Thermodynamics: Steady Flow Energy Balance (1st Law) Diffuser

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  • เผยแพร่เมื่อ 15 มี.ค. 2019
  • Solution to the following problem (Thermodynamics: An Engineering Approach, CBK, 8th Edition 5-28)
    The diffuser in a jet engine is designed to decrease the kinetic energy of the air entering the engine compressor without any work or heat interactions. Calculate the velocity at the exit of a diffuser when air at 100 kPa and 30 C enters it with a velocity of 350 m/s and the exit state is 200 kPa and 90 C.

ความคิดเห็น • 10

  • @diyaazaghloul756
    @diyaazaghloul756 3 ปีที่แล้ว +1

    The greatest teacher over the network

  • @timaustin4986
    @timaustin4986 5 ปีที่แล้ว +1

    Nice job, thank you.

  • @eduardorodriguezgomez2763
    @eduardorodriguezgomez2763 4 ปีที่แล้ว

    Adicionalmente, ¿Como puedo obtener el flujo volumétrico de entrada y de salida de ese problema?

  • @zaraakkuly1861
    @zaraakkuly1861 4 ปีที่แล้ว

    Hi, this was super helpful but why at 7:30 do you remove the mass flow rate out? It doesn't seem to be cancelled by anything.

    • @railitaylor
      @railitaylor  4 ปีที่แล้ว +1

      I'm dividing both sides by the mass flow rate. So I have 0/m on the left hand side which is equal to zero.

    • @zaraakkuly1861
      @zaraakkuly1861 4 ปีที่แล้ว +2

      @@railitaylor wow thank you for both responses! Lifesaver! I have a thermodynamics quiz tomorrow :)

  • @prasadanil5862
    @prasadanil5862 3 ปีที่แล้ว

    How to get cp value... could you please send the table

  • @zaraakkuly1861
    @zaraakkuly1861 4 ปีที่แล้ว

    Also, how come it is T1 - T2? Why not T2 - T1?

    • @railitaylor
      @railitaylor  4 ปีที่แล้ว +5

      When I moved (T2-T1) to the left hand side I got: -Cp(T2-T1) = (v2^2 - v1^2)/2. I multiplied through the negative sign to get Cp(T1-T2) on the left hand side.

  • @doitjack8400
    @doitjack8400 ปีที่แล้ว +1

    I got 248 m/s for the answer.