Thermodynamics: Steady Flow Energy Balance (1st Law) Diffuser
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- เผยแพร่เมื่อ 15 มี.ค. 2019
- Solution to the following problem (Thermodynamics: An Engineering Approach, CBK, 8th Edition 5-28)
The diffuser in a jet engine is designed to decrease the kinetic energy of the air entering the engine compressor without any work or heat interactions. Calculate the velocity at the exit of a diffuser when air at 100 kPa and 30 C enters it with a velocity of 350 m/s and the exit state is 200 kPa and 90 C.
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Nice job, thank you.
Adicionalmente, ¿Como puedo obtener el flujo volumétrico de entrada y de salida de ese problema?
Hi, this was super helpful but why at 7:30 do you remove the mass flow rate out? It doesn't seem to be cancelled by anything.
I'm dividing both sides by the mass flow rate. So I have 0/m on the left hand side which is equal to zero.
@@railitaylor wow thank you for both responses! Lifesaver! I have a thermodynamics quiz tomorrow :)
How to get cp value... could you please send the table
Also, how come it is T1 - T2? Why not T2 - T1?
When I moved (T2-T1) to the left hand side I got: -Cp(T2-T1) = (v2^2 - v1^2)/2. I multiplied through the negative sign to get Cp(T1-T2) on the left hand side.
I got 248 m/s for the answer.