Thanks for taking the time to do this. Some people charge lots of money in Books and Videos for this type of information. You are very much appreciated.
You said on the motor part (13:54) Table 240.248 It’s 430.248 😅 I could find it and you said simple lol😂 I’m on a role watching your video. And I like how you simplify things Your awesome
Oh wow! Great catch, Erica! So sorry for the misdirection. 😳I will make a correction to that immediately. Thank you so much for pointing it out to me. I guess I had too many numbers in my head. 🙄😁
Nice catch! I apologize for that mistake. A 7kW range is unusually small, and I'm so used to using Column C (especially for a single-family calc) that I defaulted to it. You are totally correct, though. Column B should be used here in order to get the minimum load. I'm so grateful for everyone's comments pointing out these kinds of errors. You keep me on my toes! I've made a note on the video at that point, so going forward, folks will be warned. Thanks for bringing it to my attention, as it helps everyone here!
I had a range question come up below could you tell me if I'm right or wrong ? for a single range shouldn't the 12kw x 1.10 be 8kw x1.10? Single / Standard Method The Problem: 14 kW - 12 kW = 2 kW 2 × 5% = 10% Apply the adjustment to the range load in Column C: 12 kW × 1.10 = 13.2 kW
Hey Eric, you are correct. The equation should be: 8kw + 8kw(14kw-12kw).05 = 8.8kw. Whoever wrote the problem made a mistake. By their logic, a 13kw range would have a larger demand than two 12kw ranges.
310.12(B) has specific criteria requirements (120/240-volt systems, 100-400 amps, etc.). However, this criteria will apply to most dwellings out there. If the criteria are met, the 83% would be applied after the calculation from 220 is completed. And keep in mind that 310.12 pertains to conductor sizing, not service sizing.
@@simply.electricalwhen calculating the service size, do you take the total demand load and use the next circuit breaker up from 240? For example if the demand load is 190 would you then use a 200 amp service and apply table 310.12A to get 2/0 cu?
@@Profanity42069 Yes, because your service size must meet or exceed your demand load. And for conductors, you can also just go down to Table 310.12 to make it easier.
Final range calc did not notice Note #6 on table 220.55 that states a single cooktop and two wall ovens can add all KW and treat as ONE range. So....cooktop of 7200 and ovens of 11,000 equal 18,200 total VA, with demand at just 10,800VA (8KVA+2800VA)
I'm assuming you are looking at the 2023 code. Note 6 refers to Branch-Circuit Load. This is NOT for a service or feeder calc. Just be careful of that.
Any extra motor loads would fall under 'Appliances'. Only the largest motor of the building gets the extra 25% added. So if one of your motors is larger than the heat pump, that is the load you would add 25% to - not the heat pump. See 220.53 for appliance criteria.
EXAMPLE #2 With the EV charger at 100% and the range from column B 220.55 my demand load is 49,860VA for a 207.75amp load for service disconnect of 225 OCPD conductors are 3/0 Cu 4 awg GEC
You nailed it. But remember, your EGC would be #4 cu. The GEC would be determined by type. Be sure that you don't get the two confused. For example, if it was a concrete-encased electrode, then yes, #4 cu is correct for the GEC as well. But if it was a ground rod, #6 cu is the minimum. Just for the sake of others who read this and may be wondering how you got your answer: If this Example #2 was calculated according to the 2023 code, NONE of the appliances would be allowed to use the 75% demand factor. In 2023, EV equipment is now exempt from the demand factor. This would bring the total number of appliances down to three. Which therefore disallows them from using the demand factor. All would get calculated at 100%. Nice job.
@@PrinceIvan18 I have a bunch of ideas in my head for future videos, but I don't have any more in the works at the moment. I hope to get back into it soon. I will make a set of calc videos based on the 2023 code since there were some changes made. And I might branch out into other code-related and practical topics. Did you have some specific requests?
Also, check out related videos here:
One-family Optional Crash Course: th-cam.com/video/HlilXI1FCmM/w-d-xo.html
Multifamily Standard Crash Course: th-cam.com/video/0Ryf2QlmO-k/w-d-xo.html
Multifamily Optional Crash Course: th-cam.com/video/zRKbEu2zNWM/w-d-xo.html
Very easy to understand. Thanks!
Thanks for taking the time to do this.
Some people charge lots of money in Books and Videos for this type of information.
You are very much appreciated.
You are very welcome. Glad to hear it's helpful to you. Thanks for the comments!
Thank you sir! Studying for my West Virginia master exam! This is exactly the video I need
You said on the motor part (13:54)
Table 240.248
It’s 430.248
😅 I could find it and you said simple lol😂
I’m on a role watching your video. And I like how you simplify things
Your awesome
Oh wow! Great catch, Erica! So sorry for the misdirection. 😳I will make a correction to that immediately. Thank you so much for pointing it out to me.
I guess I had too many numbers in my head. 🙄😁
Excellent video easy to understand 👍
on 10:53, 7KW range should be 80% = 5600VA as per 220.55 column B?
Nice catch! I apologize for that mistake. A 7kW range is unusually small, and I'm so used to using Column C (especially for a single-family calc) that I defaulted to it. You are totally correct, though. Column B should be used here in order to get the minimum load. I'm so grateful for everyone's comments pointing out these kinds of errors. You keep me on my toes!
I've made a note on the video at that point, so going forward, folks will be warned. Thanks for bringing it to my attention, as it helps everyone here!
I had a range question come up below could you tell me if I'm right or wrong ?
for a single range shouldn't the 12kw x 1.10 be 8kw x1.10?
Single / Standard Method
The Problem:
14 kW - 12 kW = 2 kW
2 × 5% = 10%
Apply the adjustment to the range load in Column C:
12 kW × 1.10 = 13.2 kW
Hey Eric, you are correct. The equation should be: 8kw + 8kw(14kw-12kw).05 = 8.8kw.
Whoever wrote the problem made a mistake. By their logic, a 13kw range would have a larger demand than two 12kw ranges.
When do we take 310.12 (B) 83% into consideration?
310.12(B) has specific criteria requirements (120/240-volt systems, 100-400 amps, etc.). However, this criteria will apply to most dwellings out there. If the criteria are met, the 83% would be applied after the calculation from 220 is completed. And keep in mind that 310.12 pertains to conductor sizing, not service sizing.
@@simply.electricalwhen calculating the service size, do you take the total demand load and use the next circuit breaker up from 240? For example if the demand load is 190 would you then use a 200 amp service and apply table 310.12A to get 2/0 cu?
@@Profanity42069 Yes, because your service size must meet or exceed your demand load. And for conductors, you can also just go down to Table 310.12 to make it easier.
Final range calc did not notice Note #6 on table 220.55 that states a single cooktop and two wall ovens can add all KW and treat as ONE range. So....cooktop of 7200 and ovens of 11,000 equal 18,200 total VA, with demand at just 10,800VA (8KVA+2800VA)
I'm assuming you are looking at the 2023 code. Note 6 refers to Branch-Circuit Load. This is NOT for a service or feeder calc. Just be careful of that.
@@simply.electrical Yes, 2023 code. Thanks for the response!
What about multiple motors in addition to the heat pump? I had one on a test that had two grinder pump motors and a well motor.
Any extra motor loads would fall under 'Appliances'. Only the largest motor of the building gets the extra 25% added. So if one of your motors is larger than the heat pump, that is the load you would add 25% to - not the heat pump. See 220.53 for appliance criteria.
EXAMPLE #2 With the EV charger at 100% and the range from column B 220.55 my demand load is 49,860VA for a 207.75amp load for service disconnect of 225 OCPD conductors are 3/0 Cu 4 awg GEC
You nailed it.
But remember, your EGC would be #4 cu. The GEC would be determined by type. Be sure that you don't get the two confused. For example, if it was a concrete-encased electrode, then yes, #4 cu is correct for the GEC as well. But if it was a ground rod, #6 cu is the minimum.
Just for the sake of others who read this and may be wondering how you got your answer:
If this Example #2 was calculated according to the 2023 code, NONE of the appliances would be allowed to use the 75% demand factor. In 2023, EV equipment is now exempt from the demand factor. This would bring the total number of appliances down to three. Which therefore disallows them from using the demand factor. All would get calculated at 100%.
Nice job.
This is amazing.
Thanks, glad you like it!
@@simply.electrical are you doing anymore videos?
@@PrinceIvan18 I have a bunch of ideas in my head for future videos, but I don't have any more in the works at the moment. I hope to get back into it soon. I will make a set of calc videos based on the 2023 code since there were some changes made. And I might branch out into other code-related and practical topics.
Did you have some specific requests?
in 2023 NEC (220.53) the demand factor shall not apply to EVSE ,THANKS
Yes, good point. EVSE was added to the list of exceptions in 2023.