1/x^148)^2=
x^296+1/x^296-2=3^2-2-2
Take square root on both sides
X^148-1/x^148=under root(3^2-2-2)
Thank u bro
four yendhuku thesukunnaru plz koddiga cheppe tappudu clarity maintain cheandi sir plzzz inka baga artham avthundhi tq sir
How can take four only
Y not taken other any values sir..
Super sir
Super
4 Ela vesthunnaru
Sir both + vaste - Ahhhh , + Ahhhh Pls reply sir
-
super sir
How we put 4... please discribe
Bt answer routes lo ivakunda values lo isthe ela
Tq
How to do if different numbers are given
this is very simple method and how to take numeric 4?
Same doubt naku koda
Sir super undi but 4 yenduku thesukovaliiii???????
Comments reply లో చూడండి ans కోరుకుతుంది
Nice sir and good
Nice
Sir 4aka vashndi pls reply me
Nice sir
Different powers unte ala cheyali? Sir
X power place lo different values iste yem cheyali.......
Four eduku tiesukunaru ikokka number tiesuvachuga 4eduku +or - tisuko valla - vunachota +tisukovala
Wow
Why should we add Nd minus 4
Pina problem lo 5 icharu dani tarvata number minus chesaru.13 sqare chesetapudu 12 minus cheyali kada
Sir no reply malli oka video chesi 4 anduku clarity evagalara plz
Arthemetic kooada videos pettandi
Kk thanq u
Rute low 4 yeandhuku theshukonaru sir
Why did you substract 4 in the root..?
Hlo sir మీరు 4 ఎందుకు ఎంచుకున్నారు
అరే నాలుగు ఎలా వచ్చింది అక్కడ
thank u ..
sir
Ur xlnt sir
Sir root lo 4 Ela vaustundhi sir
Y should we take 4??
Tx Sir
super Sir but miru 4 a anduku thisukuntunaru chepandi
Rondu chotla same symbol vostey apudu em rayali before 4 + or -
3. 3
X +1/x =110find x+1/x=?
Sir algebra 3 rd pettandi sir please....
Root lo 4 ey enduku use cheyali Sir other numbers enduku use cheyakudadhu
4 yenduku tisukunharu sir
sir 4 ela tisukunaru
Sir root lo 4 Ela vachindhi
nice sir but 4 endhuku tisukovali cheppandi sir
shortcut for
x+1/x=2, then x-1/x=?
0
+and- ni batti 2or 4 tesukovala sir
Leka Pedda power undi kabatti 4 tesukunnara
4 ela thisukovali chepandi
Anna akada 4 Ela vastadhii
17 power 200 divided with 18 Pls solve this problem
1 answer
Powers different ga Este how
Explain how it possible
First some lo 4 ala vastunde anna
4 Ela vesthunnaru
Thank you sir but how is it possible for 4 only
Sandhyarani Ponnada
x^157+1/x^157=5
this is our first equation
and square on both sides
(x^157+1/x^157)^2=(5)^2
..(a+b)^2=a^2+b^2+2ab
(x^157)^2+(1/x^157)^2+2=25
(x^157)^2+(1/x^157)^2=23
then....
x^157-1/x^157=???
this is our second equation
and square it
(x^157-1/x^157)^2
(a-b)^2=a^2+b^2-2ab
and calculate this
=(x^157)^2+(1/x^157)^2-2
from first equation value
=23-2
=21
(x^157-1/x^157)^2=21
x^157-1/x^157=square root of 21
in this first question
we subtract 2
and second equation subtract 2
then finally we subtract total 4 in the square root
3 square - 4 avuthundi sir Mari alaganea ikkada Mari 5 square - 6 avuthundi kadha sir how is it possible tell me...............,,.......
.
4ela vasthundhi anna
boya rambabu
x^157+1/x^157=5
this is our first equation
and square on both sides
(x^157+1/x^157)^2=(5)^2
..(a+b)^2=a^2+b^2+2ab
(x^157)^2+(1/x^157)^2+2=25
(x^157)^2+(1/x^157)^2=23
then....
x^157-1/x^157=???
this is our second equation
and square it
(x^157-1/x^157)^2
(a-b)^2=a^2+b^2-2ab
and calculate this
=(x^157)^2+(1/x^157)^2-2
from first equation value
=23-2
=21
(x^157-1/x^157)^2=21
x^157-1/x^157=square root of 21
in this first question
we subtract 2
and second equation subtract 2
then finally we subtract total 4 in the square root
@@ANIL-yw5rt c
Super explanation brooo👍
Why did you take 4 here brother??
Y did y take 4 always could plz... explain again
If z=5+2√6, then z^2+1/z^2=????
thanks sir
question lo x power same lekapothe sir
X+y=3,xy=2 then x3-y3=? 3 is cube
(a+b)^2-(a-b)^2=4ab
by this formula we solve x-y=1
(a-b)^3=a^3-b^3-3ab(a-b)
By this formula we can solve x^3-y^3=7
4 yendhuku thisukovali
Bhayyaa nvu 4 akada nunchi tisukostunav bhyaa chepu bhayya konchem
Tell me how to take 4
Root 3²-4 a yenduku theesukunnaru
Four ela vachindhi? Explain clatirty to next videos
simplega under root b square minus 4ac ani cheppochuga
ante discriminant value anochuga
Both + or - iste elaaaa please
Sir .no4 ala వచ్చింది
Sir same numbers iste k but different numbers vaste etla
4 ela vastadi sir
Why we take 4