This is what I want to write exatly. b(b² - 3) = 0 -> A product is zero if at least one of its factors is zero. So b = 0 or ( and does not apply here ) b² - 3 = 0 -> b² = 3 - > b = ±√3
@@chriscanis1554 no exactly. Logic is: let's assume two situations. First b=0 , second b≠0 In first situation b=0 is root In second situation we can divide by b, because we calculate in field where b cannot be zero. It is just separation.
@@chriscanis1554 Just seperate the two cases. Case 1: b can be 0 and case two b must not be zero. I wasn't going to write a book about this simple problem. So I shortend the answer. Key fact is: His way is far to complicated. You have to be able to solve a problem in a finite amount of time.
b=0 is an obvious solution. Thus we may assume that b is not zero. Divide b-cubed equals 3b by b to obtain b-squared equals 3 and hence b equals plus or minus square root of 3 or b equals zero as complete solution.
Thanks for the great effort and time to solve the problem, Evidently the demonstration of each root was not for people that understand the procedures, it was developed for less skilled learners or for those in lower levels of maths. Greetings.
1:17 a=√(a²) is wrong. Let take a=-1 √(a²)= √((-1) ²)=√1=±1 So a=±1, a=-1 or a=1, but we took a=-1, so -1≠1, so a≠√(a²) a=(√a) ² is correct and since you went with this equation, you got the right answer, but a=√(a²) is wrong
No entiendo ¿ Qué problema tienen en los comentarios con el cero? El término independiente, sin parte literal, es igual a cero, por lo que es una raíz evidente. Precioso video.
Как только в математику ввели буквы, математика превратилась в философию. Оставьте прости цифры без букв, и станет легко и понятно. А буквы используйте для поэзии
b(b^2-3)=0… Then solutions are 0,+sqrt(3), -sqrt(3). Not a rocket science. I had my 5th grader niece and solved in less than 2 minutes. Is it just you want to make lengthy youtube videos?
b+b+b=b*b*b ->
3b = b³ ->
b³ - 3b = 0 ->
b(b² - 3) = 0 ->
b = [0, ±√3] .. and we are done
Correct .
This is what I want to write exatly. b(b² - 3) = 0 -> A product is zero if at least one of its factors is zero. So b = 0 or ( and does not apply here ) b² - 3 = 0 -> b² = 3 - > b = ±√3
LOL, it can be resolved in 15 seconds
Why so complicated? 0 is an obvious solution. 3b=b*b*b Just divide by b -> 3=b*b (obviously two results) Done in less than a minute!
@@chriscanis1554 no exactly. Logic is: let's assume two situations. First b=0 , second b≠0
In first situation b=0 is root
In second situation we can divide by b, because we calculate in field where b cannot be zero. It is just separation.
you are very smart
@@chriscanis1554 Just seperate the two cases. Case 1: b can be 0 and case two b must not be zero. I wasn't going to write a book about this simple problem. So I shortend the answer. Key fact is: His way is far to complicated. You have to be able to solve a problem in a finite amount of time.
Мало найти ответ эмпирически. Надо составить корректную, формальную запись решения. С обоснованием всех корней.
@@АлексейБигвава достаточно подобрать и пояснить, что больше нет.
3b = b³
b = 0 (trivial solution)
3 = b²
b = ±√3 (two solution)
Less than 1 minute to solve.
@@andredcavalcante Молодец!
Him: b+b+b = bxbxb
b = ?
Me: 0🍷🗿
Excelente ejercicio y explicación, sensacional. Gracias 👌👌
b=0 is an obvious solution. Thus we may assume that b is not zero. Divide b-cubed equals 3b by b to obtain b-squared equals 3 and hence b equals plus or minus square root of 3 or b equals zero as complete solution.
Thanks for the great effort and time to solve the problem, Evidently the demonstration of each root was not for people that understand the procedures, it was developed for less skilled learners or for those in lower levels of maths. Greetings.
3b = b^3
0 = b^3 - 3b
0 = b (b^2 - 3)
b = 0 v b^2 - 3 = 0 /√
|b| = √3
b = 3 / b = -3
R: b = -3, 0, 3
Pero chico!! Lo hice mentalmente en dos pasos, 3b = b b b , 3 = b b b / b, 3 = b b , b = √3
1:17
a=√(a²) is wrong.
Let take a=-1
√(a²)= √((-1) ²)=√1=±1
So a=±1, a=-1 or a=1, but we took a=-1, so -1≠1, so
a≠√(a²)
a=(√a) ² is correct and since you went with this equation, you got the right answer, but a=√(a²) is wrong
(b+b+b ) ÷b = b.b
b/b+b/b+b/b = b^2
1+1+1 = b^2
Therefore b= +- √3
Of course I agree 👍
b1=0; b2=√3; b3=-√3.
Thank you.
Why does he take such a long way.
3b = b.b.b
Divide by b
3 = b.b
Square root
b = √3
It took me 3 seconds instead of 10 mimutes
yes, your logic is on point.
3×b=b^3;
b^3-3×b=0;
b(b^2-3)=0;
b(b+sqr(3))(b-sqr(3))=0;
b1=0, b2=-sqr(3), b3=sqr(3).
0, +- sqrt(3). Total of three answers for power three equations.
I solved it mentally without using pen&paper.The answer is+- 3 under root.
and 0!
What a long way of going it. The 3 simple roots are obvious from inspection right at the start
Это корректная формальная и обоснованная запись анализа. С обоснованием корней. Алгебра это ведь анализ. Не так ли?
b+b+b=b×b×b
3b=b³
b³-3b=0
b×(b²-3)=0
b²-3=0 or b=0
b=±sqrt(3) or b=0
Greetings , you have chosen the long vay , to solve the problem , Good lock wehad fun.
I usually watch this to get to sleep 😅
Thx 4 mental exces,keepit up 4 learners
You are solving in round about manner. b+b+b=b.b.b / 3b=bcube / 3=bsquare / b = sq.rt of 3
This Solution is not only
mathematitions ,for biginars n laymans too😊😊😊😊
b+b+b=b.b.b
3b=b^2.b
3=b^2.b/b
3=b^2
b=√3 or b=-√3
This is very easy.
b+b+b=b.b.b=>
3b=b^3=> 3=b^2=>b=-√3 ou b=√3 condition b=0
Ну устно же:
3b=b³
b=0
b=±√(3)
b1=0; b2=sqrt(3); b3=-sqrt(3).
No entiendo ¿ Qué problema tienen en los comentarios con el cero? El término independiente, sin parte literal, es igual a cero, por lo que es una raíz evidente. Precioso video.
Never mind the maths, what is that blue pen and where do you get them from…?!😂
The music is very disturbing. The math is good.
b = 0 v b = ± root(3)
b=Sqrt3=1,732
The best method to make stidents hate math.
Too complex and too long.
b^3-3b=0
b(b^2-3)=0
b=0 and b=(3)^0.5 and -(3)^0.5
sqrt(3)
Решил за 30 секунд,прям спидран
0😊
Решается в уме, при чем тут олимпиада? 😮
Вот занунуда. Молдец. Я b=0 не учел. )
Как только в математику ввели буквы, математика превратилась в философию. Оставьте прости цифры без букв, и станет легко и понятно. А буквы используйте для поэзии
Математика - это и есть настоящая поэзия.
√3 y -√3
b=0 ou b=racine de 3 ou b= -racine de 3
3b=b^3 , 3=B ^2, B=+-raiz de 3 kkkk
B+B+B = BBB = Grêmio 😅
Это очень просто решить,в уме 9а секунды. Ответ 0
b(b^2-3)=0… Then solutions are 0,+sqrt(3), -sqrt(3). Not a rocket science. I had my 5th grader niece and solved in less than 2 minutes. Is it just you want to make lengthy youtube videos?
0+0+0=0.0.0 -b -0
😂😂😂😂😂😂
8' for a stupid equation 😂
b=正負根號3或0
Cevap √3
You can only solve it if you let b = x
Sqrt3
1
1 ou 0
+-√3
Cansei....
b is o and 3^1/2
b=+or-√3.
B = 0
3b=b,^3,,,,>b=✓3
Вроде как устное решение)))
@@Alexander_M61 pruwetctwuyou was ,washe mnenie absolyutnoe ppawilnoe
b = 0, tambem satifaz a igualdade, ou não?
Premissa: b, diferente de zero, né??
Ответ b=0.
Root3?
Why do you have to rewrite the problem all over again? Go straight to solving the problem.
😂
Te ahoga en un vaso de agua
Il obtient même des likes. 🤦
So much stupidity to solve an easy solution of a problem
Yeah, he's definitely drawing it out to get past a certain playtime
b=2
Useless only the 0 can have the same result with + and ×
b= 0, b= ✓3, b= -✓3.
0,√3
0+0+0=0*0*0
В+В+В=В*3
В*3=В*В*В
В*В=В²
В=√3
b = 0
B=0